复制字符串末尾并粘贴到新列

Question

我使用哪个 UNIX 命令复制第 1 列中字符串的末尾并将其粘贴到新列？

例如，

> $ head -3 test1.bed 
> HLA:HLA00001_A_01:01:01:01_3503  1 
> HLA:HLA02169_A_01:01:01:02N_3291 1 
> HLA:HLA14798_A_01:01:01:03_2903  1

变成，

> $ head -3 test1.bed 
> HLA:HLA00001_A_01:01:01:01_3503  1 3503
> HLA:HLA02169_A_01:01:01:02N_3291 1 3291
> HLA:HLA14798_A_01:01:01:03_2903  1 2903

Answer 1

awk 救援！

$ awk '{n=split(,a,"_"); print [=10=], a[n]}' file

HLA:HLA00001_A_01:01:01:01_3503  1  3503
HLA:HLA02169_A_01:01:01:02N_3291 1  3291
HLA:HLA14798_A_01:01:01:03_2903  1 2903

复制字符串末尾并粘贴到新列

Copy end of string and paste to new column

awk

sed

paste

cut