如何在不使用 new 关键字的情况下设置原型函数

Question

在原型继承的一个简单示例中，我想将 Person 对象设置为 Student 对象的父对象 class，但我不想使用 new 关键字在为 Student class 设置原型时，因为这是错误的。但不知何故这段代码不起作用。有什么帮助吗？

var Person = function(name) {
  var that = this;
  this.name = name;
  var _log = function() {
    console.log("Hello", that.name)
  };
  return {
    log: _log
  };
};

var Student = function(name) { 
  Person.call(this, name);  
  var _getCollegeName = function() {
    console.log("MIT")
  };
  return {
    getCollegeName: _getCollegeName
  };
};

Student.prototype = Object.create(Person);
//Student.prototype = new Person("Soham"); want to avoid this as the value should be passed from child class

var s = new Student("Soham");
s.log();
//s.getCollegeName();

Answer 1

您可以将 getCollegeName 设置为 Person() 调用的属性，return Person 对象

var Person = function(name) {
  var that = this;
  this.name = name;
  var _log = function() {
    console.log("Hello", that.name)
  };
  return {
    log: _log
  };
};

var Student = function(name) {
  var p = Person.call(this, name);

  var _getCollegeName = function() {
    console.log("MIT")
  };

  p.getCollegeName = _getCollegeName;

  return p
};

Student.prototype = Object.create(Person);
//Student.prototype = new Person("Soham"); want to avoid this as the value should be passed from child class

var s = Student("Soham");
s.log();
s.getCollegeName();

如何在不使用 new 关键字的情况下设置原型函数

How can I set a prototype function without using the new keyword

javascript

prototypal-inheritance