SQL Not IN 查询正在花费时间与类似 table

Question

我有 2 个表假设 table_1 & table_2 table_1 有 56 列和 120 万条记录我的查询就像

table_1 喜欢

RollNumber | Subject | G         | Part | Status  
------------------------------------------------  
1          | 1       | 1         | 1    |  1  
1          | 1       | 1         | 2    |  1  
1          | 2       | 1         | 1    |  1  
1          | 2       | 1         | 2    |  5  
1          | 3       | 1         | 1    |  0  
1          | 3       | 1         | 2    |  1  
2          | 1       | 2         | 1    |  1  
2          | 1       | 2         | 2    |  1  
2          | 2       | 2         | 1    |  1  
2          | 2       | 2         | 2    |  1  
2          | 3       | 2         | 1    |  1  
2          | 3       | 2         | 2    |  1 
3          | 1       | 2         | 1    |  1  
3          | 1       | 2         | 2    |  1  
3          | 2       | 2         | 1    |  1  
3          | 2       | 2         | 2    |  1  
3          | 3       | 2         | 1    |  0  
3          | 3       | 2         | 2    |  1

我想要来自 table_1 的所有 RollNumber（按第 2 和第 3 列分组），其中任何状态为 0，但不希望状态也为 5（或非 1）的学生

我试过了

select * from table_1 as t1  
inner join table_2 as t2  
on  t1.column2 = t2.column2 and t1.column3 = t2.column3 and t1.column4 = t2.column4  
where t1.column1 not in  
     (select column1 from table_1 where status = 5)

这是我qhole查询的最内层查询
我也试过 EXCEPT 子句
两个查询执行时间太长

Answer 1

您可以使用 EXISTS 代替 NOT IN. 这会更快，因为会有 boolean 比较而不是 string 比较。

select * from table_1 as t1  
inner join table_2 as t2  
on t1.column1 = t2.column1 and t1.column2 = t2.column2 and t1.column3 = t2.column3  
where not EXISTS  
     (select 1 from table_1 where status = 5 and t1.column3 = table_1.column3)

Answer 2

尝试使用 NOT EXISTS 而不是 NOT IN

SELECT * 
FROM table_1 AS t1  
INNER JOIN table_2 AS t2  
ON t1.column1 = t2.column1 AND t1.column2 = t2.column2 AND t1.column3 = t2.column3  
WHERE NOT EXISTS(
                    SELECT 1
                    FROM table_1
                    WHERE status=5 AND column3=t1.column3
                                                           )

Answer 3

从 SQL Server 2008 开始，您可以使用 count() over() 计算给定组中具有特定值的总行数。

在这种情况下，您需要计算每组 status <> 1 的数量，并且只计算属于 0 组的 select 行。

select * from (
    select * , 
      count(case when status <> 1 then 1 end) over(partition by RollNumber, G) c
    from table_1
) t where c = 0

SQL Not IN 查询正在花费时间与类似 table

SQL Not IN query is taking time with similar table

sql

sql-server

join

self-join

notin