我怎样才能避免在 neo4j 中多次访问具有相同 属性 的节点？
how can i avoid visiting a node with same property more than once in neo4j?
我的 Cypher 查询：
MATCH p =(o:Order)-[r:seeks*2..8]->(o:Order)
WHERE o.Name="000093" AND ALL(x IN tail(nodes(p)) WHERE SINGLE(y IN tail(nodes(p)) WHERE x=y))
RETURN extract(n IN nodes(p)| n.Name) AS OrderID, extract(u IN nodes(p)| u.UserName) AS UserName,length(p), endNode(r[0])
ORDER BY length(p)
我想避免在路径中有具有相同 属性 值的节点，如何避免它们？
["000093","000090","000096","000097","000107","000091","000089","000093"]
["yunis","gio","Anhar","Jhon","**shakilbit**","xalima","**shakilbit**","yunis"]
所以，订单 0000107 和 000089 是由同一个用户名 shakilbit 下达的，有什么办法可以避免在同一路径下使用这些订单，谢谢！ NEO4J..据我所知，社区非常有帮助。
使用 APOC Procedures，您可能希望将您的集合作为一个集合（消除重复值）并比较大小。如果存在重复项，集合的大小将更小。
MATCH p =(o:Order)-[r:seeks*2..8]->(o:Order)
WHERE o.Name="000093" AND ALL(x IN tail(nodes(p)) WHERE SINGLE(y IN tail(nodes(p)) WHERE x=y))
WITH p, o, r, extract(u IN nodes(p)| u.UserName) AS UserName
// need to make some adjustments since first and last nodes are same
WHERE size(UserName) - 1 = size(apoc.coll.toSet(tail(UserName)))
RETURN extract(n IN nodes(p)| n.Name) AS OrderID, UserName, length(p), endNode(r[0])
ORDER BY length(p)
替代方法是在 UserName 集合上重复 ALL(x in tail...) WHERE single()... 谓词（或者在现有的 ALL() 谓词中包括此检查，尽管这可能很昂贵）。您可能想对每个进行 PROFILE，看看哪个性能更好。
我的 Cypher 查询：
MATCH p =(o:Order)-[r:seeks*2..8]->(o:Order)
WHERE o.Name="000093" AND ALL(x IN tail(nodes(p)) WHERE SINGLE(y IN tail(nodes(p)) WHERE x=y))
RETURN extract(n IN nodes(p)| n.Name) AS OrderID, extract(u IN nodes(p)| u.UserName) AS UserName,length(p), endNode(r[0])
ORDER BY length(p)
我想避免在路径中有具有相同 属性 值的节点，如何避免它们？
["000093","000090","000096","000097","000107","000091","000089","000093"]
["yunis","gio","Anhar","Jhon","**shakilbit**","xalima","**shakilbit**","yunis"]
所以，订单 0000107 和 000089 是由同一个用户名 shakilbit 下达的，有什么办法可以避免在同一路径下使用这些订单，谢谢！ NEO4J..据我所知，社区非常有帮助。
使用 APOC Procedures，您可能希望将您的集合作为一个集合（消除重复值）并比较大小。如果存在重复项，集合的大小将更小。
MATCH p =(o:Order)-[r:seeks*2..8]->(o:Order)
WHERE o.Name="000093" AND ALL(x IN tail(nodes(p)) WHERE SINGLE(y IN tail(nodes(p)) WHERE x=y))
WITH p, o, r, extract(u IN nodes(p)| u.UserName) AS UserName
// need to make some adjustments since first and last nodes are same
WHERE size(UserName) - 1 = size(apoc.coll.toSet(tail(UserName)))
RETURN extract(n IN nodes(p)| n.Name) AS OrderID, UserName, length(p), endNode(r[0])
ORDER BY length(p)
替代方法是在 UserName 集合上重复 ALL(x in tail...) WHERE single()... 谓词（或者在现有的 ALL() 谓词中包括此检查，尽管这可能很昂贵）。您可能想对每个进行 PROFILE，看看哪个性能更好。