ArrayList 模拟队列 - Java
ArrayList to emulate a queue - Java
我想在 Java 中使用 ArrayList 并将其实现为队列。使用 queue.add("element")
添加到队列应该相当容易。虽然,删除弹出项目有点棘手。我想到的方法如下:
public String pop(){
String s = queue.get(0);
queue.remove(0);
queue.trimToSize();
return s;
}
这是正确的方法吗?下次我调用 pop() 方法时是否会获取队列的下一个元素?
如果您确实需要使用 ArrayList
,remove()
已经可以满足您的所有需求。您应该能够仅使用 add()
和 remove(0)
来实现队列。您的 pop()
方法可以实现为:
public String pop() {
return queue.remove(0);
}
remove
public E remove(int index)
Removes the element at the specified position in this list. Shifts any subsequent elements to the left (subtracts one from their indices).
Returns: the element that was removed from the list
不过,正如其他人所建议的那样,ArrayDeque
更适合队列。
尝试下面提到的使用 ArrayDeque 的实现
import java.util.ArrayDeque;
import java.util.Collection;
import java.util.Iterator;
public class QueueImpl<E>
{
private ArrayDeque<E> arrayDeque;
/**
* Constructs an empty array deque with an initial capacity sufficient to
* hold 16 elements.
**/
public QueueImpl()
{
arrayDeque = new ArrayDeque<E>();
}
/**
* Constructs a deque containing the elements of the specified collection,
* in the order they are returned by the collection's iterator.
**/
public QueueImpl(Collection<? extends E> c)
{
arrayDeque = new ArrayDeque<E>(c);
}
/**
* Constructs an empty array deque with an initial capacity sufficient to
* hold the specified number of elements.
**/
public QueueImpl(int numElements)
{
arrayDeque = new ArrayDeque<E>(numElements);
}
/** Inserts the specified element at the tail of this queue. **/
public boolean add(E e)
{
return arrayDeque.add(e);
}
/** Atomically removes all of the elements from this queue. **/
public void clear()
{
arrayDeque.clear();
}
/** Returns true if this queue contains the specified element. **/
public boolean contains(Object o)
{
return arrayDeque.contains(o);
}
/** Returns an iterator over the elements in this queue in proper sequence. **/
public Iterator<E> iterator()
{
return arrayDeque.iterator();
}
/**
* Inserts the specified element at the tail of this queue if it is possible
* to do so immediately without exceeding the queue's capacity, returning
* true upon success and false if this queue is full.
**/
public boolean offer(E e)
{
return arrayDeque.offer(e);
}
/**
* Retrieves, but does not remove, the head of this queue, or returns null
* if this queue is empty.
**/
public E peek()
{
return arrayDeque.peek();
}
/**
* Retrieves and removes the head of this queue, or returns null if this
* queue is empty.
**/
public E poll()
{
return arrayDeque.poll();
}
/**
* Removes a single instance of the specified element from this queue, if it
* is present.
**/
public boolean remove(Object o)
{
return arrayDeque.remove(o);
}
/** Returns the number of elements in this queue. **/
public int size()
{
return arrayDeque.size();
}
/**
* Returns an array containing all of the elements in this queue, in proper
* sequence.
**/
public Object[] toArray()
{
return arrayDeque.toArray();
}
/**
* Returns an array containing all of the elements in this queue, in proper
* sequence; the runtime type of the returned array is that of the specified
* array.
**/
public <T> T[] toArray(T[] a)
{
return arrayDeque.toArray(a);
}
/** Returns a string representation of this collection. **/
public String toString()
{
return arrayDeque.toString();
}
/** Inserts the specified element at the front of this deque. **/
public void addFirst(E e)
{
arrayDeque.addFirst(e);
}
/** Inserts the specified element at the end of this deque. **/
public void addLast(E e)
{
arrayDeque.addLast(e);
}
/** Retrieves, but does not remove, the first element of this deque. **/
public void getFirst()
{
arrayDeque.getFirst();
}
/** Retrieves, but does not remove, the last element of this deque. **/
public void getLast()
{
arrayDeque.getLast();
}
/** Inserts the specified element at the front of this deque. **/
public boolean offerFirst(E e)
{
return arrayDeque.offerFirst(e);
}
/** Inserts the specified element at the end of this deque. **/
public boolean offerLast(E e)
{
return arrayDeque.offerLast(e);
}
/**
* Retrieves, but does not remove, the first element of this deque, or
* returns null if this deque is empty.
**/
public E peekFirst()
{
return arrayDeque.peekFirst();
}
/**
* Retrieves, but does not remove, the last element of this deque, or
* returns null if this deque is empty.
**/
public E peekLast()
{
return arrayDeque.peekLast();
}
public static void main(String... arg)
{
QueueImpl<Integer> arrayDeque = new QueueImpl<Integer>();
arrayDeque.add(300);
arrayDeque.add(200);
arrayDeque.add(600);
arrayDeque.add(-400);
arrayDeque.add(240);
System.out.println("the elements of the arrayDeque is ");
Iterator<Integer> itr = arrayDeque.iterator();
while (itr.hasNext())
{
System.out.print(itr.next() + "\t");
}
System.out.println();
arrayDeque.offer(600);
arrayDeque.offer(700);
arrayDeque.offerFirst(3);
arrayDeque.offerLast(10);
System.out.println("the peak element of the arrayDeque is(by peeking) " + arrayDeque.peek());
System.out.println("the peak element of the arrayDeque is(by polling) " + arrayDeque.poll());
System.out.println("the last element of arrayDeque is (peeking)" + arrayDeque.peekLast());
System.out.println("element 300 removed " + arrayDeque.remove(300));
System.out.println("the arrayDeque contains 400 :" + arrayDeque.contains(400));
System.out.println("the arrayDeque contains 600 :" + arrayDeque.contains(600));
System.out.println("the size of the arrayDeque is " + arrayDeque.size());
System.out.println(arrayDeque);
}
}
结果:
the elements of the arrayDeque is
300 200 600 -400 240
the peak element of the arrayDeque is(by peeking) 3
the peak element of the arrayDeque is(by polling) 3
the last element of arrayDeque is (peeking)10
element 300 removed true
the arrayDeque contains 400 :false
the arrayDeque contains 600 :true
the size of the arrayDeque is 7
[200, 600, -400, 240, 600, 700, 10]
我想在 Java 中使用 ArrayList 并将其实现为队列。使用 queue.add("element")
添加到队列应该相当容易。虽然,删除弹出项目有点棘手。我想到的方法如下:
public String pop(){
String s = queue.get(0);
queue.remove(0);
queue.trimToSize();
return s;
}
这是正确的方法吗?下次我调用 pop() 方法时是否会获取队列的下一个元素?
如果您确实需要使用 ArrayList
,remove()
已经可以满足您的所有需求。您应该能够仅使用 add()
和 remove(0)
来实现队列。您的 pop()
方法可以实现为:
public String pop() {
return queue.remove(0);
}
remove
public E remove(int index)
Removes the element at the specified position in this list. Shifts any subsequent elements to the left (subtracts one from their indices).
Returns: the element that was removed from the list
不过,正如其他人所建议的那样,ArrayDeque
更适合队列。
尝试下面提到的使用 ArrayDeque 的实现
import java.util.ArrayDeque;
import java.util.Collection;
import java.util.Iterator;
public class QueueImpl<E>
{
private ArrayDeque<E> arrayDeque;
/**
* Constructs an empty array deque with an initial capacity sufficient to
* hold 16 elements.
**/
public QueueImpl()
{
arrayDeque = new ArrayDeque<E>();
}
/**
* Constructs a deque containing the elements of the specified collection,
* in the order they are returned by the collection's iterator.
**/
public QueueImpl(Collection<? extends E> c)
{
arrayDeque = new ArrayDeque<E>(c);
}
/**
* Constructs an empty array deque with an initial capacity sufficient to
* hold the specified number of elements.
**/
public QueueImpl(int numElements)
{
arrayDeque = new ArrayDeque<E>(numElements);
}
/** Inserts the specified element at the tail of this queue. **/
public boolean add(E e)
{
return arrayDeque.add(e);
}
/** Atomically removes all of the elements from this queue. **/
public void clear()
{
arrayDeque.clear();
}
/** Returns true if this queue contains the specified element. **/
public boolean contains(Object o)
{
return arrayDeque.contains(o);
}
/** Returns an iterator over the elements in this queue in proper sequence. **/
public Iterator<E> iterator()
{
return arrayDeque.iterator();
}
/**
* Inserts the specified element at the tail of this queue if it is possible
* to do so immediately without exceeding the queue's capacity, returning
* true upon success and false if this queue is full.
**/
public boolean offer(E e)
{
return arrayDeque.offer(e);
}
/**
* Retrieves, but does not remove, the head of this queue, or returns null
* if this queue is empty.
**/
public E peek()
{
return arrayDeque.peek();
}
/**
* Retrieves and removes the head of this queue, or returns null if this
* queue is empty.
**/
public E poll()
{
return arrayDeque.poll();
}
/**
* Removes a single instance of the specified element from this queue, if it
* is present.
**/
public boolean remove(Object o)
{
return arrayDeque.remove(o);
}
/** Returns the number of elements in this queue. **/
public int size()
{
return arrayDeque.size();
}
/**
* Returns an array containing all of the elements in this queue, in proper
* sequence.
**/
public Object[] toArray()
{
return arrayDeque.toArray();
}
/**
* Returns an array containing all of the elements in this queue, in proper
* sequence; the runtime type of the returned array is that of the specified
* array.
**/
public <T> T[] toArray(T[] a)
{
return arrayDeque.toArray(a);
}
/** Returns a string representation of this collection. **/
public String toString()
{
return arrayDeque.toString();
}
/** Inserts the specified element at the front of this deque. **/
public void addFirst(E e)
{
arrayDeque.addFirst(e);
}
/** Inserts the specified element at the end of this deque. **/
public void addLast(E e)
{
arrayDeque.addLast(e);
}
/** Retrieves, but does not remove, the first element of this deque. **/
public void getFirst()
{
arrayDeque.getFirst();
}
/** Retrieves, but does not remove, the last element of this deque. **/
public void getLast()
{
arrayDeque.getLast();
}
/** Inserts the specified element at the front of this deque. **/
public boolean offerFirst(E e)
{
return arrayDeque.offerFirst(e);
}
/** Inserts the specified element at the end of this deque. **/
public boolean offerLast(E e)
{
return arrayDeque.offerLast(e);
}
/**
* Retrieves, but does not remove, the first element of this deque, or
* returns null if this deque is empty.
**/
public E peekFirst()
{
return arrayDeque.peekFirst();
}
/**
* Retrieves, but does not remove, the last element of this deque, or
* returns null if this deque is empty.
**/
public E peekLast()
{
return arrayDeque.peekLast();
}
public static void main(String... arg)
{
QueueImpl<Integer> arrayDeque = new QueueImpl<Integer>();
arrayDeque.add(300);
arrayDeque.add(200);
arrayDeque.add(600);
arrayDeque.add(-400);
arrayDeque.add(240);
System.out.println("the elements of the arrayDeque is ");
Iterator<Integer> itr = arrayDeque.iterator();
while (itr.hasNext())
{
System.out.print(itr.next() + "\t");
}
System.out.println();
arrayDeque.offer(600);
arrayDeque.offer(700);
arrayDeque.offerFirst(3);
arrayDeque.offerLast(10);
System.out.println("the peak element of the arrayDeque is(by peeking) " + arrayDeque.peek());
System.out.println("the peak element of the arrayDeque is(by polling) " + arrayDeque.poll());
System.out.println("the last element of arrayDeque is (peeking)" + arrayDeque.peekLast());
System.out.println("element 300 removed " + arrayDeque.remove(300));
System.out.println("the arrayDeque contains 400 :" + arrayDeque.contains(400));
System.out.println("the arrayDeque contains 600 :" + arrayDeque.contains(600));
System.out.println("the size of the arrayDeque is " + arrayDeque.size());
System.out.println(arrayDeque);
}
}
结果:
the elements of the arrayDeque is
300 200 600 -400 240
the peak element of the arrayDeque is(by peeking) 3
the peak element of the arrayDeque is(by polling) 3
the last element of arrayDeque is (peeking)10
element 300 removed true
the arrayDeque contains 400 :false
the arrayDeque contains 600 :true
the size of the arrayDeque is 7
[200, 600, -400, 240, 600, 700, 10]