mysql连接两个table，得到匹配记录的非零值的字段名
mysql join two table, and get field name of the matched record which has nonzero value
我有两个 table 如下所示
mysql> show tables;
+-------------------+
| Tables_in_testdbs |
+-------------------+
| dts |
| ref |
+-------------------+
2 rows in set (0.00 sec)
各table内容如下
mysql> select * from ref;
+----+------+------+
| Id | key1 | key2 |
+----+------+------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 2 | 2 |
| 4 | 3 | 1 |
| 5 | 3 | 2 |
| 6 | 3 | 3 |
+----+------+------+
6 rows in set (0.00 sec)
mysql> select * from dts;
+----+------+------+--------+------+------+------+------+------+
| Id | key1 | key2 | serial | pr1 | pr2 | pr3 | pr4 | pr5 |
+----+------+------+--------+------+------+------+------+------+
| 1 | 1 | 1 | 1 | 0 | 0 | 1 | 0 | 2 |
| 2 | 1 | 1 | 2 | 0 | 0 | 0 | 0 | 0 |
| 3 | 1 | 1 | 3 | 0 | 0 | 0 | 1 | 0 |
| 4 | 1 | 1 | 4 | 1 | 0 | 1 | 1 | 3 |
| 5 | 1 | 2 | 5 | 0 | 0 | 0 | 2 | 5 |
| 6 | 1 | 2 | 6 | 0 | 0 | 0 | 0 | 1 |
| 7 | 1 | 2 | 7 | 0 | 1 | 0 | 0 | 0 |
| 8 | 2 | 2 | 1 | 1 | 1 | 1 | 1 | 2 |
| 9 | 2 | 2 | 2 | 0 | 0 | 0 | 0 | 0 |
| 10 | 3 | 2 | 3 | 0 | 0 | 0 | 0 | 0 |
| 11 | 3 | 3 | 1 | 1 | 1 | 0 | 0 | 1 |
| 12 | 3 | 3 | 5 | 0 | 0 | 1 | 1 | 0 |
+----+------+------+--------+------+------+------+------+------+
12 rows in set (0.00 sec)
这是我尝试加入的两个table
mysql> select distinct
-> i.key1,
-> i.key2
-> from
-> ref i,
-> dts d
-> where
-> i.key1=d.key1 and
-> i.key2=d.key2 ;
+------+------+
| key1 | key2 |
+------+------+
| 1 | 1 |
| 1 | 2 |
| 2 | 2 |
| 3 | 2 |
| 3 | 3 |
+------+------+
5 rows in set (0.00 sec)
期待低于o/p，真不知道怎么弄
key1 key2 fields_non_zero
1 1 pr1,pr3,pr4,pr5
1 2 pr2,pr4,pr5
2 2 pr1,pr2,pr3,pr4,pr5
3 2
3 3 pr1,pr2,pr3,pr4,pr5
我想使用以下条件进行检查，例如，让 table 匹配
的 key1=1 和 key2=1
- Join two table
- check is there any non zero data in fields(pr1-pr5) of dts, which is matched
- If found concat field name with comma,
- suppose if all fields are non zero, just concat fields and stop joining further for same key1, key2 because if found all (save
execution time), go to next key1,key2
+----+------+------+
| Id | key1 | key2 |
+----+------+------+
| 1 | 1 | 1 | <- for ref table key1,key2 following rows matches
| Id | key1 | key2 | serial | pr1 | pr2 | pr3 | pr4 | pr5 | nonzero_fields
+----+------+------+--------+------+------+------+------+------+
| 1 | 1 | 1 | 1 | 0 | 0 | 1 | 0 | 2 | = pr3,pr5
| 2 | 1 | 1 | 2 | 0 | 0 | 0 | 0 | 0 | =
| 3 | 1 | 1 | 3 | 0 | 0 | 0 | 1 | 0 | = pr4
| 4 | 1 | 1 | 4 | 1 | 0 | 1 | 1 | 3 | = pr1,pr3,pr4,p45
So distinct of below are
= pr3,pr5
=
= pr4
= pr1,pr3,pr4,p45
key1 key2 fields_non_zero
1 1 pr1,pr3,pr4,pr5
至少我不介意如果我没有得到像下面这样的订单
key1 key2 fields_non_zero
1 1 pr3,pr5,pr4,pr1
table的结构如下
DROP TABLE IF EXISTS `dts`;
CREATE TABLE `dts` (
`Id` int(11) NOT NULL AUTO_INCREMENT,
`key1` int(11) DEFAULT '-99',
`key2` int(11) DEFAULT '-99',
`serial` int(11) DEFAULT '-99',
`pr1` int(11) DEFAULT '-99',
`pr2` int(11) DEFAULT '-99',
`pr3` int(11) DEFAULT '-99',
`pr4` int(11) DEFAULT '-99',
`pr5` int(11) DEFAULT '-99',
PRIMARY KEY (`Id`),
KEY `main` (`key1`,`key2`,`serial`)
) ENGINE=MyISAM AUTO_INCREMENT=13 DEFAULT CHARSET=latin1;
LOCK TABLES `dts` WRITE;
INSERT INTO `dts` VALUES (1,1,1,1,0,0,1,0,2),(2,1,1,2,0,0,0,0,0),(3,1,1,3,0,0,0,1,0),(4,1,1,4,1,0,1,1,3),(5,1,2,5,0,0,0,2,5),(6,1,2,6,0,0,0,0,1),(7,1,2,7,0,1,0,0,0),(8,2,2,1,1,1,1,1,2),(9,2,2,2,0,0,0,0,0),(10,3,2,3,0,0,0,0,0),(11,3,3,1,1,1,0,0,1),(12,3,3,5,0,0,1,1,0);
UNLOCK TABLES;
DROP TABLE IF EXISTS `ref`;
CREATE TABLE `ref` (
`Id` int(11) NOT NULL AUTO_INCREMENT,
`key1` int(11) DEFAULT '-99',
`key2` int(11) DEFAULT '-99',
PRIMARY KEY (`Id`),
KEY `main` (`key1`,`key2`)
) ENGINE=MyISAM AUTO_INCREMENT=7 DEFAULT CHARSET=latin1;
LOCK TABLES `ref` WRITE;
INSERT INTO `ref` VALUES (1,1,1),(2,1,2),(3,2,2),(4,3,1),(5,3,2),(6,3,3);
UNLOCK TABLES;
您可以从 dts table 中逆透视数据，然后在其上使用 group_concat。
SELECT
r.key1,
r.key2,
group_concat(distinct case when val > 0 then pr end order by pr separator ',') prs
FROM
ref r
INNER JOIN
(
SELECT
d.key1,
d.key2,
t.pr,
CASE t.pr
WHEN 'pr1' THEN pr1
WHEN 'pr2' THEN pr2
WHEN 'pr3' THEN pr3
WHEN 'pr4' THEN pr4
WHEN 'pr5' THEN pr5
END val
FROM
dts d
CROSS JOIN
(
SELECT 'pr1' pr UNION ALL
SELECT 'pr2' UNION ALL
SELECT 'pr3' UNION ALL
SELECT 'pr4' UNION ALL
SELECT 'pr5') t
) d ON r.key1 = d.key1 AND r.key2 = d.key2
GROUP BY r.key1 , r.key2;
生产：
+------+------+---------------------+
| key1 | key2 | prs |
+------+------+---------------------+
| 1 | 1 | pr1,pr3,pr4,pr5 |
| 1 | 2 | pr2,pr4,pr5 |
| 2 | 2 | pr1,pr2,pr3,pr4,pr5 |
| 3 | 2 | NULL |
| 3 | 3 | pr1,pr2,pr3,pr4,pr5 |
+------+------+---------------------+
5 rows in set (0.00 sec)
编辑：
没有加入 ref table（因为 ref table 有所有的 key1, key2 而我们只是在内部加入它）：
SELECT
key1,
key2,
group_concat(distinct case when val > 0 then pr end order by pr separator ',') prs
FROM (
SELECT
d.key1,
d.key2,
t.pr,
CASE t.pr
WHEN 'pr1' THEN pr1
WHEN 'pr2' THEN pr2
WHEN 'pr3' THEN pr3
WHEN 'pr4' THEN pr4
WHEN 'pr5' THEN pr5
END val
FROM
dts d
CROSS JOIN (
SELECT 'pr1' pr UNION ALL
SELECT 'pr2' UNION ALL
SELECT 'pr3' UNION ALL
SELECT 'pr4' UNION ALL
SELECT 'pr5'
) t
) r
GROUP BY key1 , key2;
产生相同的输出：
+------+------+---------------------+
| key1 | key2 | prs |
+------+------+---------------------+
| 1 | 1 | pr1,pr3,pr4,pr5 |
| 1 | 2 | pr2,pr4,pr5 |
| 2 | 2 | pr1,pr2,pr3,pr4,pr5 |
| 3 | 2 | NULL |
| 3 | 3 | pr1,pr2,pr3,pr4,pr5 |
+------+------+---------------------+
5 rows in set (0.00 sec)
编辑 2：
SELECT
r.key1,
r.key2,
group_concat(distinct case when val > 0 then pr end order by pr separator ',') prs
FROM (
select key1, key2
from ref
order by id
limit 0, 1000 -- Added limit to get only first 1000 key pairs based on id
) r INNER JOIN (
SELECT
d.key1,
d.key2,
t.pr,
CASE t.pr
WHEN 'pr1' THEN pr1
WHEN 'pr2' THEN pr2
WHEN 'pr3' THEN pr3
WHEN 'pr4' THEN pr4
WHEN 'pr5' THEN pr5
END val
FROM
dts d
CROSS JOIN
(
SELECT 'pr1' pr UNION ALL
SELECT 'pr2' UNION ALL
SELECT 'pr3' UNION ALL
SELECT 'pr4' UNION ALL
SELECT 'pr5') t
) d ON r.key1 = d.key1 AND r.key2 = d.key2
GROUP BY r.key1 , r.key2;
对于前 1000 个唯一密钥对，请在上面的查询中使用以下 SQL：
(
select key1, key2
from ref
group by key1, key2
order by key1, key2
limit 0, 1000 -- Added limit to get only first 1000 key pairs based on id
) r
我有两个 table 如下所示
mysql> show tables;
+-------------------+
| Tables_in_testdbs |
+-------------------+
| dts |
| ref |
+-------------------+
2 rows in set (0.00 sec)
各table内容如下
mysql> select * from ref;
+----+------+------+
| Id | key1 | key2 |
+----+------+------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 2 | 2 |
| 4 | 3 | 1 |
| 5 | 3 | 2 |
| 6 | 3 | 3 |
+----+------+------+
6 rows in set (0.00 sec)
mysql> select * from dts;
+----+------+------+--------+------+------+------+------+------+
| Id | key1 | key2 | serial | pr1 | pr2 | pr3 | pr4 | pr5 |
+----+------+------+--------+------+------+------+------+------+
| 1 | 1 | 1 | 1 | 0 | 0 | 1 | 0 | 2 |
| 2 | 1 | 1 | 2 | 0 | 0 | 0 | 0 | 0 |
| 3 | 1 | 1 | 3 | 0 | 0 | 0 | 1 | 0 |
| 4 | 1 | 1 | 4 | 1 | 0 | 1 | 1 | 3 |
| 5 | 1 | 2 | 5 | 0 | 0 | 0 | 2 | 5 |
| 6 | 1 | 2 | 6 | 0 | 0 | 0 | 0 | 1 |
| 7 | 1 | 2 | 7 | 0 | 1 | 0 | 0 | 0 |
| 8 | 2 | 2 | 1 | 1 | 1 | 1 | 1 | 2 |
| 9 | 2 | 2 | 2 | 0 | 0 | 0 | 0 | 0 |
| 10 | 3 | 2 | 3 | 0 | 0 | 0 | 0 | 0 |
| 11 | 3 | 3 | 1 | 1 | 1 | 0 | 0 | 1 |
| 12 | 3 | 3 | 5 | 0 | 0 | 1 | 1 | 0 |
+----+------+------+--------+------+------+------+------+------+
12 rows in set (0.00 sec)
这是我尝试加入的两个table
mysql> select distinct
-> i.key1,
-> i.key2
-> from
-> ref i,
-> dts d
-> where
-> i.key1=d.key1 and
-> i.key2=d.key2 ;
+------+------+
| key1 | key2 |
+------+------+
| 1 | 1 |
| 1 | 2 |
| 2 | 2 |
| 3 | 2 |
| 3 | 3 |
+------+------+
5 rows in set (0.00 sec)
期待低于o/p，真不知道怎么弄
key1 key2 fields_non_zero
1 1 pr1,pr3,pr4,pr5
1 2 pr2,pr4,pr5
2 2 pr1,pr2,pr3,pr4,pr5
3 2
3 3 pr1,pr2,pr3,pr4,pr5
我想使用以下条件进行检查，例如，让 table 匹配
的key1=1 和 key2=1
- Join two table
- check is there any non zero data in fields(pr1-pr5) of dts, which is matched
- If found concat field name with comma,
- suppose if all fields are non zero, just concat fields and stop joining further for same key1, key2 because if found all (save execution time), go to next key1,key2
+----+------+------+
| Id | key1 | key2 |
+----+------+------+
| 1 | 1 | 1 | <- for ref table key1,key2 following rows matches
| Id | key1 | key2 | serial | pr1 | pr2 | pr3 | pr4 | pr5 | nonzero_fields
+----+------+------+--------+------+------+------+------+------+
| 1 | 1 | 1 | 1 | 0 | 0 | 1 | 0 | 2 | = pr3,pr5
| 2 | 1 | 1 | 2 | 0 | 0 | 0 | 0 | 0 | =
| 3 | 1 | 1 | 3 | 0 | 0 | 0 | 1 | 0 | = pr4
| 4 | 1 | 1 | 4 | 1 | 0 | 1 | 1 | 3 | = pr1,pr3,pr4,p45
So distinct of below are
= pr3,pr5
=
= pr4
= pr1,pr3,pr4,p45
key1 key2 fields_non_zero
1 1 pr1,pr3,pr4,pr5
至少我不介意如果我没有得到像下面这样的订单
key1 key2 fields_non_zero
1 1 pr3,pr5,pr4,pr1
table的结构如下
DROP TABLE IF EXISTS `dts`;
CREATE TABLE `dts` (
`Id` int(11) NOT NULL AUTO_INCREMENT,
`key1` int(11) DEFAULT '-99',
`key2` int(11) DEFAULT '-99',
`serial` int(11) DEFAULT '-99',
`pr1` int(11) DEFAULT '-99',
`pr2` int(11) DEFAULT '-99',
`pr3` int(11) DEFAULT '-99',
`pr4` int(11) DEFAULT '-99',
`pr5` int(11) DEFAULT '-99',
PRIMARY KEY (`Id`),
KEY `main` (`key1`,`key2`,`serial`)
) ENGINE=MyISAM AUTO_INCREMENT=13 DEFAULT CHARSET=latin1;
LOCK TABLES `dts` WRITE;
INSERT INTO `dts` VALUES (1,1,1,1,0,0,1,0,2),(2,1,1,2,0,0,0,0,0),(3,1,1,3,0,0,0,1,0),(4,1,1,4,1,0,1,1,3),(5,1,2,5,0,0,0,2,5),(6,1,2,6,0,0,0,0,1),(7,1,2,7,0,1,0,0,0),(8,2,2,1,1,1,1,1,2),(9,2,2,2,0,0,0,0,0),(10,3,2,3,0,0,0,0,0),(11,3,3,1,1,1,0,0,1),(12,3,3,5,0,0,1,1,0);
UNLOCK TABLES;
DROP TABLE IF EXISTS `ref`;
CREATE TABLE `ref` (
`Id` int(11) NOT NULL AUTO_INCREMENT,
`key1` int(11) DEFAULT '-99',
`key2` int(11) DEFAULT '-99',
PRIMARY KEY (`Id`),
KEY `main` (`key1`,`key2`)
) ENGINE=MyISAM AUTO_INCREMENT=7 DEFAULT CHARSET=latin1;
LOCK TABLES `ref` WRITE;
INSERT INTO `ref` VALUES (1,1,1),(2,1,2),(3,2,2),(4,3,1),(5,3,2),(6,3,3);
UNLOCK TABLES;
您可以从 dts table 中逆透视数据，然后在其上使用 group_concat。
SELECT
r.key1,
r.key2,
group_concat(distinct case when val > 0 then pr end order by pr separator ',') prs
FROM
ref r
INNER JOIN
(
SELECT
d.key1,
d.key2,
t.pr,
CASE t.pr
WHEN 'pr1' THEN pr1
WHEN 'pr2' THEN pr2
WHEN 'pr3' THEN pr3
WHEN 'pr4' THEN pr4
WHEN 'pr5' THEN pr5
END val
FROM
dts d
CROSS JOIN
(
SELECT 'pr1' pr UNION ALL
SELECT 'pr2' UNION ALL
SELECT 'pr3' UNION ALL
SELECT 'pr4' UNION ALL
SELECT 'pr5') t
) d ON r.key1 = d.key1 AND r.key2 = d.key2
GROUP BY r.key1 , r.key2;
生产：
+------+------+---------------------+
| key1 | key2 | prs |
+------+------+---------------------+
| 1 | 1 | pr1,pr3,pr4,pr5 |
| 1 | 2 | pr2,pr4,pr5 |
| 2 | 2 | pr1,pr2,pr3,pr4,pr5 |
| 3 | 2 | NULL |
| 3 | 3 | pr1,pr2,pr3,pr4,pr5 |
+------+------+---------------------+
5 rows in set (0.00 sec)
编辑：
没有加入 ref table（因为 ref table 有所有的 key1, key2 而我们只是在内部加入它）：
SELECT
key1,
key2,
group_concat(distinct case when val > 0 then pr end order by pr separator ',') prs
FROM (
SELECT
d.key1,
d.key2,
t.pr,
CASE t.pr
WHEN 'pr1' THEN pr1
WHEN 'pr2' THEN pr2
WHEN 'pr3' THEN pr3
WHEN 'pr4' THEN pr4
WHEN 'pr5' THEN pr5
END val
FROM
dts d
CROSS JOIN (
SELECT 'pr1' pr UNION ALL
SELECT 'pr2' UNION ALL
SELECT 'pr3' UNION ALL
SELECT 'pr4' UNION ALL
SELECT 'pr5'
) t
) r
GROUP BY key1 , key2;
产生相同的输出：
+------+------+---------------------+
| key1 | key2 | prs |
+------+------+---------------------+
| 1 | 1 | pr1,pr3,pr4,pr5 |
| 1 | 2 | pr2,pr4,pr5 |
| 2 | 2 | pr1,pr2,pr3,pr4,pr5 |
| 3 | 2 | NULL |
| 3 | 3 | pr1,pr2,pr3,pr4,pr5 |
+------+------+---------------------+
5 rows in set (0.00 sec)
编辑 2：
SELECT
r.key1,
r.key2,
group_concat(distinct case when val > 0 then pr end order by pr separator ',') prs
FROM (
select key1, key2
from ref
order by id
limit 0, 1000 -- Added limit to get only first 1000 key pairs based on id
) r INNER JOIN (
SELECT
d.key1,
d.key2,
t.pr,
CASE t.pr
WHEN 'pr1' THEN pr1
WHEN 'pr2' THEN pr2
WHEN 'pr3' THEN pr3
WHEN 'pr4' THEN pr4
WHEN 'pr5' THEN pr5
END val
FROM
dts d
CROSS JOIN
(
SELECT 'pr1' pr UNION ALL
SELECT 'pr2' UNION ALL
SELECT 'pr3' UNION ALL
SELECT 'pr4' UNION ALL
SELECT 'pr5') t
) d ON r.key1 = d.key1 AND r.key2 = d.key2
GROUP BY r.key1 , r.key2;
对于前 1000 个唯一密钥对，请在上面的查询中使用以下 SQL：
(
select key1, key2
from ref
group by key1, key2
order by key1, key2
limit 0, 1000 -- Added limit to get only first 1000 key pairs based on id
) r