Objective-C

Question

我有一个 NSArray 字符串，我想将其放入单个 NSString 中，并在 objective-c.

中用多个分隔符分隔元素

例如数组看起来像这样。

["Mike", "Brother", "Sarah", "Sister", "Jane", "Sister"]

我希望它们在字符串中看起来像这样。

"Mike,Brother; Sarah,Sister; Jane,Sister"

即人和关系用逗号分隔，兄弟姐妹用分号分隔。

Answer 1

使用 appendFormat 的 for 循环将起作用：

BOOL first=YES;
NSMutableString *res = [NSMutableString string];
for (int i = 0 ; i+1 < array.length ; i+=2) {
    if (!first) {
        [res appendString:@"; "];
    } else {
        first = NO;
    }
    [res appendFormat:@"%@,%@", array[i], array[i+1]];
}

使用NSMutableString有助于避免创建临时对象。

当然这并不理想，因为数组中的项是相关的。您最好创建可以存储名称和关系的对象，这样您就不必将它们存储在平面数组的相邻元素中。

Answer 2

NSArray *input = [ @"Mike", @"Brother", @"Sarah", @"Sister", @"Jane", @"Sister" ];
NSMutableArray *nameSiblingPairs = [NSMutableArray array];

for (NSInteger i = 0; i < [input count]; i += 2)
    [nameSiblingPairs addObject:[NSString stringWithFormat:@"%@,%@", input[i], input[i + 1]]];

NSString *output = [nameSiblingPairs componentsJoinedByString:@"; "];

Answer 3

NSArray *array = @[@"Mike", @"Brother", @"Sarah", @"Sister", @"Jane", @"Sister"];
NSMutableArray* newArray = [[NSMutableArray alloc] init];
for (int i = 1; i<[array count]; i+=2){
  [newArray addObject: [NSString stringWithFormat:@"%@,%@", array[i-1],array[i]]];
}
NSString* s = [newArray componentsJoinedByString:@"; "];

Answer 4

试试这个：

- (NSString *)serialize:(NSArray *)array
{
    NSUInteger count = [array count];
    NSAssert(count % 2 == 0,  @"Array count must be even");
    NSString *result = @"";
    NSUInteger i = 0;
    for (i = 0; i < count / 2 + 2 ; i+=2) {
        NSString *temp = [NSString stringWithFormat:@"%@,%@",array[i], array[i+1]];

        result = [result stringByAppendingString:temp];
        if (i < count / 2) {
            result = [result stringByAppendingString:@"; "];
        }
    }
    return result;
}

Answer 5

这是一种更更好并且干净的方法

NSArray *input = [ @"Mike", @"Brother", @"Sarah", @"Sister", @"Jane", @"Sister" ];
NSMutableString *outputString = [NSMutableString string];
NSArray *delimiters = [@",", @"; "];

for(int i=0; i < outputString.count; ++ i) {

    [outputString appendString:[input objectAtIndex:i]];

    if (i < input.count - 1) {
        [outputString appendString:i % delimiters.count];
    }
}

取回数组

NSArray *array = [outputString componentsSeparatedByCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:@",; "]];

这是一个动态代码，您可以在其中添加 n 个分隔符

Answer 6

试试这个：

NSArray+Extension.h

@interface NSArray (Extension)
- (NSString *)componentsJoinedByStrings:(NSArray *)separatorStrings;
@end

NSArray+Extension.m

@implementation NSArray (Extension)

- (NSString *)componentsJoinedByStrings:(NSArray *)separatorStrings {
    NSMutableString *newString = [NSMutableString stringWithString:@""];
    for (NSInteger i = 0; i < [self count]; i += 1){
        NSMutableString *tempString = [NSString stringWithFormat:@"%@ %@", self[i], separatorStrings[i% [separatorStrings count]]];
        [newString appendString:tempString];
    }
    return newString
}

@end

Objective-C - NSArray 到具有多个分隔符的 NSString

Objective-C - NSArray to NSString with multiple delimiters

nsstring

nsarray

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