如何根据 SQL 中的一些条件汇总

Question

我有一个这样的数据table：

QuestionID    UserName    UserWeightingForQuestion    AnswerGivenForQuestion    Metric
1             A           1.50                        1                         ToBeCalculated
1             B           1.00                        2                         ToBeCalculated
1             C           1.80                        3                         ToBeCalculated
1             D           1.20                        1                         ToBeCalculated
1             E           1.40                        2                         ToBeCalculated
2             A           1.20                        2                         ToBeCalculated
2             B           1.20                        2                         ToBeCalculated
2             C           1.10                        4                         ToBeCalculated
2             D           1.20                        5                         ToBeCalculated
...

对于每个问题组，我想用定义如下所示的计算值填充Metric列下的每个单元格：

Metric_For_User_A_For_QuestionID_X = SUM(Weights_With_The_Answer_Similar_To_What_Is_Given_By_User_A_In_QuestionID_Group = X) / DISTINCT(All_WEeights_In_One_QuestionID_Group = X)

具体来说，

Metric_For_User_A_For_QuestionID_1 = SUM(1.50+1.20)/(1.50+1.00+1.80+1.20+1.40)
Metric_For_User_B_For_QuestionID_1 = SUM(1.00+1.40)/(1.50+1.00+1.80+1.20+1.40)
Metric_For_User_C_For_QuestionID_1 = SUM(1.80)/(1.50+1.00+1.80+1.20+1.40)
Metric_For_User_D_For_QuestionID_1 = SUM(1.50+1.20)/(1.50+1.00+1.80+1.20+1.40)
Metric_For_User_E_For_QuestionID_1 = SUM(1.00+1.40)/(1.50+1.00+1.80+1.20+1.40)

对于QuestionID group = 2，我想重复上面的过程。例如，

Metric_For_User_A_For_QuestionID_2 = SUM(1.20+1.20)/(1.20+1.10)

我是 SQL 的新手，我相信 OVER 或某种聚合函数可以用来实现这个（？）如果这种计算在 SQL，有 SQL 专业知识的人可以建议我一种方法来实现我正在尝试计算的结果。

原始 table 有大约 7000 万行，我正在使用 SQL 服务器。非常感谢您的建议和回答！

Answer 1

您可以使用 SUM window 函数来执行此操作。

select t.*,
sum(UserWeightingForQuestion) over(partition by questionID,AnswerGivenForQuestion)
/sum(UserWeightingForQuestion) over(partition by questionID) as metric
from tablename t

sum(UserWeightingForQuestion) over(partition by questionID) 获取每个问题 ID
sum(UserWeightingForQuestion) over(partition by questionID,AnswerGivenForQuestion) 对每个问题 ID

编辑：要对分母中每个问题 ID 的 distinct 权重求和，请使用

select t.*,
sum(UserWeightingForQuestion) over(partition by questionID,AnswerGivenForQuestion)
/(select sum(distinct UserWeightingForQuestion) from tablename where t.questionID=questionID) as metric
from tablename t

Answer 2

declare @quest table(QuestionID int
                     , UserName varchar(20)
                     , UserWeightingForQuestion decimal(10,2)
                     , AnswerGivenForQuestion int);
insert into @quest values
(1,'A',1.50,1),(1,'B',1.00,2),(1,'C',1.80,3),(1,'D',1.20,1),
(1,'E',1.40,2),(2,'A',1.20,2),(2,'B',1.20,2),(2,'C',1.10,4),(2,'D',1.20,5);

基本上你做了两个分区，一个按 QuestionID 和 AnswerGivenForQuestion，另一个按 QuestionID。

WITH CALC AS
(
    SELECT Q2.QuestionID, Q2.UserName, 
           SUM(UserWeightingForQuestion) OVER (PARTITION BY QuestionID, AnswerGivenForQuestion) AS Weight,
           (SELECT SUM(DISTINCT Q1.UserWeightingForQuestion)
            FROM @quest Q1
            WHERE Q1.QuestionID = Q2.QuestionID) AS AllWeights
    FROM @quest Q2
)
SELECT QuestionID, UserName, Weight, AllWeights, 
       CAST(Weight / AllWeights AS DECIMAL(18,2)) as Metric
FROM CALC
ORDER BY QuestionID, UserName;

+------------+----------+--------+------------+--------+
| QuestionID | UserName | Weight | AllWeights | Metric |
+------------+----------+--------+------------+--------+
|      1     |     A    |  2,70  |    6,90    |  0,39  |
|      1     |     B    |  2,40  |    6,90    |  0,35  |
|      1     |     C    |  1,80  |    6,90    |  0,26  |
|      1     |     D    |  2,70  |    6,90    |  0,39  |
|      1     |     E    |  2,40  |    6,90    |  0,35  |
+------------+----------+--------+------------+--------+
|      2     |     A    |  2,40  |    2,30    |  1,04  |
|      2     |     B    |  2,40  |    2,30    |  1,04  |
|      2     |     C    |  1,10  |    2,30    |  0,48  |
|      2     |     D    |  1,20  |    2,30    |  0,52  |
+------------+----------+--------+------------+--------+

如何根据 SQL 中的一些条件汇总

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