在 Android Nougat 上拍摄照片后，BitmapFactory 无法从 Uri 解码位图

Question

我尝试拍照然后使用照片。这是我做的。

我的设备是 Nexus 6P (Android 7.1.1).

首先，我创建了一个 Uri:

Uri mPicPath = UriUtil.fromFile(this, UriUtil.createTmpFileForPic());
//Uri mPicPath = UriUtil.fromFile(this, UriUtil.createFileForPic());

然后，我开始 Intent：

Intent intent = ActivityUtils.getTakePicIntent(mPicPath);
if (intent.resolveActivity(getPackageManager()) != null) {
    startActivityForResult(intent, RequestCode.TAKE_PIC);
}

最后，我在 onActivityResult 上处理了这个 Uri:

if (requestCode == RequestCode.TAKE_PIC) {
    if (resultCode == RESULT_OK && mPicPath != null) {
        Bitmap requireBitmap = BitmapFactory.decodeFile(mPicPath.getPath());
        //path is like this: /Download/Android/data/{@applicationId}/files/Pictures/JPEG_20170216_173121268719051242.jpg
        requireBitmap.recycle();//Here NPE was thrown.
    }
}

同时，这里是UriUtil：

public class UriUtil {

    public static File createFileForPic() throws IOException {
        String fileName = "JPEG_" + new SimpleDateFormat("yyyyMMdd_HHmmssSSS", Locale.getDefault()).format(new Date()) + ".jpg";
        File storageDic = SPApplication.getInstance().getExternalFilesDir(Environment.DIRECTORY_PICTURES);
        return new File(storageDic, fileName);
    }

    public static File createTmpFileForPic() throws IOException {
        String fileName = "JPEG_" + new SimpleDateFormat("yyyyMMdd_HHmmssSSS", Locale.getDefault()).format(new Date());
        File storageDic = SPApplication.getInstance().getExternalFilesDir(Environment.DIRECTORY_PICTURES);
        return File.createTempFile(fileName, ".jpg", storageDic);
    }

    public static Uri fromFile(@NonNull Context context, @NonNull File file) {
        if (context == null || file == null) {
            throw new RuntimeException("context or file can't be null");
        }
        if (ActivityUtils.requireSDKInt(Build.VERSION_CODES.N)) {
            return FileProvider.getUriForFile(context, BuildConfig.APPLICATION_ID + ".file_provider", file);
        } else {
            return Uri.fromFile(file);
        }
    }
}

和getTakePicIntent(Uri)：

public static Intent getTakePicIntent(Uri mPicPath) {
    Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
    intent.putExtra(MediaStore.EXTRA_OUTPUT, mPicPath);
    if (!ActivityUtils.requireSDKInt(Build.VERSION_CODES.KITKAT_WATCH)) {//in pre-KitKat devices, manually grant uri permission.
        List<ResolveInfo> resInfoList = SPApplication.getInstance().getPackageManager().queryIntentActivities(intent, PackageManager.MATCH_DEFAULT_ONLY);
        for (ResolveInfo resolveInfo : resInfoList) {
            String packageName = resolveInfo.activityInfo.packageName;
            SPApplication.getInstance().grantUriPermission(packageName, mPicPath, Intent.FLAG_GRANT_WRITE_URI_PERMISSION | Intent.FLAG_GRANT_READ_URI_PERMISSION);
        }
    } else {
        intent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
        intent.addFlags(Intent.FLAG_GRANT_WRITE_URI_PERMISSION);
    }
    return intent;
}

和requireSDKInt：

public static boolean requireSDKInt(int sdkInt) {
    return Build.VERSION.SDK_INT >= sdkInt;
}

除 Android 牛轧糖 (7.x.x) 外，其他 Android API 均有效。即使提供了 'FileProvider'，'requireBitmap' 也总是返回为 'null'。

读取日志后，FileNotFoundException 从 BitmapFactory 抛出。就像：

BitmapFactory: Unable to decode stream: java.io.FileNotFoundException: /Download/Android/data/{@applicationId}/files/Pictures/JPEG_20170216_1744551601425984925.jpg (No such file or directory)

好像都明白了，但还是没看懂。

怎么可能？明明我创建了一个File！我该如何解决？有什么想法吗？

Answer 1

看起来很像 {@applicationID} 实际上应该包含您的应用程序的包 ID。实际上，该文件夹不存在，因此无法写入或读取该文件。看起来像 SPApplication.getInstance().getExternalFilesDir(Environment.DIRECTORY_PICTURES);未返回有效路径。

Answer 2

Nougat 和以前的更新正在使用此代码

要从牛轧糖中的数据库获取真实路径，请使用此函数并将您在数据字段中获取的 uri 传递到 onActivityResult 中，然后从路径中获取文件。

    public String getPath(Uri uri) {
    Cursor cursor = getContentResolver().query(uri, null, null, null, null);
    cursor.moveToFirst();
    String document_id = cursor.getString(0);
    document_id = document_id.substring(document_id.lastIndexOf(":") + 1);
    cursor.close();

    cursor = getContentResolver().query(
            android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI,
            null, MediaStore.Images.Media._ID + " = ? ", new String[]{document_id}, null);
    cursor.moveToFirst();
    String path = cursor.getString(cursor.getColumnIndex(MediaStore.Images.Media.DATA));
    cursor.close();

    return path;
}

Answer 3

试试这个函数，也许你可以从中获取路径。这对我有用

@TargetApi(Build.VERSION_CODES.KITKAT)
public static String getRealPathFromURI_API19(Context context, Uri uri) {

    if (HelperFunctions.isExternalStorageDocument(uri)) {

        // ExternalStorageProvider
        final String docId = DocumentsContract.getDocumentId(uri);
        final String[] split = docId.split(":");
        final String type = split[0];

        if ("primary".equalsIgnoreCase(type)) {
            return Environment.getExternalStorageDirectory() + "/"
                    + split[1];
        }
    } else if (HelperFunctions.isDownloadsDocument(uri)) {

        // DownloadsProvider

        final String id = DocumentsContract.getDocumentId(uri);
        final Uri contentUri = ContentUris.withAppendedId(
                Uri.parse("content://downloads/public_downloads"),
                Long.valueOf(id));

        return HelperFunctions.getDataColumn(context, contentUri, null, null);

    } else if (HelperFunctions.isMediaDocument(uri)) {


        final String docId = DocumentsContract.getDocumentId(uri);
        final String[] split = docId.split(":");
        final String type = split[0];

        Uri contentUri = null;
        if ("image".equals(type)) {
            contentUri = MediaStore.Images.Media.EXTERNAL_CONTENT_URI;
        } else if ("video".equals(type)) {
            contentUri = MediaStore.Video.Media.EXTERNAL_CONTENT_URI;
        } else if ("audio".equals(type)) {
            contentUri = MediaStore.Audio.Media.EXTERNAL_CONTENT_URI;
        }

        final String selection = "_id=?";
        final String[] selectionArgs = new String[]{split[1]};

        return HelperFunctions.getDataColumn(context, contentUri, selection,
                selectionArgs);


    } else if ("content".equalsIgnoreCase(uri.getScheme())) {

        // Return the remote address
        if (HelperFunctions.isGooglePhotosUri(uri))
            return uri.getLastPathSegment();

        return HelperFunctions.getDataColumn(context, uri, null, null);
    }
    // File
    else if ("file".equalsIgnoreCase(uri.getScheme())) {
        return uri.getPath();
    }

    return null;

}

这是我上面使用的静态函数 HelperFunction class。

 public class HelperFunction{
       /**
 * @param uri The Uri to check.
 * @return Whether the Uri authority is ExternalStorageProvider.
 */
public static boolean isExternalStorageDocument(Uri uri) {
    return "com.android.externalstorage.documents".equals(uri.getAuthority());
}

/**
 * @param uri The Uri to check.
 * @return Whether the Uri authority is DownloadsProvider.
 */
public static boolean isDownloadsDocument(Uri uri) {
    return "com.android.providers.downloads.documents".equals(uri.getAuthority());
}

/**
 * @param uri The Uri to check.
 * @return Whether the Uri authority is MediaProvider.
 */
public static boolean isMediaDocument(Uri uri) {
    return "com.android.providers.media.documents".equals(uri.getAuthority());
}



/**
 * @param uri
 *            The Uri to check.
 * @return Whether the Uri authority is Google Photos.
 */
public static boolean isGooglePhotosUri(Uri uri) {
    return "com.google.android.apps.photos.content".equals(uri
            .getAuthority());
}

}

Answer 4

你应该使用 FileProvider。您可以参考此 commit 进行必要的更改。

Answer 5

我试过你的代码。这是我尝试的示例。https://github.com/raghunandankavi2010/SamplesAndroid/tree/master/WhosebugTest。

看看这个博客https://commonsware.com/blog/2016/03/15/how-consume-content-uri.html

在博客 commonsware 中提到你不应该做 new File (mPicPath.getPath())。

相反，您应该在 onActivityResult

中使用以下内容

try {
       InputStream ims = getContentResolver().openInputStream(mPicPath);
       // just display image in imageview
       imageView.setImageBitmap(BitmapFactory.decodeStream(ims));
    } catch (FileNotFoundException e) {
            e.printStackTrace();
    }

还有 xml

 <external-files-path name="external_files" path="path" />

注意：它是您拥有的内容 uri。在我的 phone 上，我得到如下 uri。仅在 Nexus6p 上测试过。

content://com.example.raghu.Whosebugtest.fileProvider/external_files/Pictures/JPEG_20170424_161429691143693160.jpg

有关文件提供程序的更多信息https://developer.android.com/reference/android/support/v4/content/FileProvider.html

Answer 6

尝试Glide。

1. 添加Glide依赖到app/build.gradle

repositories {
   mavenCentral() // jcenter() works as well because it pulls from Maven Central
}

dependencies {
   compile 'com.github.bumptech.glide:glide:3.7.0'
   compile 'com.android.support:support-v4:19.1.0'
 }

2. 使用 Glide 加载图片

Glide.with(context).load(new File(uri.getPath())).placeholder(R.drawable.placeholder).into(imageView);

或

Glide.load(new File(uri.getPath())) // Uri of the picture
.transform(new CircleTransform(..))
.into(imageView);

在 Android Nougat 上拍摄照片后，BitmapFactory 无法从 Uri 解码位图

BitmapFactory can't decode a Bitmap from Uri after photos taken on Android Nougat

android

bitmap

android-camera-intent

android-fileprovider

android-7.0-nougat

Nougat 和以前的更新正在使用此代码