如何在QUERY中使用CONCAT?
How to use CONCAT in QUERY?
我有一个 table:
A | B | C
BEN | MOSKOW | YES
ANTON | IRKUTSK | NO
VIKTOR | PARIS | YES
BEN | PARIS | YES
ANTON | TORONTO | NO
DON | TORONTO | YES
ANNA | IRKUTSK | YES
BEN | MOSKOW | NO
并尝试了一个公式:
=UNIQUE(query(A:C; "Select A,B,C where A contains 'BEN' OR A contains 'ANTON' order by A"))
和一个数组公式:
=arrayformula(UNIQUE(query(A:C; "Select A,B,C where A contains 'BEN' OR A contains 'ANTON' order by A")))
但结果在列中:
ANTON | IRKUTSK | NO
ANTON | TORONTO | NO
BEN | MOSKOW | YES
BEN | PARIS | YES
BEN | MOSKOW | NO
而我只需要每行一个单元格的结果,如下所示:
ANTON IRKUTSK NO
ANTON TORONTO NO
BEN MOSCOW YES
BEN PARIS YES
BEN MOSKOW NO
Google 工作表 query
中没有 concat
选项。
JPV 建议的解决方法可能适合您:
使用公式:
=ARRAYFORMULA(
SUBSTITUTE(
trim(transpose(query(transpose(_your_query_here_),,COLUMNS(_your_query_here_))))," "," → ")
)
将 " → "
更改为 space " "
以将结果与 space 连接。
有关表格中 SQL 的更多信息:
https://developers.google.com/chart/interactive/docs/querylanguage
使用转置两次。
=transpose(query(transpose(_you query_);;COLUMNS(_you query_)))
以我的问题为例:
=transpose(query(transpose(UNIQUE(query(A:C; "select * where A contains 'BEN' OR A contains 'ANTON' order by A")));;COLUMNS(UNIQUE(query(A:C; "select * where A contains 'BEN' OR A contains 'ANTON' order by A")))))
结果:
ANTON IRKUTSK NO
ANTON TORONTO NO
BEN MOSCOW YES
BEN PARIS YES
BEN MOSKOW NO
不幸的是,我的问题恰恰相反,当我使用常规查询时,表格会连接我的字符串。
=QUERY('Co-voiturage'!D21:F24;"select D, E Where F <> 0")
我有一个 table:
A | B | C
BEN | MOSKOW | YES
ANTON | IRKUTSK | NO
VIKTOR | PARIS | YES
BEN | PARIS | YES
ANTON | TORONTO | NO
DON | TORONTO | YES
ANNA | IRKUTSK | YES
BEN | MOSKOW | NO
并尝试了一个公式:
=UNIQUE(query(A:C; "Select A,B,C where A contains 'BEN' OR A contains 'ANTON' order by A"))
和一个数组公式:
=arrayformula(UNIQUE(query(A:C; "Select A,B,C where A contains 'BEN' OR A contains 'ANTON' order by A")))
但结果在列中:
ANTON | IRKUTSK | NO
ANTON | TORONTO | NO
BEN | MOSKOW | YES
BEN | PARIS | YES
BEN | MOSKOW | NO
而我只需要每行一个单元格的结果,如下所示:
ANTON IRKUTSK NO
ANTON TORONTO NO
BEN MOSCOW YES
BEN PARIS YES
BEN MOSKOW NO
Google 工作表 query
中没有 concat
选项。
JPV 建议的解决方法可能适合您:
使用公式:
=ARRAYFORMULA(
SUBSTITUTE(
trim(transpose(query(transpose(_your_query_here_),,COLUMNS(_your_query_here_))))," "," → ")
)
将 " → "
更改为 space " "
以将结果与 space 连接。
有关表格中 SQL 的更多信息:
https://developers.google.com/chart/interactive/docs/querylanguage
使用转置两次。
=transpose(query(transpose(_you query_);;COLUMNS(_you query_)))
以我的问题为例:
=transpose(query(transpose(UNIQUE(query(A:C; "select * where A contains 'BEN' OR A contains 'ANTON' order by A")));;COLUMNS(UNIQUE(query(A:C; "select * where A contains 'BEN' OR A contains 'ANTON' order by A")))))
结果:
ANTON IRKUTSK NO
ANTON TORONTO NO
BEN MOSCOW YES
BEN PARIS YES
BEN MOSKOW NO
不幸的是,我的问题恰恰相反,当我使用常规查询时,表格会连接我的字符串。
=QUERY('Co-voiturage'!D21:F24;"select D, E Where F <> 0")