Android 使用单选按钮向下操作
Android Action Down with radio button
我当前正在尝试制作项目,以便选择一个单选按钮并保留一个按钮时,它会产生所选的声音。但是当我使用 ACTION_DOWN 函数时,没有噪音产生。任何帮助都会很棒
public boolean onTouch(View v, MotionEvent event) {
int frequency = Integer.parseInt(frequencyInput.getText().toString());
displayFrequency.setText(String.valueOf(frequency));
sineWave.setSine(frequency);
squareWave.setSquareWave(frequency);
sawWave.setSawWave(frequency);
boolean on = ((startStop.isPressed()) && sine.isChecked());
boolean sqOn = ((startStop.isPressed()) && square.isChecked());
boolean sawOn =((startStop.isPressed()) && saw.isChecked());
switch (event.getAction()) {
case MotionEvent.ACTION_DOWN:
if (on)
{
sineWave.start();
}
else if (sqOn)
{
squareWave.start();
}
else if (sawOn)
{
sawWave.start();
}
break;
case MotionEvent.ACTION_UP:
if (!on) {
sineWave.stop();
}
if (!sqOn) {
squareWave.stop();
}
if (!sawOn) {
sawWave.stop();
;
}
break;
}
主要问题是你还在onTouch
的时候检查了isPressed()
,所以按钮的按下状态还没有设置。
如果您将 onTouchListener
直接添加到 startStop 按钮,您可以确定每次调用它时都是 startStop 按钮触发了事件。这允许您删除 startStop.isPressed()
检查。
startStop.setOnTouchListener(new View.OnTouchListener() {
@Override
public boolean onTouch(View v, MotionEvent event) {
int frequency = Integer.parseInt(frequencyInput.getText().toString());
displayFrequency.setText(String.valueOf(frequency));
sineWave.setSine(frequency);
squareWave.setSquareWave(frequency);
sawWave.setSawWave(frequency);
boolean on = sine.isChecked();
boolean sqOn = square.isChecked();
boolean sawOn = saw.isChecked();
switch (event.getAction()) {
case MotionEvent.ACTION_DOWN:
if (on) {
sineWave.start();
} else if (sqOn) {
squareWave.start();
} else if (sawOn) {
sawWave.start();
}
break;
case MotionEvent.ACTION_UP:
if (!on) {
sineWave.stop();
}
if (!sqOn) {
squareWave.stop();
}
if (!sawOn) {
sawWave.stop();
}
break;
default:
return false;
}
return true;
}
});
我当前正在尝试制作项目,以便选择一个单选按钮并保留一个按钮时,它会产生所选的声音。但是当我使用 ACTION_DOWN 函数时,没有噪音产生。任何帮助都会很棒
public boolean onTouch(View v, MotionEvent event) {
int frequency = Integer.parseInt(frequencyInput.getText().toString());
displayFrequency.setText(String.valueOf(frequency));
sineWave.setSine(frequency);
squareWave.setSquareWave(frequency);
sawWave.setSawWave(frequency);
boolean on = ((startStop.isPressed()) && sine.isChecked());
boolean sqOn = ((startStop.isPressed()) && square.isChecked());
boolean sawOn =((startStop.isPressed()) && saw.isChecked());
switch (event.getAction()) {
case MotionEvent.ACTION_DOWN:
if (on)
{
sineWave.start();
}
else if (sqOn)
{
squareWave.start();
}
else if (sawOn)
{
sawWave.start();
}
break;
case MotionEvent.ACTION_UP:
if (!on) {
sineWave.stop();
}
if (!sqOn) {
squareWave.stop();
}
if (!sawOn) {
sawWave.stop();
;
}
break;
}
主要问题是你还在onTouch
的时候检查了isPressed()
,所以按钮的按下状态还没有设置。
如果您将 onTouchListener
直接添加到 startStop 按钮,您可以确定每次调用它时都是 startStop 按钮触发了事件。这允许您删除 startStop.isPressed()
检查。
startStop.setOnTouchListener(new View.OnTouchListener() {
@Override
public boolean onTouch(View v, MotionEvent event) {
int frequency = Integer.parseInt(frequencyInput.getText().toString());
displayFrequency.setText(String.valueOf(frequency));
sineWave.setSine(frequency);
squareWave.setSquareWave(frequency);
sawWave.setSawWave(frequency);
boolean on = sine.isChecked();
boolean sqOn = square.isChecked();
boolean sawOn = saw.isChecked();
switch (event.getAction()) {
case MotionEvent.ACTION_DOWN:
if (on) {
sineWave.start();
} else if (sqOn) {
squareWave.start();
} else if (sawOn) {
sawWave.start();
}
break;
case MotionEvent.ACTION_UP:
if (!on) {
sineWave.stop();
}
if (!sqOn) {
squareWave.stop();
}
if (!sawOn) {
sawWave.stop();
}
break;
default:
return false;
}
return true;
}
});