嵌套 SKActions 不使用等待时间

Question

我正在尝试在 SKSpriteNode 上执行以下操作：把它变大，将其移动到新位置，再变小。

但是，代码似乎运行一下子变大和变小相互抵消了。

这是在 Playground 中创建的代码：

import PlaygroundSupport
import UIKit
import SpriteKit

var theirCard:SKSpriteNode
let CARDSHRINK_TIME = 5.0
let AICARDMOVE_SPEED = 2.5
let droppoint:CGPoint = CGPoint(x: 100,y:  100)

let sceneView = SKView(frame: CGRect(x:0 , y:0, width: 480, height: 320))

let scene = SKScene(size: CGSize(width: 480, height: 320))
sceneView.showsFPS = true
sceneView.presentScene(scene)
PlaygroundSupport.PlaygroundPage.current.liveView = sceneView

theirCard = SKSpriteNode(imageNamed: "card")
theirCard.name = "theircard"
theirCard.position = CGPoint(x: scene.size.width * 0.50, y: scene.size.height * 0.5)

scene.addChild(theirCard)

func getwait(makeBig big:Bool) -> SKAction {
    let ret = SKAction.wait(forDuration: CARDSHRINK_TIME)
    var action:SKAction

    if big {
        action = SKAction.scale(to: 1.9, duration: CARDSHRINK_TIME)
    }
    else {
        action = SKAction.scale(to: 1.0, duration: CARDSHRINK_TIME)
    }
    theirCard.run(action, completion: { print("getwait \(big) done!") } )

    return ret
}



// We want to MAKE the node BIG, move it to the location, then make it SMALL again
let action1:SKAction = getwait(makeBig: true)
let action2:SKAction = SKAction.move(to: droppoint, duration: AICARDMOVE_SPEED)
let action3:SKAction = getwait(makeBig: false )
let seq:SKAction = SKAction.sequence([action1, action2, action3])
theirCard.run(seq, completion: {
    print("animation complete!!!!")
})

我需要保持 getwait 的原样，因为在实际代码中它是 Card class 的一个方法（实际上是 theirCard）。我简化了它以便在 Playground

中进行测试

更新：

let action1 = SKAction.scale(to: 1.9, duration: CARDSHRINK_TIME)
let action2:SKAction = SKAction.move(to: droppoint, duration: AICARDMOVE_SPEED)
let action3 = SKAction.scale(to: 1.0, duration: CARDSHRINK_TIME)

如我所愿，但这意味着我无法使用卡片 class 中的方法。

Answer 1

使用 getwait(makeBig: true) 时一次性执行运行的原因是因为以下行：

theirCard.run(action, completion: { print("getwait \(big) done!") } )

无论何时调用该函数，您都会立即使卡片运行成为一个动作。所以你可以看到为什么连续打电话

getwait(makeBig: true)
getwait(makeBig: false)

只会在相同时间产生卡片放大和缩小的净效应。

建议改写如下：

func getScaleAction(makeBig big:Bool) -> SKAction {
    return SKAction.scale(to: big? 1.9 : 1.0, duration: CARDSHRINK_TIME)
}

并按如下方式调用它：

let scaleUp = getScaleAction(makeBig: true)
let move = SKAction.move(to: droppoint, duration: AICARDMOVE_SPEED)
let scaleDown = getScaleAction(makeBig: false)

theirCard.run(SKAction.sequence([scaleUp, move, scaleDown])) {
    print("done")
}

嵌套 SKActions 不使用等待时间

Nesting SKActions not using wait duration

swift

duration

skaction