Functor -> 必须调用对非静态成员函数的引用

Question

我有一个 class 我试图指向其成员函数，问题是我不断收到此错误 reference to non-static member function must be called 根据我的理解，需要指向一个成员函数。问题是，当我尝试使用 this 解决方案时，编译器会抱怨，因为 there is no viable conversion from 'void (Foo::*) (const List&) to std::function<void (const List &)>

这是我的 Foo class:

class Foo {
public:
  int Run( int port);
  void HandleRequest(HTTPServerRequest* request);

private:
    int num_ports;
    void callback_method(const List& );

};  //class Foo

void Foo::HandleRequest(HTTPServerRequest* request){
std::function<void (const List&)> functor = callback_method;
}

Answer 1

你可以这样做：

void Foo::HandleRequest(HTTPServerRequest* request){
    std::function<void (const List&)> functor =
        std::bind(&Foo::callback_method, this, std::placeholders::_1);
}

或：

void Foo::HandleRequest(HTTPServerRequest* request){
    std::function<void (const List&)> functor = 
        [this](const List& list){callback_method(list);};
}

Functor -> 必须调用对非静态成员函数的引用

Functor -> reference to non-static member function must be called

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function

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