如何获取时间表的 "time" 值
How to obtain the "time" values of a schedule
假设固定利率债券的时间表如下面的示例代码所示。
我可以使用 businessDaysBetween
函数获取期限之间的天数。
现在我要"time value"。有没有不创建新函数的方法?
这是预期的结果:
May 14th, 2012 .5
November 14th, 2012 .5
May 14th, 2013 .5
November 14th, 2013 .5
May 14th, 2014 .5
November 14th, 2014 .5
May 14th, 2015 .5
November 16th, 2015 .505556
May 16th, 2016 .5
November 14th, 2016 .49444
代码如下:
from QuantLib import *
import pandas as pd
effective_date = Date(14, 11, 2011)
termination_date = Date(14, 11, 2016)
tenor = Period(Semiannual)
calendar = UnitedStates()
business_convention = ModifiedFollowing
termination_business_convention = Following
date_generation = DateGeneration.Forward
end_of_month = False
day_count = Thirty360()
schedule = Schedule(effective_date,
termination_date,
tenor,
calendar,
business_convention,
termination_business_convention,
date_generation,
end_of_month)
t = []
for i, d in enumerate(schedule):
tmp = i+1, d,
t.append(tmp)
df = pd.DataFrame(t,columns = ['tenorNo','tenorDate'])
nbDays = []
for x in df['tenorNo'] :
if x == 1:
tmp = 0
else:
tmp = calendar.businessDaysBetween(df['tenorDate'][x-2],df['tenorDate'][x-1])
nbDays.append(tmp)
df['nbDays'] = nbDays
print df
tenorNo tenorDate nbDays
0 1 November 14th, 2011 0
1 2 May 14th, 2012 125
2 3 November 14th, 2012 127
3 4 May 14th, 2013 124
4 5 November 14th, 2013 127
5 6 May 14th, 2014 124
6 7 November 14th, 2014 127
7 8 May 14th, 2015 124
8 9 November 16th, 2015 127
9 10 May 16th, 2016 125
10 11 November 14th, 2016 125
这就是 DayCounter
实例的用途。时间将取决于您选择的天数规则(例如,您似乎使用的是 30/360)。
通话中
day_count.yearFraction(date1, date2)
将 return date1
和 date2
之间的时间。
假设固定利率债券的时间表如下面的示例代码所示。
我可以使用 businessDaysBetween
函数获取期限之间的天数。
现在我要"time value"。有没有不创建新函数的方法?
这是预期的结果:
May 14th, 2012 .5
November 14th, 2012 .5
May 14th, 2013 .5
November 14th, 2013 .5
May 14th, 2014 .5
November 14th, 2014 .5
May 14th, 2015 .5
November 16th, 2015 .505556
May 16th, 2016 .5
November 14th, 2016 .49444
代码如下:
from QuantLib import *
import pandas as pd
effective_date = Date(14, 11, 2011)
termination_date = Date(14, 11, 2016)
tenor = Period(Semiannual)
calendar = UnitedStates()
business_convention = ModifiedFollowing
termination_business_convention = Following
date_generation = DateGeneration.Forward
end_of_month = False
day_count = Thirty360()
schedule = Schedule(effective_date,
termination_date,
tenor,
calendar,
business_convention,
termination_business_convention,
date_generation,
end_of_month)
t = []
for i, d in enumerate(schedule):
tmp = i+1, d,
t.append(tmp)
df = pd.DataFrame(t,columns = ['tenorNo','tenorDate'])
nbDays = []
for x in df['tenorNo'] :
if x == 1:
tmp = 0
else:
tmp = calendar.businessDaysBetween(df['tenorDate'][x-2],df['tenorDate'][x-1])
nbDays.append(tmp)
df['nbDays'] = nbDays
print df
tenorNo tenorDate nbDays
0 1 November 14th, 2011 0
1 2 May 14th, 2012 125
2 3 November 14th, 2012 127
3 4 May 14th, 2013 124
4 5 November 14th, 2013 127
5 6 May 14th, 2014 124
6 7 November 14th, 2014 127
7 8 May 14th, 2015 124
8 9 November 16th, 2015 127
9 10 May 16th, 2016 125
10 11 November 14th, 2016 125
这就是 DayCounter
实例的用途。时间将取决于您选择的天数规则(例如,您似乎使用的是 30/360)。
通话中
day_count.yearFraction(date1, date2)
将 return date1
和 date2
之间的时间。