数组初始化结构

Question

我有以下数据结构

struct single_t
{
    uint16_t i1 = 0;
    uint8_t i2 = 0;
    uint8_t i3 = 0;
};

struct mapping_t
{
    uint8_t n1;
    uint8_t n2;
    bool enable;
    uint n3;
    std::array<single_t, 32> map;
};

我想按以下方式初始化它们：

mapping_t m1 {
    3,                                  // n1
    254,                                // n2
    true,                               // enable
    5,                                  // n3

    // map
    // i1                   i2              i3
    {{
        {0x1000,            1,              8}
    }}
};

我可以确定 std::array<single_t, 32> map; 中的元素（在本例中为索引 1..31）被初始化为 0 还是类似于堆栈 int i; 中未初始化的变量？我的调试器显示它们为 0，但该实现是依赖于调试版本还是在标准中定义？

Answer 1

来自http://en.cppreference.com/w/cpp/language/aggregate_initialization

If the number of initializer clauses is less than the number of members or initializer list is completely empty, the remaining members are value-initialized. If a member of a reference type is one of these remaining members, the program is ill-formed.

值初始化的默认情况是用0初始化

见http://en.cppreference.com/w/cpp/language/value_initialization

The effects of value initialization are:

[...]

4) otherwise, the object is zero-initialized.

总结一下，你很好！

数组初始化结构

Array initialization with structures

c++

constructor

initializer-list

c++14