LuaSocket server:accept() 超时（TCP）

Question

问题

关注 LuaSocket Introduction 我设法获得了服务器运行。我还设法从客户端连接。但是，我注意到服务器脚本会冻结，直到 server:accept() 获得连接。

研究

LuaSocket Reference 指定：

Use the settimeout method or accept might block until another client shows up.

这甚至包含在示例代码中。但是，client:settimeout(10) 在 local client = server:accept() 之后调用，因此脚本在到达此点之前被阻止。

我读到这可以通过多线程解决，但这似乎有点夸张。

问题

如何使服务器脚本停止等待连接并继续前进？
如何防止 client:receive()（服务器端）和 tcp:receive()（客户端）出现类似问题（或者 client:settimeout(10) 负责）？

代码

服务器（来自LuaSocketIntroduction）

-- load namespace
local socket = require("socket")
-- create a TCP socket and bind it to the local host, at any port
local server = assert(socket.bind("*", 0))
-- find out which port the OS chose for us
local ip, port = server:getsockname()
-- print a message informing what's up
print("Please telnet to localhost on port " .. port)
print("After connecting, you have 10s to enter a line to be echoed")
-- loop forever waiting for clients
while 1 do
  -- wait for a connection from any client
  local client = server:accept()
  -- make sure we don't block waiting for this client's line
  client:settimeout(10)
  -- receive the line
  local line, err = client:receive()
  -- if there was no error, send it back to the client
  if not err then client:send(line .. "\n") end
  -- done with client, close the object
  client:close()
end

客户（关注 this answer）

local host, port = "127.0.0.1", 100
local socket = require("socket")
local tcp = assert(socket.tcp())

tcp:connect(host, port);
--note the newline below
tcp:send("hello world\n");

while true do
    local s, status, partial = tcp:receive()
    print(s or partial)
    if status == "closed" then break end
end
tcp:close()

Answer 1

您应该可以在调用 server:accept() 之前使用 server:timeout():

server:settimeout(2)
local client, err = server:accept()
print(client, err)

如果 2 秒内没有请求，这会为我打印 nil timeout。

LuaSocket server:accept() 超时（TCP）

LuaSocket server:accept() timeout (TCP)

lua

luasocket