获取此输出的所有值 json
Getting All the values of this output json
我想提取这些咖啡的名字这是我输出的摘录,因为我有大约 1000 个名字,我想自动提取它们:
results = (
{
geometry = {
location = {
lat = "-33.3979227";
lng = "-70.58503859999999";
};
viewport = {
northeast = {
lat = "-33.39783990000001";
lng = "-70.58502229999999";
};
southwest = {
lat = "-33.39795669999999";
lng = "-70.58507830000001";
};
};
};
id = 46354da06de96a36c5c44a5fa05a10f8f83f8edd;
name = "Hotel Bidasoa";
"opening_hours" = {
"open_now" = 1;
"weekday_text" = (
);
};
}
);
"place_id" = ChIJ4dfUCC7PYpYRRDkSNifrfBE;
rating = "4.7";
scope = GOOGLE;
types = (
cafe,
lodging,
food,
store,
"point_of_interest",
establishment
);
vicinity = "Avenida Vitacura 4873, Santiago, Santiago";
},
{
geometry = {
location = {
lat = "-33.37900460000001";
lng = "-70.55533029999999";
};
viewport = {
northeast = {
lat = "-33.37897230000002";
lng = "-70.5553148";
};
southwest = {
lat = "-33.37910149999999";
lng = "-70.55537679999999";
};
};
};
id = c451d2146b7a065fa1afd0ffa39353a4b1cae178;
name = "Ceibo Emporio Cafeter\U00eda";
"opening_hours" = {
"open_now" = 0;
"weekday_text" = (
);
};
这是我的代码,但只显示我想要的名字,因为我有 1000 个名字:
let jsonResult = try JSONSerialization.jsonObject(with: urlContent, options: JSONSerialization.ReadingOptions.mutableContainers) as AnyObject
print (jsonResult)
if let nombre = ((jsonResult["results"]as?NSArray)?[0]as?NSDictionary)?["name"] {
print (nombre)
}
一如既往:
- 从不 在解析 JSON.
时在 Swift 中使用 NSDictionary / NSArray
- 从不 在 Swift 中使用
mutableContainers
。完全没用。
要获取 results
数组中的所有项目,请使用循环,为了方便和可读性,请使用类型别名:
typealias JSONDictionary = [String:Any]
if let jsonResult = try JSONSerialization.jsonObject(with: urlContent, options: []) as? JSONDictionary {
print (jsonResult)
if let results = jsonResult["results"] as? [JSONDictionary] {
for result in results {
print(result["name"] as? String ?? "n/a")
if let geometry = result["geometry"] as? JSONDictionary,
let location = geometry["location"] as? JSONDictionary {
let lat = location["lat"] as? Double ?? 0.0
let lng = location["lng"] as? Double ?? 0.0
print("latitude: \(lat)")
print("longitude: \(lng)")
}
}
}
}
我想提取这些咖啡的名字这是我输出的摘录,因为我有大约 1000 个名字,我想自动提取它们:
results = (
{
geometry = {
location = {
lat = "-33.3979227";
lng = "-70.58503859999999";
};
viewport = {
northeast = {
lat = "-33.39783990000001";
lng = "-70.58502229999999";
};
southwest = {
lat = "-33.39795669999999";
lng = "-70.58507830000001";
};
};
};
id = 46354da06de96a36c5c44a5fa05a10f8f83f8edd;
name = "Hotel Bidasoa";
"opening_hours" = {
"open_now" = 1;
"weekday_text" = (
);
};
}
);
"place_id" = ChIJ4dfUCC7PYpYRRDkSNifrfBE;
rating = "4.7";
scope = GOOGLE;
types = (
cafe,
lodging,
food,
store,
"point_of_interest",
establishment
);
vicinity = "Avenida Vitacura 4873, Santiago, Santiago";
},
{
geometry = {
location = {
lat = "-33.37900460000001";
lng = "-70.55533029999999";
};
viewport = {
northeast = {
lat = "-33.37897230000002";
lng = "-70.5553148";
};
southwest = {
lat = "-33.37910149999999";
lng = "-70.55537679999999";
};
};
};
id = c451d2146b7a065fa1afd0ffa39353a4b1cae178;
name = "Ceibo Emporio Cafeter\U00eda";
"opening_hours" = {
"open_now" = 0;
"weekday_text" = (
);
};
这是我的代码,但只显示我想要的名字,因为我有 1000 个名字:
let jsonResult = try JSONSerialization.jsonObject(with: urlContent, options: JSONSerialization.ReadingOptions.mutableContainers) as AnyObject
print (jsonResult)
if let nombre = ((jsonResult["results"]as?NSArray)?[0]as?NSDictionary)?["name"] {
print (nombre)
}
一如既往:
- 从不 在解析 JSON. 时在 Swift 中使用
- 从不 在 Swift 中使用
mutableContainers
。完全没用。
NSDictionary / NSArray
要获取 results
数组中的所有项目,请使用循环,为了方便和可读性,请使用类型别名:
typealias JSONDictionary = [String:Any]
if let jsonResult = try JSONSerialization.jsonObject(with: urlContent, options: []) as? JSONDictionary {
print (jsonResult)
if let results = jsonResult["results"] as? [JSONDictionary] {
for result in results {
print(result["name"] as? String ?? "n/a")
if let geometry = result["geometry"] as? JSONDictionary,
let location = geometry["location"] as? JSONDictionary {
let lat = location["lat"] as? Double ?? 0.0
let lng = location["lng"] as? Double ?? 0.0
print("latitude: \(lat)")
print("longitude: \(lng)")
}
}
}
}