flask-admin: 如何只允许超级用户可以查看指定的 table 列？

Question

我已经构建了一个名为 Project 的 table 应用程序，它存储在 sqlite 中，我只想允许 超级用户 创建、编辑数据时可以查看approve栏目。

Project 数据在 "class Project" 中检索，我添加了 if current_user.has_role('superuser') 在 "class ProjectView":

from flask import Flask
from flask_sqlalchemy import SQLAlchemy
from flask_security import SQLAlchemyUserDatastore, current_user,UserMixin,        
     RoleMixin
from flask_admin.contrib import sqla

 # Create Flask application
 app = Flask(__name__)
 app.config.from_pyfile('config.py')
 db = SQLAlchemy(app)

 # Define models
 roles_users = db.Table(
     'roles_users',
     db.Column('user_id', db.Integer(), db.ForeignKey('user.id')),
     db.Column('role_id', db.Integer(), db.ForeignKey('role.id'))
 )

 class Role(db.Model, RoleMixin):
     id = db.Column(db.Integer(), primary_key=True)
     name = db.Column(db.String(80), unique=True)
     description = db.Column(db.String(255))

     def __str__(self):
         return self.name

 class User(db.Model, UserMixin):
     id = db.Column(db.Integer, primary_key=True)
     email = db.Column(db.String(255), unique=True)
     password = db.Column(db.String(255))
     roles = db.relationship('Role', secondary=roles_users,
                        backref=db.backref('users', lazy='dynamic'))

     def __str__(self):
         return self.email

 class Project(db.Model):
    id = db.Column(db.Integer, primary_key=True)
    team = db.Column(db.Unicode(64))
    project_name = db.Column(db.Unicode(128))
    approve = db.Column(db.Boolean())

 # Setup Flask-Security
 user_datastore = SQLAlchemyUserDatastore(db, User, Role)
 security = Security(app, user_datastore)


  # Create customized model view class
 class MyModelView(sqla.ModelView):

     def is_accessible(self):
        if not current_user.is_active or not current_user.is_authenticated:
            return False

        if current_user.has_role('superuser'):
            return True

        return False

     def _handle_view(self, name, **kwargs):
        if not self.is_accessible():
            if current_user.is_authenticated:
                # permission denied
               abort(403)
        else:
            # login
            return redirect(url_for('security.login', next=request.url))

 class ProjectView(sqla.ModelView):

    def is_accessible(self):
        if not current_user.is_active:
            return False
        else:
            return True

    def _handle_view(self, name, **kwargs):
        if not self.is_accessible():
            if current_user.is_authenticated:
                # permission denied
               abort(403)
            else:
               if current_user.has_role('superuser'):
                 form_create_rules = [
                 rules.FieldSet(('team'), 'Personal Info'),
                 rules.Header('Project Info'),
                 rules.Field('project_name'),
                 'approve',
                 rules.Container('rule_demo.wrap', rules.Field('notes'))
                 ]

             else: 
                 form_create_rules = [
                 rules.FieldSet(('team'), 'Personal Info'),
                 rules.Header('Project Info'),
                 rules.Field('project_name'),
                 #'approve',
                 rules.Container('rule_demo.wrap', rules.Field('notes'))
                 ]
             form_edit_rules = form_create_rules

             create_template = 'rule_create.html'
             edit_template = 'rule_edit.html'

    @app.route('/')
    def index():
      return render_template('index.html')

    # Create admin
    admin = flask_admin.Admin(
          app,
          'Release Control System',
          # log in success page
          base_template='my_master.html',   
          template_mode='bootstrap3',
        )

   # Add model views
   admin.add_view(MyModelView(Role, db.session))
   admin.add_view(MyModelView(User, db.session))
   admin.add_view(ProjectView(Project, db.session))

但它仍然不起作用，所有用户仍然可以查看 approve 列。好心提醒。提前致谢。

Answer 1

您可以使用 BaseModelView.column_list 属性来指定动态计算的可访问列列表，只需将其设为属性。然而，ModelView 的不同 "field" 属性在应用程序启动时被缓存，因此您需要覆盖它们的缓存：

from flask import has_app_context

class ProjectView(sqla.ModelView):
    @property
    def _list_columns(self):
        return self.get_list_columns()

    @_list_columns.setter
    def _list_columns(self, value):
        pass

    @property
    def column_list(self):
        if not has_app_context() or current_user.has_role('superuser'):
            return ['team', 'project_name', 'approve']
        else:
            return ['team', 'project_name']

当 current_user 不可用时，在应用程序初始化期间使用

column_list 属性。使用 flask.has_app_context() 方法检查此状态并在启动时向应用程序传递完整的列列表。

如果您需要指定不同的列集进行编辑，您需要 form_rules 属性（您已经在问题中使用了它们）：

from flask_admin.form import rules

class ProjectView(sqla.ModelView):
    @property
    def _form_edit_rules(self):
        return rules.RuleSet(self, self.form_rules)

    @_form_edit_rules.setter
    def _form_edit_rules(self, value):
        pass

    @property
    def _form_create_rules(self):
        return rules.RuleSet(self, self.form_rules)

    @_form_create_rules.setter
    def _form_create_rules(self, value):
        pass

    @property
    def form_rules(self):
        form_rules = [
            rules.FieldSet(('team',), 'Personal Info'),
            rules.Header('Project Info'),
            rules.Field('project_name')
        ]
        if not has_app_context() or current_user.has_role('superuser'):
            form_rules.append('approve')
        form_rules.append(rules.Container('rule_demo.wrap', rules.Field('notes')))
        return form_rules

此外，您不需要使用 _handle_view 将用户重定向到登录页面。为此，使用 BaseView.inaccessible_callback 方法：

def inaccessible_callback(self, name, **kwargs):
    if current_user.is_authenticated:
        abort(403)
    else:
        return redirect(url_for('security.login', next=request.url))

Answer 2

 class ProjectView(sqla.ModelView):
    '''
    def inaccessible_callback(self, name, **kwargs):
       if current_user.is_authenticated:
          abort(403)
       else:
          return redirect(url_for('security.login', next=request.url))
    '''
    def is_accessible(self):
        if not current_user.is_active or not current_user.is_authenticated:
            return False
        else:
            return True

    @property
    def _list_columns(self):
        return self.get_list_columns()

    @_list_columns.setter
    def _list_columns(self,value):
       pass

    @property
    def column_list(self):
       if not has_app_context() or current_user.has_role('superuser'):
          return ['team', 'project_name', 'approve']
       else:
          return ['team', 'project_name']

    form_edit_rules = column_list
    create_template = 'rule_create.html'
    edit_template = 'rule_edit.html'

Answer 3

class ProjectView(sqla.ModelView):

  def inaccessible_callback(self, name, **kwargs):
     if current_user.is_authenticated:
        abort(403)
     else:
        return redirect(url_for('security.login', next=request.url))

  @property
  def _form_edit_rules(self):
      return rules.RuleSet(self, self.form_rules)

  @_form_edit_rules.setter
  def _form_edit_rules(self, value):
      pass

  @property
  def _form_create_rules(self):
      return rules.RuleSet(self, self.form_rules)

  @_form_create_rules.setter
  def _form_create_rules(self, value):
      pass

  @property
  def form_rules(self):
      form_rules = [
          rules.FieldSet(('team'), 'Personal Info'),
          rules.Header('Project Info'),
          rules.Field('project_name')
      ]
      if not has_app_context() or current_user.has_role('superuser'):
          form_rules.append('approve')
      form_rules.append(rules.Container('rule_demo.wrap', 
          rules.Field('notes')))
      return form_rules

Answer 4

我想合并 FileAdmin（此处示例：https://github.com/flask-admin/flask-admin/tree/master/examples/file）。

也就是说只有在项目通过后（见图），用户才能将文件上传到系统自动指定的路径（比如：/Reviewer1/Reviewer2/file）

flask-admin: 如何只允许超级用户可以查看指定的 table 列？

flask-admin: how to allow only super users can view the specified table column?

flask

flask-sqlalchemy

flask-admin