如何重组对象数组

Question

我在 parse.com 上从我的后端查询一个名为消息的 NSArray 类型的对象，看起来像这样：

 self.messages = (
"<lean: 0x7fcf98665140, objectId: vglE1UJ5KI, localId: (null)> {\n    messageBody = Jj;\n    recipientId = XvvxETqjph;\n    senderId = XvvxETqjph;\n    timestamp = \"1424991590106.210938\";\n}",
"<lean: 0x7fcf98667940, objectId: rgBFYBMKlU, localId: (null)> {\n    messageBody = \"test 3 from ian\";\n    recipientId = XvvxETqjph;\n    senderId = Hoy7UjLzOh;\n    timestamp = \"1424631667110.638184\";\n}",
"<lean: 0x7fcf98667f30, objectId: hB5uhwsYsu, localId: (null)> {\n    messageBody = \"test 2 from user1\";\n    recipientId = XvvxETqjph;\n    senderId = VQzxWbDnal;\n    timestamp = \"1424630904935.162109\";\n}",
"<lean: 0x7fcf986685b0, objectId: dOe2B9oq5b, localId: (null)> {\n    messageBody = \"test 1\";\n    recipientId = XvvxETqjph;\n    senderId = XvvxETqjph;\n    timestamp = \"1424630808309.478027\";\n}"
)

所以它基本上是一个字典对象数组。如何将其重新格式化为如下所示的普通字典数组：

self.messages = (
"{\n objectId: vglE1UJ5KI;\n    messageBody = Jj;\n    recipientId = XvvxETqjph;\n    senderId = XvvxETqjph;\n    timestamp = \"1424991590106.210938\";\n}",
"{\n objectId: rgBFYBMKlU;\n    messageBody = \"test 3 from ian\";\n    recipientId = XvvxETqjph;\n    senderId = Hoy7UjLzOh;\n    timestamp = \"1424631667110.638184\";\n}",
"{\n objectId: hB5uhwsYsu;\n    messageBody = \"test 2 from user1\";\n    recipientId = XvvxETqjph;\n    senderId = VQzxWbDnal;\n    timestamp = \"1424630904935.162109\";\n}",
"{\n objectId: dOe2B9oq5b;\n    messageBody = \"test 1\";\n    recipientId = XvvxETqjph;\n    senderId = XvvxETqjph;\n    timestamp = \"1424630808309.478027\";\n}"
)

Answer 1

parse 返回的 PFObject 非常像字典，因为它响应 allKeys 和 objectForKey: 和 setObject:forKey:，等等。我在 SO 上看到几个提问者对 PFObject 实现 description 的方式以及它在控制台上的打印方式感到困惑，这使得它看起来不像字典，而不是它应该的样子。

无论如何，如果由于某种原因确实必须有一个 NSDictionaries 的 NSArray，而不是一个类似字典的对象的 NSArray，那么他们可以使用这样的代码：

- (NSDictionary *)dictionaryFromPFObject:(PFObject *)pfObject {
    NSMutableDictionary *dictionary = [NSMutableDictionary dictionary];
    for (NSString *key in [pfObject allKeys]) {
        dictionary[key] = [pfObject objectForKey:key];
    }
    return dictionary;
}

... 并从这样的查找完成块中调用它：

[query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
    if (!error) {
        NSMutableArray *array = [NSMutableArray array];
        for (PFObject *pfObject in objects) {
            [array addObject:[self dictionaryFromPFObject:pfObject]];
        }
    }
}];

如何重组对象数组

How to restructure array of objects

ios

objective-c

arrays

parse-platform

nsdictionary