实现与 rational class(java) 类似的接口
Implementing comparable interface to rational class(java)
我是 Java 的初学者,这是我第一次使用 Comparable 界面。我不明白为什么在比较 r1 和 r2 时它总是返回零。有人可以向我解释我的代码有什么问题吗?谢谢。
public class Rational implements Comparable<Rational>{
private int num; //numerator
private int denom; //denominator
public Rational() {
num = 0;
denom = 1;
}
public Rational(int num, int denom) {
if(denom <=0 ){
throw new ArithmeticException("You cannot divide by a non-positive number");
}
this.num = num;
this.denom = denom;
}
//returns numerator of this rational number
public int getNum() {
return num;
}
//returns denominator of this rational number
public int getDenom() {
return denom;
}
public Rational add(Rational rhs) {
return new Rational(num*rhs.denom+rhs.num*denom, denom*rhs.denom);
}
public Rational subtract(Rational rhs) {
return new Rational(num*rhs.denom-rhs.num*denom, denom*rhs.denom);
}
public Rational multiply(Rational rhs) {
return new Rational(num*rhs.num, denom*rhs.denom);
}
public Rational divide(Rational rhs) {
return new Rational(num*rhs.denom, denom*rhs.num);
}
public String toString() {
String result;
if (num == 0)
result = "0";
else if(denom == 1)
result = num + "";
else
result = num + "/" + denom;
return result;
}
public int compareTo(Rational rhs){
double r1 = ((double) getNum()/getDenom());
double r2 = ((double)rhs.getNum() / rhs.getDenom());
return (int) (r1 - r2);
}
public static void main(String[] args) {
Rational r1 = new Rational(1, 2); // 1/2
Rational r2 = new Rational(3, 4); // 3/4
Rational result = r1.add(r2);
Rational result1 = r1.subtract(r2);
Rational result2 = r1.multiply(r2);
Rational result3 = r1.divide(r2);
System.out.println( "r1 + r2 = " + result + "\n" + "r1 - r2 = " + result1 + "\n" + "r1*r2 = "+ result2 + "\n" + "r1/r2 = " + result3 + "\n" + (r1.compareTo(r2)));
}
}
这个公式
return (int) (r1 - r2);
当 r1
和 r2
之间的差异小于 1
时, 产生零,这就是您正在测试的情况。
由于 class 的构造中两个分母都是正数,因此您可以 cross-multiply 并完全不使用除法进行减法:
long a = (long)getNum() * rhs.getDenom();
long b = (long)rhs.getNum() * getDenom();
return Long.compare(a, b);
使用long
避免乘法溢出。
我是 Java 的初学者,这是我第一次使用 Comparable 界面。我不明白为什么在比较 r1 和 r2 时它总是返回零。有人可以向我解释我的代码有什么问题吗?谢谢。
public class Rational implements Comparable<Rational>{
private int num; //numerator
private int denom; //denominator
public Rational() {
num = 0;
denom = 1;
}
public Rational(int num, int denom) {
if(denom <=0 ){
throw new ArithmeticException("You cannot divide by a non-positive number");
}
this.num = num;
this.denom = denom;
}
//returns numerator of this rational number
public int getNum() {
return num;
}
//returns denominator of this rational number
public int getDenom() {
return denom;
}
public Rational add(Rational rhs) {
return new Rational(num*rhs.denom+rhs.num*denom, denom*rhs.denom);
}
public Rational subtract(Rational rhs) {
return new Rational(num*rhs.denom-rhs.num*denom, denom*rhs.denom);
}
public Rational multiply(Rational rhs) {
return new Rational(num*rhs.num, denom*rhs.denom);
}
public Rational divide(Rational rhs) {
return new Rational(num*rhs.denom, denom*rhs.num);
}
public String toString() {
String result;
if (num == 0)
result = "0";
else if(denom == 1)
result = num + "";
else
result = num + "/" + denom;
return result;
}
public int compareTo(Rational rhs){
double r1 = ((double) getNum()/getDenom());
double r2 = ((double)rhs.getNum() / rhs.getDenom());
return (int) (r1 - r2);
}
public static void main(String[] args) {
Rational r1 = new Rational(1, 2); // 1/2
Rational r2 = new Rational(3, 4); // 3/4
Rational result = r1.add(r2);
Rational result1 = r1.subtract(r2);
Rational result2 = r1.multiply(r2);
Rational result3 = r1.divide(r2);
System.out.println( "r1 + r2 = " + result + "\n" + "r1 - r2 = " + result1 + "\n" + "r1*r2 = "+ result2 + "\n" + "r1/r2 = " + result3 + "\n" + (r1.compareTo(r2)));
}
}
这个公式
return (int) (r1 - r2);
当 r1
和 r2
之间的差异小于 1
时,产生零,这就是您正在测试的情况。
由于 class 的构造中两个分母都是正数,因此您可以 cross-multiply 并完全不使用除法进行减法:
long a = (long)getNum() * rhs.getDenom();
long b = (long)rhs.getNum() * getDenom();
return Long.compare(a, b);
使用long
避免乘法溢出。