如何设置要查询的默认参数类型。当前为 body
How to set default paramType to query. current is body
如果我不设置paramType = "query",密码是body。怎么改?
@ApiOperation("登录")
@ApiImplicitParams({
@ApiImplicitParam(name = "account", value = "用户名或手机号码", paramType = "query"),
@ApiImplicitParam(name = "password", value = "密码")
})
@RequestMapping
public JR login(String account, String password) {
if (StringUtils.isEmpty(account) || StringUtils.isEmpty(password)) {
return JR.fail(2, "请填写完整信息");
}
User user = userRepository.findByAccountOrPhone(account, account);
if (user != null && StringUtils.md5(password).equals(user.getPassword())) {
ApiUtils.loginInfo(user, userRepository, true);
return JR.success(user);
}
return JR.fail(1, "账号或密码错误");
}
与其在 swagger
注释中设置它,不如在 method
中使用 @RequestParam
指定查询参数,如下所示:
@ApiOperation("登录")
@RequestMapping
public JR login(@RequestParam("account") String account, @RequestParam("password") String password) {
if (StringUtils.isEmpty(account) || StringUtils.isEmpty(password)) {
return JR.fail(2, "请填写完整信息");
}
User user = userRepository.findByAccountOrPhone(account, account);
if (user != null && StringUtils.md5(password).equals(user.getPassword())) {
ApiUtils.loginInfo(user, userRepository, true);
return JR.success(user);
}
return JR.fail(1, "账号或密码错误");
}
如果我不设置paramType = "query",密码是body。怎么改?
@ApiOperation("登录")
@ApiImplicitParams({
@ApiImplicitParam(name = "account", value = "用户名或手机号码", paramType = "query"),
@ApiImplicitParam(name = "password", value = "密码")
})
@RequestMapping
public JR login(String account, String password) {
if (StringUtils.isEmpty(account) || StringUtils.isEmpty(password)) {
return JR.fail(2, "请填写完整信息");
}
User user = userRepository.findByAccountOrPhone(account, account);
if (user != null && StringUtils.md5(password).equals(user.getPassword())) {
ApiUtils.loginInfo(user, userRepository, true);
return JR.success(user);
}
return JR.fail(1, "账号或密码错误");
}
与其在 swagger
注释中设置它,不如在 method
中使用 @RequestParam
指定查询参数,如下所示:
@ApiOperation("登录")
@RequestMapping
public JR login(@RequestParam("account") String account, @RequestParam("password") String password) {
if (StringUtils.isEmpty(account) || StringUtils.isEmpty(password)) {
return JR.fail(2, "请填写完整信息");
}
User user = userRepository.findByAccountOrPhone(account, account);
if (user != null && StringUtils.md5(password).equals(user.getPassword())) {
ApiUtils.loginInfo(user, userRepository, true);
return JR.success(user);
}
return JR.fail(1, "账号或密码错误");
}