如何在列表视图中隐藏同一用户消息的第二个用户名？

Question

我试着和 socket.io 聊天。我希望只有同一用户的消息的用户名字可见。

例如：

     Username | Message

item:  Hans:     hello         (first message with name of user)
item:            How are you?  (second message without username)
item:  Look:     Thanks, good!
item:            you?          (second message without username)

下面的代码时好时坏。在滚动列表视图时，有时同一用户的第二个用户名是可见的，其他时候是隐藏的。我怎样才能隐藏同一用户的用户的第二个名字和分隔符？

简单代码：

package com.example.seadog.fb_dialog;

import android.content.Context;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.BaseAdapter;
import android.widget.TextView;

import java.util.ArrayList;

public class MyBaseAdapter extends BaseAdapter {

    Context context;
    ArrayList<ListData> items = new ArrayList();
    LayoutInflater inflater;

    int id = 0;

    public MyBaseAdapter(Context context, ArrayList items) {
        this.context = context;
        this.items = items;
        inflater = LayoutInflater.from(this.context);
    }

    @Override
    public int getCount() {
        return items.size();
    }

    @Override
    public ListData getItem(int position) {
        return items.get(position);
    }

    @Override
    public long getItemId(int position) {
        return 0;
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        MyViewHolder mViewHolder;

        if (convertView == null) {
            convertView = inflater.inflate(R.layout.list_item, parent, false);
            mViewHolder = new MyViewHolder(convertView);
            convertView.setTag(mViewHolder);
        } else {
            mViewHolder = (MyViewHolder) convertView.getTag();
        }

        ListData currentListData = getItem(position);

        mViewHolder.Title.setText(currentListData.getTitle());
        mViewHolder.Desc.setText(currentListData.getDescription());

        if (id != currentListData.getID() || position == 0) {
            mViewHolder.Title.setVisibility(View.VISIBLE);
        }else{
            mViewHolder.Title.setVisibility(View.GONE);
        }

        id = currentListData.getID();

        return convertView;
    }

    private class MyViewHolder {
        TextView Title, Desc;

        public MyViewHolder(View item) {
            Title = (TextView) item.findViewById(R.id.txtitem);
            Desc = (TextView) item.findViewById(R.id.descitem);
        }
    }
}

Answer 1

您可以将其更改为：

@Override
public View getView(int position, View convertView, ViewGroup parent) {
    MyViewHolder mViewHolder;

    if (convertView == null) {
        convertView = inflater.inflate(R.layout.list_item, parent, false);
        mViewHolder = new MyViewHolder(convertView);
        convertView.setTag(mViewHolder);
    } else {
        mViewHolder = (MyViewHolder) convertView.getTag();
    }

    id = position > 0 ? getItem(position - 1).getID() : -1;

    ListData currentListData = getItem(position);

    mViewHolder.Title.setText(currentListData.getTitle());
    mViewHolder.Desc.setText(currentListData.getDescription());

    if (id == -1 && id != currentListData.getID()) {
        mViewHolder.Title.setVisibility(View.VISIBLE);
    } else {
        mViewHolder.Title.setVisibility(View.GONE);
    }

    return convertView;
}

您无法确定 getView() 是否会按顺序位置调用，例如在向上滚动时。

如何在列表视图中隐藏同一用户消息的第二个用户名？

How to hide a second name of user of message the same user in listview?

android

listview

livechat

socket.io

baseadapter