如何在 sapui5 上验证表单（不要取空值）

Question

我的表格

 var oSimpleForm = new sap.ui.layout.form.SimpleForm({
                maxContainerCols: 2,
                content:[
                    new sap.ui.core.Title({text:"Employee"}),
                    new sap.ui.commons.Label({text:"Emp No",required:true}),
                    new sap.ui.commons.TextField({value:"",}),
                    new sap.ui.commons.Label({text:"First Name"}),
                    new sap.ui.commons.TextField({value:"",required: true}),
                    new sap.ui.commons.Label({text:"Last Name"}),
                    new sap.ui.commons.TextField({value:"",required: true}),
                    new sap.ui.commons.Label({text:"Street"}),
                    new sap.ui.commons.TextField({value:"",required: true}),
                    new sap.ui.commons.Label({text:"Country"}),
                    new sap.ui.commons.TextField({value:"",required: true}),
                    new sap.ui.commons.Label({text:"City"}),
                    new sap.ui.commons.TextField({value:"",required: true})

                ]

            });                
            oCreateDialog.addContent(oSimpleForm);
            oCreateDialog.addButton(
                new sap.ui.commons.Button({
                    text: "Submit", 
                    press: function() {
                    //validate input data not null
                     }
                })
            );

这是一个简单的表格，需要一些输入 data.My 问题是 -- 单击提交按钮时，我如何验证输入数据或在提交时没有数据字段应为空...

谢谢

Answer 1

function() {
  // get the content (as array)
  var content = oSimpleForm.getContent();
  // check every single control
  for (var i in content) {
    var control = content[i];
    // check control only if it has the function getValue
    // a rather primitive way to filter the TextFields
    if(control.getValue) {
      // check the value on empty text
      if(control.getValue() === "") {
        // do whatever you want to show the user he has to provide more input
        alert("empty value found");
      }
    }
  }
}

只提醒一次：

function() {
  var content = oSimpleForm.getContent();
  // assume all controls are valid, if one is invalid this flag is set to false
  var allValid = true;
  for (var i in content) {
    var control = content[i];
    // in case one control was invalid the variable allValid has been set to false
    if(allValid && control.getValue && control.getValue() === "") {
      allValid = false;
      // stop the for-loop
      break;
    }
  }
  if(!allValid) {
    alert("empty value found");
  }
}

如何在 sapui5 上验证表单（不要取空值）

how to validate form(do not take null value) on sapui5

sapui5