Google 表单如果命令错误

Question

我一直在尝试为 Google 表单编写一个函数，该表单将向表单指定的特定教师发送电子邮件。问题是我在简单的 if 语句中不断出错。错误显示，"Missing ; before statement. (line 29, file "Code")"。该代码基于 Google 应用程序教程：https://developers.google.com/apps-script/articles/mail_merge#section-5-full-code。这就是我现在拥有的：

    function sendEmails() {
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var dataSheet = ss.getSheets()[0];
  var dataRange = dataSheet.getRange(2, 1, dataSheet.getMaxRows() - 1, 4);

  var templateSheet = ss.getSheets()[1];
  var emailTemplate = templateSheet.getRange("A1").getValue();

  // Create one JavaScript object per row of data.
  var objects = getRowsData(dataSheet, dataRange);

  // For every row object, create a personalized email from a template and send
  // it to the appropriate person.
  for (var i = 0; i < objects.length; ++i) {
    // Get a row object
    var rowData = objects[i];

    // Generate a personalized email.
    // Given a template string, replace markers (for instance ${"First Name"}) with
    // the corresponding value in a row object (for instance rowData.firstName).
    var emailText = fillInTemplateFromObject(emailTemplate, rowData);
    var emailSubject = "Lab Visit Report";

  var sheet = SpreadsheetApp.getActiveSheet();
  var data = sheet.getDataRange().getValues();
  for (var i = 0; i < data.length; i++) {
  var teacher = data[i][10];

    If (teacher == "Jake Nabasny") {MailApp.sendEmail("JakeN@school.edu", emailSubject, emailText);}
    else if (teacher == "Dan S") {MailApp.sendEmail("DanS@school.edu", emailSubject, emailText);}

  }
}

我已经确保变量（例如 teacher 和 emailText）包含数据。据我所知，问题完全出在 if 语句上。谁能告诉我这里出了什么问题？

Answer 1

你好像把 If 大写了...

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