SQL 来自数据库的语句

SQL Statement from database

我不是 SQL 中的 "pro"。

我有以下场景:

Table: 最喜欢的颜色

 User   |Red    |Blue   |Yellow |Green  |Black
 Klaus  |0      |1      |1      |0      |0
 Jessy  |1      |0      |1      |0      |1 
 Andy   |1      |1      |0      |0      |0 
 Alex   |0      |0      |0      |1      |1 
 Denis  |1      |1      |0      |0      |1

HTML代码

 <form method="post" action="./usercolor.php"> <input type="checkbox" id="colorred" name="colorred" value="1" />red</td>
 <input type="checkbox" id="colorblue" name="colorblue" value="1" />blue</td>
 <input type="checkbox" id="coloryellow" name="coloryellow" value="1" />yellow</td>
 <input type="checkbox" id="colorgreen" name="colorgreen" value="1" />green</td>
 <input type="checkbox" id="colorblack" name="colorblack" value="1" />black</td>
 <input type="submit" value="SEARCH" /> </form>

PHP/SQL(使用MySQL 5.6):

    $colorred       =   $_POST["colorred"];
    $colorblue      =   $_POST["colorblue"];
    $colorgreen     =   $_POST["colorgreen"];
    $coloryellow    =   $_POST["coloryellow"];
    $colorblack     =   $_POST["colorblack"];

SELECT * FROM favcolor WHERE red = '".$colorred."' AND blue = '".$colorblue."' AND green = '".$colorgreen."' AND yellow = '".$coloryellow."' AND black = '".$colorblack."'

现在解决我的问题: 例如我想知道哪个用户喜欢黄色。然后我选中 id "coloryellow" 上的复选框并按 "SEARCH"。 但是我没有收到任何结果,因为 SQL 语句中的 "AND" 运算符是错误的... 我必须使用哪个运算符才能让我的 SQL 语句给我两个结果?

$whereArr = Array();
if (isset($_POST["colorred"]) && $_POST["colorred"]==1) $whereArr[] = "red=1";
if (isset($_POST["colorblue"]) && $_POST["colorblue"]==1) $whereArr[] = "blue=1";
if (isset($_POST["colorgreen"]) && $_POST["colorgreen"]==1) $whereArr[] = "green=1";
if (isset($_POST["coloryellow"]) && $_POST["coloryellow"]==1) $whereArr[] = "yellow=1";
if (isset($_POST["colorblack"]) && $_POST["colorblack"]==1) $whereArr[] = "black=1";

$sqlStr = "SELECT * FROM favcolor WHERE " . implode(" AND ", $whereArr);

然后你运行查询