下划线 return 数组中对象的索引，其中单词存在于对象内的句子中

Question

我有一个数组，里面有这样的数组；

    var lines = [
["1","1","1","A man is walking."]
,["1","1","2","Noooo he's not, no way!"],
["1","1","3","You can't see that far can you?"],
["1","1","4","I can, he stopped, he's looking right at us"]
];

如果 line[4] 正好是搜索语句，使用 Underscore 我可以在 "lines" 中得到一个数组，例如，"A man is walking." 会 return lines[0];

所以我希望能够只用一个词来搜索这些句子（行），比如 "Walking" 应该匹配 return 'lines' 中的第一个数组因为有一个句子包含这个词。

_.some(lines, function(array){
            var result = (array[4] == 'walking' && array[4]);
        if (result !== false){
                console.log(result);
            } 
});

我该如何修改这个下划线函数，或者如果有一个我应该使用的正确的函数，或者如果有的话，即使它没有下划线，也请提出建议。

Answer 1

_.some returns 布尔值。您需要 filter 通过查看搜索词是否在字符串中获得的匹配结果。索引从 0 开始，因此您需要检查索引 3 而不是 4。

工作示例：

    var lines = [
        ["1", "1", "1", "A man is walking."],
        ["1", "1", "2", "Noooo he's not, no way!"],
        ["1", "1", "3", "You can't see that far can you?"],
        ["1", "1", "4", "I can, he stopped, he's looking right at us"]
    ];


    var input = document.getElementById('search');
    var output = document.getElementById('output');

    input.onkeyup = function (event) {
        var value = this.value;
        var results = _.filter(lines, function (array) {
            return array[3].indexOf(value) > -1;
        });

        var indexes = _.map(results, function(array) {
          return lines.indexOf(array);
       });

        output.innerHTML = '<pre>Indexes: ' + JSON.stringify(indexes) + '</pre><pre>' + JSON.stringify(results, null, 2) + '</pre>';
    };

<script src="//cdn.jsdelivr.net/lodash/2.1.0/lodash.compat.js"></script>
<input type="text" id="search" placeholder="Search">
<output id="output"></output>

Answer 2

假设你没有 ES6 的奢侈，简单地说 javascript:

var lines = [
["1","1","1","A man is walking."],
["1","1","2","Noooo he's not, no way!"],
["1","1","3","You can't see that far can you?"],
["1","1","4","I can, he stopped, he's looking right at us"]
];

function lineSearch(arr, term) {
  var indices = arr.map(function(innerArr, index) {
    return innerArr[3].indexOf(term) > -1 ? index : null;
  }).filter(function(x) {
    return x !== null;
  });

  var results = arr.map(function(innerArr, index) {
    return innerArr[3].indexOf(term) > -1 ? innerArr : null;
  }).filter(function(x) {
    return x !== null;
  });

  return {indices: indices, results: results};
}

console.log(lineSearch(lines, "can"));

应该给：

 {
  indices: [2, 3],
  results: [["1", "1", "3", "You can't see that far can you?"], ["1", "1", "4", "I can, he stopped, he's looking right at us"]]
 }

下划线 return 数组中对象的索引，其中单词存在于对象内的句子中

Underscore return indeces of objects in an array where word exists in sentences within objects

javascript

arrays

search

indexof

underscore.js