在 React 中检测 2 个键的 onKeyPress

Detect onKeyPress for 2 keys in React

我有一个 input 元素,上面有 onKeyPress 属性。

<input type="text" onKeyPress={this.keyPressed}

我想知道何时按下 EnterEscape 并采取相应行动。

keyPressed: function(e) {

    if (e.key == 'Enter') {
        console.log('Enter was pressed!');
    } 
    else if (e.key == 'Escape') {
        console.log('Escape was pressed!');
    } 
    else {
        return;
    }
}

我能够检测到何时按下 Enter 但在按下 Escape 时无法检测到。


编辑


更新:

我已经设法让它工作了。
检查我的答案:

在输入元素上

在我的函数中,

  • 我使用 e.key == 'Escape' 作为我的 if() 声明的条件。

成功了。

出于某种我懒得去理解的原因,Enter 似乎可以在 onKeyPress 上工作,而 Escape 却不行't.

您将通过以下方式获得关键代码:

const code = event.keyCode || event.which;

class App extends React.Component {
    state={code:''};
   
    onKeyPress(event) {
     const code = event.keyCode || event.which;  
     this.setState({code})
    }
  
    render() {
      return (
        <div>
         <input onKeyPress={this.onKeyPress.bind(this)} />
         <span> Key Code :  {this.state.code}</span>
        </div>
        
      )
    }
  
}

ReactDOM.render(<App />, document.querySelector('section'));
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>
 <section />

 function useKeyPress(keys, onPress) {
  keys = keys.split(' ').map((key) => key.toLowerCase())
  const isSingleKey = keys.length === 1
  const pressedKeys = useRef([])

  const keyIsRequested = (key) => {
    key = key.toLowerCase()
    return keys.includes(key)
  }

  const addPressedKey = (key) => {
    key = key.toLowerCase()
    const update = pressedKeys.current.slice()
    update.push(key)
    pressedKeys.current = update
  }

  const removePressedKey = (key) => {
    key = key.toLowerCase()
    let update = pressedKeys.current.slice()
    const index = update.findIndex((sKey) => sKey === key)
    update = update.slice(0, index)
    pressedKeys.current = update
  }

  const downHandler = ({ key }) => {
    const isKeyRequested = keyIsRequested(key)
    if (isKeyRequested) {
      addPressedKey(key)
    }
  }

  const upHandler = ({ key }) => {
    const isKeyRequested = keyIsRequested(key)
    if (isKeyRequested) {
      if (isSingleKey) {
        pressedKeys.current = []
        onPress()
      } else {
        const containsAll = keys.every((i) => pressedKeys.current.includes(i))
        removePressedKey(key)
        if (containsAll) {
          onPress()
        }
      }
    }
  }

  useEffect(() => {
    window.addEventListener('keydown', downHandler)
    window.addEventListener('keyup', upHandler)
    return () => {
      window.removeEventListener('keydown', downHandler)
      window.removeEventListener('keyup', upHandler)
    }
  }, [])
}

这样使用:

function testUseKeyPress() {
 const onPressSingle = () => {
    console.log('onPressSingle!')
  }
  const onPressMulti = () => {
    console.log('onPressMulti!')
  }

  useKeyPress('a', onPressSingle)
  useKeyPress('shift h', onPressMulti)
}