如何进行这样的 mysql 查询?
How to do such a mysql query?
我会向你寻求帮助。
例子 table:
| ID | NAME |POINT|
| 1 | alex | 2 |
| 2 | alex | 2 |
| 3 | jenn | 4 |
| 4 | shama| 3 |
| 5 | jenn | 4 |
| 6 | Mike | 1 |
我想找到重复的名称并更改名称值和重复值的总和。
喜欢
| ID | NAME |POINT|
| 1 | alexander| 4 |
| 2 | jennifer | 8 |
是否可以mysql查询?
谢谢
这是你想要的吗?
select (@rn := @rn + 1) as id, name, sum(point) as point
from t cross join
(select @rn := 0) params
group by name
having count(*) >= 2;
试试这个
select id,
case when name = 'alex' then replace(NAME,'alex','alexander')
when name = 'jenn' then replace(NAME,'jenn','jennifer')
end as d,sum(point)
from name group by d having d is not null;
我会向你寻求帮助。 例子 table:
| ID | NAME |POINT|
| 1 | alex | 2 |
| 2 | alex | 2 |
| 3 | jenn | 4 |
| 4 | shama| 3 |
| 5 | jenn | 4 |
| 6 | Mike | 1 |
我想找到重复的名称并更改名称值和重复值的总和。 喜欢
| ID | NAME |POINT|
| 1 | alexander| 4 |
| 2 | jennifer | 8 |
是否可以mysql查询? 谢谢
这是你想要的吗?
select (@rn := @rn + 1) as id, name, sum(point) as point
from t cross join
(select @rn := 0) params
group by name
having count(*) >= 2;
试试这个
select id,
case when name = 'alex' then replace(NAME,'alex','alexander')
when name = 'jenn' then replace(NAME,'jenn','jennifer')
end as d,sum(point)
from name group by d having d is not null;