为什么 Mockery return demeter_getMyClass 而不是 MyClass?

Why does Mockery return demeter_getMyClass instead of MyClass?

我尝试模拟多个方法调用。如前所述 in the documentation,测试以下方法调用:

$object->foo()->bar()->zebra()->alpha()->selfDestruct();

我们可以使用下面这段代码:

$mock = \Mockery::mock('CaptainsConsole');
$mock->shouldReceive('foo->bar->zebra->alpha->selfDestruct')->andReturn('Ten!');

所以,我实现了它:

public function testProcessPayment()
{
    $offerPayment =  m::mock('MyApp\Model\Entity\OfferPayment');

    $paymentTransaction = m::mock('MyApp\Model\Entity\PaymentTransaction');
    $paymentTransaction->shouldReceive('getOfferPayment->getOffer')->andReturn($offerPayment);

    $transactionManager = new TransactionManager();
    $transactionManager->processPayment($paymentTransaction);

    $this->assertInstanceOf('Offer', $paymentTransaction->getOfferPayment()->getOffer());
}

相关class:

class TransactionManager
{
    public function processPayment(PaymentTransaction $paymentTransaction) {
        $itemGroupEntity = $paymentTransaction->getOfferPayment()->getOffer();
    }
}

我得到:

Return value of Mockery_3_MyApp_Model_Entity_PaymentTransaction::getOfferPayment() must be an instance of MyApp\Model\Entity\OfferPayment, instance of Mockery_4__demeter_getOfferPayment returned


getOfferPayment 和 getOffer 的实现:

public function getOfferPayment() : OfferPayment
{
    return $this->offerPayment;
}


public function getOffer() : Offer
{
    return $this->offer;
}

在这种情况下,Mockery 不支持return type declarations。 这个问题可以通过 删除 return getter 的类型声明 来解决:

public function getOfferPayment()
{
    return $this->offerPayment;
}


public function getOffer()
{
    return $this->offer;
}