我怎样才能让这 3 行代码更干

Question

此代码：

if len(group['elements']) > 0:
    groups.append(group)
    group = {'bla': '', 'elements': []}

在下面的例子中重复了 3 次。我想在 1 行中完成（至少减少它）。有可能吗？那我该怎么做呢？

collection_of_items = [
    ['strong', 'a', ['a'], '', 'strong', ['a'], ['a'], 'a', 'a', [], ''], 
    ['strong', 'a', ['a'], '', 'strong', 'a']
]

groups = []

for items in collection_of_items:
    group = {'bla': '', 'elements': []}
    for item in items:
        if hasattr(item, 'lower'):
            if item == 'strong':
                group['bla'] = item
            elif item =='a':
                group['elements'].append(item)
            elif item == '':
                # Make it DRY <---------------------------------------
                if len(group['elements']) > 0:
                    groups.append(group)
                    group = {'bla': '', 'elements': []}
        else:
            if 'a' in item:
                group['elements'].append(item[0])
            else:
                # Make it DRY <---------------------------------------
                if len(group['elements']) > 0:
                    groups.append(group)
                    group = {'bla': '', 'elements': []}

    # Make it DRY <---------------------------------------     
    if len(group['elements']) > 0:
                groups.append(group)
                group = {'bla': '', 'elements': []}

print(groups)

修改这 3 行，

注意：除了示例代码的结构外，什么都不能改变

抱歉有错误。

Answer 1

将该代码放入一个函数中，并在需要时调用它。但严重的是，4 space 缩进。

collection_of_items = [
  ['strong', 'a', ['a'], '', 'strong', ['a'], ['a'], 'a', 'a', [], ''], 
  ['strong', 'a', ['a'], '', 'strong', 'a']
]

groups = []

def my_func(g):
  if len(g['elements']) > 0:
    groups.append(g)
    g = {'bla': '', 'elements': []}
  return g

for items in collection_of_items:
  group = {'bla': '', 'elements': []}
  for item in items:
    if hasattr(item, 'lower'):
      if item == 'strong':
        group['bla'] = item
      elif item =='a':
        group['elements'].append(item)
      elif item == '':
        group = my_func(group)
    else:
      if 'a' in item:
        group['elements'].append(item[0])
      else:
        group = my_func(group)

  group = my_func(group)

print(groups)

我怎样才能让这 3 行代码更干

How can i make these 3 lines of code more DRY

python

dry

python-3.x