如何使用 Moment JS 计算范围之间给定工作日的数量?

How do I calculate number of given weekday between range using Moment JS?

如何使用 Moment JS 和 jQuery 找出给定工作日(例如:星期二)中有多少个工作日?

我可以使用差值找到天数: http://momentjs.com/docs/#/displaying/difference/

而且我知道开始和结束日期,所以我觉得应该可以吧?

示例:3 月 1 日到 3 月 25 日之间有多少个星期二?

如果您要查找两个日期 N 之间的工作日数 W(例如星期一、星期二...)和 M,您可以:

  1. N.[=36= 之后找到 W 的下一个 N' ]
  2. N'M 之间的天数。
  3. 如果N'M之后,则没有W之间。否则,W 天数应为 1 + floor((M-N)/7).
function getWeekdaysBetweenDates(firstDate, secondDate, dayOfWeek) {
    var MILISECONDS_IN_DAY = 86400000;

    function getNextDayOfWeek(date, dayOfWeek) {
        date.setDate(date.getDate() + (7 + dayOfWeek - date.getDay()) % 7);
        return date;
    }

    firstDate = getNextDayOfWeek(firstDate, dayOfWeek);
    if (firstDate > secondDate) {
        return 0;
    }

    return 1 + Math.floor(((secondDate - firstDate) / MILISECONDS_IN_DAY) / 7);
}

var firstDate = new Date("March 1, 2015");
var secondDate = new Date("March 25, 2015");
console.log(getWeekdaysBetweenDates(firstDate, secondDate, 2));
// 4

我想出了以下函数,它似乎适用于我尝试过的给定的少数测试用例:

function weekdaysBetween(d1, d2, isoWeekday) {
    // ensure we have valid moment instances
    d1 = moment(d1);
    d2 = moment(d2);
    // figure out how many days to advance to get to the next
    // specified weekday (might be 0 if d1 is already the 
    // specified weekday).
    var daysToAdd = ((7 + isoWeekday) - d1.isoWeekday()) % 7;
    var nextTuesday = d1.clone().add(daysToAdd, 'days');
    // if we are already passed the end date, there must not
    // be any of that day in the given period.
    if (nextTuesday.isAfter(d2)) {
        return 0;
    }
    // otherwise, just return the whole number of weeks
    // difference plus one for the day we already advanced to
    var weeksBetween = d2.diff(nextTuesday, 'weeks');
    return weeksBetween + 1;
}

您输入了您要计算的那一天的 isoWeekday 值。例如星期二,传入 2.

示例调用:

var d1 = moment('2015-03-01');
var d2 = moment('2015-03-25');

console.log('result:', weekdaysBetween(d1, d2, 2)); // => result: 4

Wolfram Alpha gives the same result.

不过,在完全信任它之前,您应该添加自己的测试。

https://github.com/andruhon/moment-weekday-calc 满足您的需求。 它计算范围内的特定工作日,并可选择排除特定日期(比如 public 假期)

用法:

moment().isoWeekdayCalc({  
  rangeStart: '1 Apr 2015',  
  rangeEnd: '31 Mar 2016',  
  weekdays: [1,2,3,4,5], //weekdays Mon to Fri
  exclusions: ['6 Apr 2015','7 Apr 2015']  //public holidays
}) //returns 260 (260 workdays excluding two public holidays)

如果你像我一样对数学感到困惑:

var startDate = moment().startOf('month');
var endDate = moment().endOf('month');

var aDate = moment(startDate).day('Sunday');

var weekDays = 0;
while (aDate.isSameOrBefore(endDate)) {
   if (aDate.isSameOrAfter(startDate) && aDate.isSameOrBefore(endDate))
        weekDays++;
   aWeekDayDate.add(1, 'week');
}
let dayno = [0, 1, 2, 3, 4, 5, 6]
for (let i = 0; i < dayno.length; i++) {
      let start = moment('2022-1-01')
      let end = moment('2022-1-31')
      getweek(start, end, dayno[i])
    }

var dataArray = []

  const getweek = (start, end, dayno) => {
    var arr = []
    let tmp = start.clone().day(dayno)
    if (tmp.isAfter(start, 'd')) {
      arr.push(tmp.format('YYYY-MM-DD'))
    }
    while (tmp.isBefore(end)) {
      tmp.add(7, 'days')
      if (tmp.format('M') == start.format('M')) {
        arr.push(tmp.format('YYYY-MM-DD'))
      }
    }

    const dow = moment(start).startOf('month').day()

    if (dow + 1 == dayno + 1) {
      var obj = {
        name: dayno + 1,
        value: arr.length + 1,
      }
    } else {
      var obj = {
        name: dayno + 1,
        value: arr.length,
      }
    }

    dataArray.push(obj)
  }