按下 'E' 时如何重命名按钮

Question

从我之前的post那里偷来的，这就是这个post的目的。

具有用于输入密码的触觉数字键盘的银行金库系统很容易被小偷滥用。窃贼可以使用摄像头、他们自己甚至其他人来查看输入时 4 位密码的图案；因此他们不需要知道您的密码的实际值，只需要知道允许进入系统的按钮按下顺序。为了克服这个致命缺陷，可以使用具有数字键盘 GUI 的触摸屏显示器，每次输入 PIN 码时都会随机排列按键，无论它是否正确。

每次收到 'E' 时，我都试图打乱键盘矩阵（有效），但 GUI 拒绝更新。我试图让数字和字母在用户输入他们的 pin 时随机播放。任何帮助表示赞赏。

#!/usr/bin/env python3

import Tkinter as tk
import random

def code(value):
    # inform function to use external/global variable
    global pin

    if value == 'D':
        # remove last element from `pin`
        pin = pin[:-1]
        # remove all from `entry` and put new `pin`
        e.delete('0', 'end')
        e.insert('end', pin)

    elif value == 'E':
         # check pin

       if pin == "3529":

        print("PIN OK")


       else:
            print("PIN ERROR!")
            # clear pin
            pin = ''
            e.delete('0', 'end')


    else:
        # add number to `pin`
        pin += value
        # add number to `entry`
        e.insert('end', value)

    print("Current:", pin)



# --- main ---

# keypad description
keys = [
['1', '2', '3'],
['4', '5', '6'],
['7', '8', '9'],
['D', '0', 'E'],
]



for key in keys:
    random.shuffle(key)
    random.shuffle(keys)
    print(keys)

# create global variable 
pin = '' # empty string

# init
root = tk.Tk()

# create `entry` to display `pin`
e = tk.Entry(root, justify='right')
e.grid(row=0, column=0, columnspan=3, ipady=5)

# create `buttons` using `keys
for y, row in enumerate(keys, 1):
    for x, key in enumerate(row):
        # `lambda` inside `for` have to use `val=key:code(val)`
        # instead of direct `code(key)`
        b = tk.Button(root, text=key, command=lambda val=key:code(val))
        b.grid(row=y, column=x, ipadx=20, ipady=20)

# start program

root.mainloop()

Answer 1

将 enumerate(keys, 1) 更改为 enumerate(keys)，将 b.grid(row=y, column=x, ipadx=20, ipady=20) 更改为 b.grid(row=y+1, column=x, ipadx=20, ipady=20)，以便可以显示条目。

完整代码：

import tkinter as tk
import random

def code(position):
    global pin
    b = buttons[position]
    value = b['text']

    if value == 'D':
        # remove last element from `pin`
        pin = pin[:-1]
        # remove all from `entry` and put new `pin`
        e.delete('0', 'end')
        e.insert('end', pin)

    elif value == 'E':
        # check pin
        if pin == "3529":
            print("PIN OK")
        else:
            print("PIN ERROR!")
            # clear pin
            pin = ''
            e.delete('0', 'end')
    else:
        # add number to `pin`
        pin += value
        # add number to `entry`
        e.insert('end', value)

    print("Current:", pin)

    shuffle_buttons()

def shuffle_buttons():
    for key in keys:
        random.shuffle(key)
    random.shuffle(keys)
    for y, row in enumerate(keys):
        for x, key in enumerate(row):
            b = buttons[(x, y)]
            b['text'] = key                

# --- main ---

# keypad description

keys = [
    ['1', '2', '3'],
    ['4', '5', '6'],
    ['7', '8', '9'],
    ['D', '0', 'E'],
]

buttons = {}

# create global variable 
pin = '' # empty string

# init
root = tk.Tk()

# create `entry` to display `pin`
e = tk.Entry(root, justify='right')
e.grid(row=0, column=0, columnspan=3, ipady=5)

# create `buttons` using `keys
for y, row in enumerate(keys):
    for x, key in enumerate(row):
        position  = (x, y)
        b = tk.Button(root, text= key, command= lambda val=position: code(val))
        b.grid(row=y+1, column=x, ipadx=20, ipady=20)

        buttons[position] = b

shuffle_buttons()

root.mainloop()

按下 'E' 时如何重命名按钮

How to rename buttons when 'E' is pressed

python

shuffle

tkinter

keypad