相当于使用proto？

Question

我正在尝试将揭示模块模式与继承结合使用。我似乎让它工作正常，但它使用“__proto__”，我知道它被认为已弃用。有没有更好的方法是不使用“__proto__”来创建继承？

var Person = (function() {
    var _name;
    var api = {
        init: init,
        getName: getName
    }
    return api;

    function init(name) {
        _name = name;
    }

    function getName() {
        return _name;
    }
}())

var Teacher = (function() {
    var _subject = "Math";
    var api = {
        getSubject: getSubject,
        say: say
    }
    api.__proto__ = Person;
    return api;

    function getSubject() {
        return _subject;
    }

    function say() {
        console.log("I am " + this.getName() + " and I teach " + _subject)
    }
}());

Teacher.init("Bob");
Teacher.say() //  I am Bob and I teach math

https://plnkr.co/edit/XbGx38oCyvRn79xnn2FR?p=preview

Answer 1

直接等价物——设置原型，仍然是个坏主意——是Object.setPrototypeOf:

Object.setPrototypeOf(api, Person);

使用 Object.create 基于原型创建对象然后向其添加属性的常规方法在这里工作正常，但是：

var api = Object.create(Person);
api.getSubject = getSubject;
api.say = say;

但理想情况下，您只需要使用构造函数：

class Person {
    constructor(name) {
        this._name = name;
    }

    getName() {
        return this._name;
    }
}

class Teacher extends Person {
    constructor(name) {
        super(name);
        this._subject = 'Math';
    }

    getSubject() {
        return this._subject;
    }

    say() {
        console.log(`I am ${this.getName()} and I teach ${this.getSubject()}`);
    }
}

var teacher = new Teacher('Bob');
teacher.say() //  I am Bob and I teach math

没有 ES6：

function Person(name) {
    this._name = name;
}

Person.prototype.getName = function () {
    return this._name;
};

function Teacher(name) {
    Person.call(this, name);
    this._subject = 'Math';
}

Teacher.prototype = Object.create(Person.prototype);

Teacher.prototype.getSubject = function () {
    return this._subject;
};

Teacher.prototype.say = function () {
    console.log('I am ' + this.getName() + ' and I teach ' + this.getSubject());
};

var teacher = new Teacher('Bob');
teacher.say();  // I am Bob and I teach math

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