将 html 数据解析为 php 中的数组数据

parse the html data to array data in php

我正在尝试使用 a 标记 类 将 html 格式的数据解析为数组,但我无法获得所需的格式。下面是我的数据

$text ='<div class="result results_links results_links_deep web-result ">
  <div class="links_main links_deep result__body">
    <h2 class="result__title">
      <a rel="nofollow" class="result__a" href="">Text1</a> 
    </h2>
    <a class="result__snippet" href="">Text1</a> 
    <a class="result__url" href="">
    example.com
    </a>
  </div>
</div>

<div class="result results_links results_links_deep web-result ">
  <div class="links_main links_deep result__body">
    <h2 class="result__title">
      <a rel="nofollow" class="result__a" href="">text3</a> 
    </h2>
    <a class="result__snippet" href="">text23</a> 
    <a class="result__url" href="">
    text.com
    </a>
  </div>
</div>';

我正在尝试使用以下代码获取结果

$lines = explode("\n", $text);
$out = array();
foreach ($lines as $line) {
    $parts = explode(" > ", $line);
    $ref = &$out;
    while (count($parts) > 0) {
        if (isset($ref[$parts[0]]) === false) {
            $ref[$parts[0]] = array();
        }
        $ref = &$ref[$parts[0]];
        array_shift($parts);
    }
}
print_r($out);

但我需要完全像下面的结果

array:2 [
  0 => array:3 [
    0 => "Text1"
    1 => "Text1"
    2 => "example.com"
  ]
  1 => array:3 [
    0 => "text3"
    1 => "text23"
    2 => "text.com"
  ]
]

演示:https://eval.in/746170

甚至我也在尝试 dom 如下 laravel :

$dom = new DOMDocument;
$dom->loadHTML($text);
foreach($dom->getElementsByTagName('a') as $node)
{
    $array[] = $dom->saveHTML($node);
}

print_r($array);

那么我如何使用 类 来按照我的意愿分隔数据。任何建议 please.Thank 你。

给你,试试这个,如果你需要更多帮助,请告诉我:

<?php
$test = <<<EOS
<div class="result results_links results_links_deep web-result ">
  <div class="links_main links_deep result__body">
    <h2 class="result__title">
      <a rel="nofollow" class="result__a" href="">Text1</a>
    </h2>
    <a class="result__snippet" href="">Text1</a>
    <a class="result__url" href="">
    example.com
    </a>
  </div>
</div>

<div class="result results_links results_links_deep web-result ">
  <div class="links_main links_deep result__body">
    <h2 class="result__title">
      <a rel="nofollow" class="result__a" href="">text3</a>
    </h2>
    <a class="result__snippet" href="">text23</a>
    <a class="result__url" href="">
    text.com
    </a>
  </div>
</div>
EOS;

$document = new DOMDocument();
$document->loadHTML($test);

// first extract all the divs with the links_deep class
$divs = [];
foreach ($document->getElementsByTagName('div') as $div) {
    $classes = $div->attributes->getNamedItem('class')->nodeValue;
    if (!$classes) continue;

    $classes = explode(' ', $classes);

    if (in_array('links_main', $classes)) {
        $divs[] = $div;
    }
}

// now iterate through them and retrieve all the links in order
$results = [];
foreach ($divs as $div) {
    $temp = [];
    foreach ($div->getElementsByTagName('a') as $link) {
        $temp[] = $link->nodeValue;
    }
    $results[] = $temp;
}

var_dump($results);

工作版本 - http://sandbox.onlinephpfunctions.com/code/e7ed2615ea32c5b9f0a89e3460da28a2702343f1

我将使用 DOMDocumentDOMXPath 来更轻松地定位有趣的部分。为了更精确,我注册了一个函数来检查 class 属性是否包含一组 classes:

function hasClasses($attrValue, $requiredClasses) {
    $requiredClasses = explode(' ', $requiredClasses);
    $classes = preg_split('~\s+~', $attrValue, -1, PREG_SPLIT_NO_EMPTY);
    return array_diff($requiredClasses, $classes) ? false : true;
}

$dom = new DOMDocument;
$state = libxml_use_internal_errors(true);
$dom->loadHTML($html);
libxml_use_internal_errors($state);

$xp = new DOMXPath($dom);
$xp->registerNamespace('php', 'http://php.net/xpath');
$xp->registerPhpFunctions('hasClasses');

$mainDivClasses = 'result results_links results_links_deep web-result';
$childDivClasses = 'links_main links_deep result__body';

$divNodeList = $xp->query('//div[php:functionString("hasClasses", @class, "' . $mainDivClasses . '")]
                           /div[php:functionString("hasClasses", @class, "' . $childDivClasses . '")]');

$results = [];
foreach ($divNodeList as $divNode) {
    $results[] = [
        trim($xp->evaluate('string(./h2/a[@class="result__a"])', $divNode)),
        trim($xp->evaluate('string(.//a[@class="result__snippet"])', $divNode)),
        trim($xp->evaluate('string(.//a[@class="result__url"])', $divNode))
    ];
}

print_r($results);

无需注册函数,您也可以在谓词中使用 XPath 函数 contains。它不太精确,因为它只检查子字符串是否在更大的字符串中(而不是 class 属性是否具有特定的 class,如 hasClasses 函数)但它必须足够:

$dom = new DOMDocument;
$state = libxml_use_internal_errors(true);
$dom->loadHTML($html);
libxml_use_internal_errors($state);

$xp = new DOMXPath($dom);

$divNodeList = $xp->query('//div[contains(@class, "results_links_deep")]
                                [contains(@class, "web-result")]
                           /div[contains(@class, "links_main")]
                               [contains(@class, "links_deep")]
                               [contains(@class, "result__body")]');

$results = [];
foreach ($divNodeList as $divNode) {
    $results[] = [
        trim($xp->evaluate('string(./h2/a[@class="result__a"])', $divNode)),
        trim($xp->evaluate('string(.//a[@class="result__snippet"])', $divNode)),
        trim($xp->evaluate('string(.//a[@class="result__url"])', $divNode))
    ];
}

print_r($results);