如何使用 Moment JS 计算范围之间给定工作日的数量?
How do I calculate number of given weekday between range using Moment JS?
如何使用 Moment JS 和 jQuery 找出给定工作日(例如:星期二)中有多少个工作日?
我可以使用差值找到天数:
http://momentjs.com/docs/#/displaying/difference/
而且我知道开始和结束日期,所以我觉得应该可以吧?
示例:3 月 1 日到 3 月 25 日之间有多少个星期二?
如果您要查找两个日期 N 之间的工作日数 W(例如星期一、星期二...)和 M,您可以:
- 在 N.[=36= 之后找到 W 的下一个 N' ]
- 求 N' 和 M 之间的天数。
- 如果N'在M之后,则没有W之间。否则,W 天数应为 1 + floor((M-N)/7).
function getWeekdaysBetweenDates(firstDate, secondDate, dayOfWeek) {
var MILISECONDS_IN_DAY = 86400000;
function getNextDayOfWeek(date, dayOfWeek) {
date.setDate(date.getDate() + (7 + dayOfWeek - date.getDay()) % 7);
return date;
}
firstDate = getNextDayOfWeek(firstDate, dayOfWeek);
if (firstDate > secondDate) {
return 0;
}
return 1 + Math.floor(((secondDate - firstDate) / MILISECONDS_IN_DAY) / 7);
}
var firstDate = new Date("March 1, 2015");
var secondDate = new Date("March 25, 2015");
console.log(getWeekdaysBetweenDates(firstDate, secondDate, 2));
// 4
我想出了以下函数,它似乎适用于我尝试过的给定的少数测试用例:
function weekdaysBetween(d1, d2, isoWeekday) {
// ensure we have valid moment instances
d1 = moment(d1);
d2 = moment(d2);
// figure out how many days to advance to get to the next
// specified weekday (might be 0 if d1 is already the
// specified weekday).
var daysToAdd = ((7 + isoWeekday) - d1.isoWeekday()) % 7;
var nextTuesday = d1.clone().add(daysToAdd, 'days');
// if we are already passed the end date, there must not
// be any of that day in the given period.
if (nextTuesday.isAfter(d2)) {
return 0;
}
// otherwise, just return the whole number of weeks
// difference plus one for the day we already advanced to
var weeksBetween = d2.diff(nextTuesday, 'weeks');
return weeksBetween + 1;
}
您输入了您要计算的那一天的 isoWeekday
值。例如星期二,传入 2
.
示例调用:
var d1 = moment('2015-03-01');
var d2 = moment('2015-03-25');
console.log('result:', weekdaysBetween(d1, d2, 2)); // => result: 4
Wolfram Alpha gives the same result.
不过,在完全信任它之前,您应该添加自己的测试。
https://github.com/andruhon/moment-weekday-calc 满足您的需求。
它计算范围内的特定工作日,并可选择排除特定日期(比如 public 假期)
用法:
moment().isoWeekdayCalc({
rangeStart: '1 Apr 2015',
rangeEnd: '31 Mar 2016',
weekdays: [1,2,3,4,5], //weekdays Mon to Fri
exclusions: ['6 Apr 2015','7 Apr 2015'] //public holidays
}) //returns 260 (260 workdays excluding two public holidays)
如果你像我一样对数学感到困惑:
var startDate = moment().startOf('month');
var endDate = moment().endOf('month');
var aDate = moment(startDate).day('Sunday');
var weekDays = 0;
while (aDate.isSameOrBefore(endDate)) {
if (aDate.isSameOrAfter(startDate) && aDate.isSameOrBefore(endDate))
weekDays++;
aWeekDayDate.add(1, 'week');
}
let dayno = [0, 1, 2, 3, 4, 5, 6]
for (let i = 0; i < dayno.length; i++) {
let start = moment('2022-1-01')
let end = moment('2022-1-31')
getweek(start, end, dayno[i])
}
var dataArray = []
const getweek = (start, end, dayno) => {
var arr = []
let tmp = start.clone().day(dayno)
if (tmp.isAfter(start, 'd')) {
arr.push(tmp.format('YYYY-MM-DD'))
}
while (tmp.isBefore(end)) {
tmp.add(7, 'days')
if (tmp.format('M') == start.format('M')) {
arr.push(tmp.format('YYYY-MM-DD'))
}
}
const dow = moment(start).startOf('month').day()
if (dow + 1 == dayno + 1) {
var obj = {
name: dayno + 1,
value: arr.length + 1,
}
} else {
var obj = {
name: dayno + 1,
value: arr.length,
}
}
dataArray.push(obj)
}
如何使用 Moment JS 和 jQuery 找出给定工作日(例如:星期二)中有多少个工作日?
我可以使用差值找到天数: http://momentjs.com/docs/#/displaying/difference/
而且我知道开始和结束日期,所以我觉得应该可以吧?
示例:3 月 1 日到 3 月 25 日之间有多少个星期二?
如果您要查找两个日期 N 之间的工作日数 W(例如星期一、星期二...)和 M,您可以:
- 在 N.[=36= 之后找到 W 的下一个 N' ]
- 求 N' 和 M 之间的天数。
- 如果N'在M之后,则没有W之间。否则,W 天数应为 1 + floor((M-N)/7).
function getWeekdaysBetweenDates(firstDate, secondDate, dayOfWeek) {
var MILISECONDS_IN_DAY = 86400000;
function getNextDayOfWeek(date, dayOfWeek) {
date.setDate(date.getDate() + (7 + dayOfWeek - date.getDay()) % 7);
return date;
}
firstDate = getNextDayOfWeek(firstDate, dayOfWeek);
if (firstDate > secondDate) {
return 0;
}
return 1 + Math.floor(((secondDate - firstDate) / MILISECONDS_IN_DAY) / 7);
}
var firstDate = new Date("March 1, 2015");
var secondDate = new Date("March 25, 2015");
console.log(getWeekdaysBetweenDates(firstDate, secondDate, 2));
// 4
我想出了以下函数,它似乎适用于我尝试过的给定的少数测试用例:
function weekdaysBetween(d1, d2, isoWeekday) {
// ensure we have valid moment instances
d1 = moment(d1);
d2 = moment(d2);
// figure out how many days to advance to get to the next
// specified weekday (might be 0 if d1 is already the
// specified weekday).
var daysToAdd = ((7 + isoWeekday) - d1.isoWeekday()) % 7;
var nextTuesday = d1.clone().add(daysToAdd, 'days');
// if we are already passed the end date, there must not
// be any of that day in the given period.
if (nextTuesday.isAfter(d2)) {
return 0;
}
// otherwise, just return the whole number of weeks
// difference plus one for the day we already advanced to
var weeksBetween = d2.diff(nextTuesday, 'weeks');
return weeksBetween + 1;
}
您输入了您要计算的那一天的 isoWeekday
值。例如星期二,传入 2
.
示例调用:
var d1 = moment('2015-03-01');
var d2 = moment('2015-03-25');
console.log('result:', weekdaysBetween(d1, d2, 2)); // => result: 4
Wolfram Alpha gives the same result.
不过,在完全信任它之前,您应该添加自己的测试。
https://github.com/andruhon/moment-weekday-calc 满足您的需求。 它计算范围内的特定工作日,并可选择排除特定日期(比如 public 假期)
用法:
moment().isoWeekdayCalc({
rangeStart: '1 Apr 2015',
rangeEnd: '31 Mar 2016',
weekdays: [1,2,3,4,5], //weekdays Mon to Fri
exclusions: ['6 Apr 2015','7 Apr 2015'] //public holidays
}) //returns 260 (260 workdays excluding two public holidays)
如果你像我一样对数学感到困惑:
var startDate = moment().startOf('month');
var endDate = moment().endOf('month');
var aDate = moment(startDate).day('Sunday');
var weekDays = 0;
while (aDate.isSameOrBefore(endDate)) {
if (aDate.isSameOrAfter(startDate) && aDate.isSameOrBefore(endDate))
weekDays++;
aWeekDayDate.add(1, 'week');
}
let dayno = [0, 1, 2, 3, 4, 5, 6]
for (let i = 0; i < dayno.length; i++) {
let start = moment('2022-1-01')
let end = moment('2022-1-31')
getweek(start, end, dayno[i])
}
var dataArray = []
const getweek = (start, end, dayno) => {
var arr = []
let tmp = start.clone().day(dayno)
if (tmp.isAfter(start, 'd')) {
arr.push(tmp.format('YYYY-MM-DD'))
}
while (tmp.isBefore(end)) {
tmp.add(7, 'days')
if (tmp.format('M') == start.format('M')) {
arr.push(tmp.format('YYYY-MM-DD'))
}
}
const dow = moment(start).startOf('month').day()
if (dow + 1 == dayno + 1) {
var obj = {
name: dayno + 1,
value: arr.length + 1,
}
} else {
var obj = {
name: dayno + 1,
value: arr.length,
}
}
dataArray.push(obj)
}