对任何对象 Swift 3 的数组进行排序

Question

我正在尝试对 anyobject 的数组进行排序，但无法 it.I 从 Parse 数据库中以 AnyObject 格式获取一些数据。根据以下数据，我想按 "NAME" 对这个 AnyObject 数组进行排序。下面是我的代码 -

  let sortedArray = (myArray as! [AnyObject]).sorted(by: { (dictOne, dictTwo) -> Bool in
                                                            let d1 = dictOne["NAME"]! as AnyObject; // this line gives error "Ambiguous use of subscript"
                                                            let d2 = dictTwo["NAME"]! as AnyObject; // this line gives error "Ambiguous use of subscript"

                                                            return d1 < d2
                                                        })

myArray 看起来像这样 -

 {
            LINK = "www.xxx.com";
            MENU = Role;
            "MENU_ID" = 1;
            NAME = "A Name";
            SUBMENU = "XXX";
            "Training_ID" = 2;
        },
            {
            LINK = "www.xyz.com";
            MENU = Role;
            "MENU_ID" = 2;
            NAME = "B name";
            SUBMENU = "jhjh";
            "Training_ID" = 6;
        },
            {
            LINK = "www.hhh.com";
            MENU = Role;
            "MENU_ID" = 3;
            NAME = "T name";
            SUBMENU = "kasha";
            "Training_ID" = 7;
        },
            {
            LINK = "www.kadjk.com";
            MENU = Role;
            "MENU_ID" = 5;
            NAME = "V name";
            SUBMENU = "ksdj";
            "Training_ID" = 1;
        },
            {
            LINK = "www.ggg.com";
            MENU = Role;
            "MENU_ID" = 4;
            NAME = "K name";
            SUBMENU = "idiot";
            "Training_ID" = 8;
        },
            {
            LINK = "www.kkk.com";
            MENU = Role;
            "MENU_ID" = 6;
            NAME = "s name";
            SUBMENU = "BOM/ABOM/BSM";
            "Training_ID" = 12;
        }

如有任何帮助，我们将不胜感激。谢谢！

Answer 1

为什么要将数组转换为 [AnyObject] 而不是将数组转换为 [[String:Any]] 意味着 Array of Dictionary 并告诉编译器数组包含 Dictionary 作为对象。

if let array = myArray as? [[String:Any]] {
   let sortedArray = array.sorted(by: { [=10=]["NAME"] as! String < ["NAME"] as! String })
}

注意： 当你在数组的每个字典中有 NAME 键和 String 值时，我已经用下标强制包装它。

Answer 2

它不是 [AnyObject]（I-have-no-idea 的数组），它是字典数组 [[String:Any]]。更具体地说，这解决了错误。

在Swift3中编译器必须知道所有下标对象的具体类型

let sortedArray = (myArray as! [[String:Any]]).sorted(by: { (dictOne, dictTwo) -> Bool in
                                         let d1 = dictOne["NAME"]! as String
                                         let d2 = dictTwo["NAME"]! as String

                                         return d1 < d2
                                     })

Answer 3

如果需要可以使用下面的功能

//function to sort requests
func sortRequests(dataToSort: [[String:Any]]) -> [[String:Any]] {
    print("i am sorting the requests...")
    var returnData = [[String:Any]]()
    returnData = dataToSort
    returnData.sort{
            let created_date0 = [=10=]["date"] as? Double ?? 0.0
            let created_date1 = ["date"] as? Double ?? 0.0
            return created_date0 > created_date1
    }
    return returnData
}

对任何对象 Swift 3 的数组进行排序

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