中间件取消路由前的 Silex 应用程序
Silex application before middleware cancel route
我找不到在 "Before Middleware" 中取消操作并在不执行控制器的情况下将响应发送给客户端的方法。
例如:
$app->before( function( Request $request ) {
// Do something here
// ...
// Here sent the response to the client and don't execute the controller
}});
可以吗?
一个例子
这段代码工作正常。我正在寻找使用框架内置方法的另一种解决方案。如果不可能,没问题。
$app->before( function( Request $request ) {
// Do something here
// ...
header( 'Content-Type: application/json' );
echo json_encode( array(
'message' => 'Invalid token'
) );
http_response_code( 400 ); // This code return Bad Request to client
exit; // Cancel the rest of the framework
}});
你检查过 official documentation 了吗?来自中间件文档:
Short-circuiting the Controller
If a before middleware returns a Response object, the request handling is short-circuited (the next middleware won't be run, nor the route callback), and the Response is passed to the after middleware right away:
$app->before(function (Request $request) {
// redirect the user to the login screen if access to the Resource is protected
if (...) {
return new RedirectResponse('/login');
}
});
如果您 return 一个 Response 对象,它应该可以工作,而不是调用控制器。
如果您想立即取消您的请求并且 return 400 响应使用例外。在您的情况下,用户未经授权,因此适合 401 之类的内容。
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpKernel\HttpKernelInterface;
use Symfony\Component\HttpKernel\Exception\UnauthorizedHttpException;
use Symfony\Component\HttpFoundation\Response;
$app->match('/', function () use ($app) {
$app->before(function (Request $request) {
$loggedIn= false;
if (!$loggedIn) {
throw new UnauthorizedHttpException(null,'unauthorized',null,Response::HTTP_UNAUTHORIZED);
}
});
});
$app->error(function (\Exception $e, Request $request, $code) {
$message = strlen($e->getMessage()) > 0 ? $e->getMessage() : null;
switch ($code) {
case Response::HTTP_UNAUTHORIZED:
$response = new Response($message, Response::HTTP_UNAUTHORIZED);
break;
default:
$response = new Response($message, Response::HTTP_NOT_FOUND);
break;
}
return $response;
});
我找不到在 "Before Middleware" 中取消操作并在不执行控制器的情况下将响应发送给客户端的方法。
例如:
$app->before( function( Request $request ) {
// Do something here
// ...
// Here sent the response to the client and don't execute the controller
}});
可以吗?
一个例子
这段代码工作正常。我正在寻找使用框架内置方法的另一种解决方案。如果不可能,没问题。
$app->before( function( Request $request ) {
// Do something here
// ...
header( 'Content-Type: application/json' );
echo json_encode( array(
'message' => 'Invalid token'
) );
http_response_code( 400 ); // This code return Bad Request to client
exit; // Cancel the rest of the framework
}});
你检查过 official documentation 了吗?来自中间件文档:
Short-circuiting the Controller
If a before middleware returns a Response object, the request handling is short-circuited (the next middleware won't be run, nor the route callback), and the Response is passed to the after middleware right away:
$app->before(function (Request $request) {
// redirect the user to the login screen if access to the Resource is protected
if (...) {
return new RedirectResponse('/login');
}
});
如果您 return 一个 Response 对象,它应该可以工作,而不是调用控制器。
如果您想立即取消您的请求并且 return 400 响应使用例外。在您的情况下,用户未经授权,因此适合 401 之类的内容。
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpKernel\HttpKernelInterface;
use Symfony\Component\HttpKernel\Exception\UnauthorizedHttpException;
use Symfony\Component\HttpFoundation\Response;
$app->match('/', function () use ($app) {
$app->before(function (Request $request) {
$loggedIn= false;
if (!$loggedIn) {
throw new UnauthorizedHttpException(null,'unauthorized',null,Response::HTTP_UNAUTHORIZED);
}
});
});
$app->error(function (\Exception $e, Request $request, $code) {
$message = strlen($e->getMessage()) > 0 ? $e->getMessage() : null;
switch ($code) {
case Response::HTTP_UNAUTHORIZED:
$response = new Response($message, Response::HTTP_UNAUTHORIZED);
break;
default:
$response = new Response($message, Response::HTTP_NOT_FOUND);
break;
}
return $response;
});