Python Excel 如果条件为真打印下一行 t+1

Question

更新：

我希望 python 在满足条件时将 excel 文件中的 t+1 之类的下一行打印到 python 输出 window 中。我认为问题出在这部分代码

 print "FA",row[0], ','.join(row[1:])

这会打印今天我需要 python 打印第二天 (t+1)

我试过了print "FA",row[0], ','.join(row[1:]).nextline() 但这不起作用

例如假设 excel 文件有

35F 1,0,1,0,1,1,1
66F 1,0,1,0,0,0,0

35F 1,0,1,0,1,1,1<-- at this moment python prints this part 

66F 1,0,1,0,0,0,0<--- **But I want python to print this {66F 1,0,1,0,0,0,0} this is the t+1**

此外，这里是完整的代码

import csv

with open('2015weather.csv', 'r') as file1:
     val = list(csv.reader(file1))[3]


with open('FAsince1900.csv', 'r') as file2:
    reader = csv.reader(file2)
    reader.next() # this skips the first row of the file
    # this iteration will start from the second row of file2.csv
    for row in reader:
        if row[1:] == val:
            print print "FA",row[0], ','.join(row[1:])

更新 2：

Answer 1

这样的事情怎么样：

conditionMet = False
for row in reader:
    if conditionMet == True:
        print "FA",row[0], ','.join(row[1:])
        conditionMet = False # or break if you know you only need at most one line
    if row[1:] == val:
        conditionMet = True

Python Excel 如果条件为真打印下一行 t+1

Python Excel if a condition is true print next line t+1

python

import-from-csv