从字典中提取匹配字段
Extract matching fileds from dictonary
有没有更聪明的方法可以将 OrderedDict 中的所有键提取到新字典中?
例如:我将所有匹配到'pre'的key收集到字典'cfg_pre'中。我试过这个(有效):
#!/usr/bin/env python
import collections
dl=collections.OrderedDict()
dl ={
'pre_enable': True,
'pre_path': '/usr/bin/pre_script.sh',
'pre_args': '-la -w --dir',
'post_enable': True,
'post_path': '/usr/bin/post_script.sh',
'fail_enable': True,
'fail_path': '/usr/bin/failure_script.sh',
'fail_args': '--debug 4'
}
cfg_pre = dict((k,v) for k, v in dl.items() if 'pre' in k)
cfg_post= dict((k,v) for k, v in dl.items() if 'post' in k)
cfg_fail=dict((k,v) for k, v in dl.items() if 'fail' in k)
print (cfg_pre)
print ("---")
print(cfg_post)
print ("---")
print(cfg_fail)
print ("---")
dl-dict 中的键总是以 pre、post 或 fail 开头。
谢谢 ;)
对于这样的问题,三行就足够了。
听写理解会更清晰一些:
cfg_pre = {k: v for k, v in dl.items() if 'pre' in k}
cfg_post = {k: v for k, v in dl.items() if 'post' in k}
cfg_fail = {k: v for k, v in dl.items() if 'fail' in k}
您也可以像这样删除冗余数据:
cfg_pre = {k.replace('pre_', ''): v for k, v in dl.items() if 'pre' in k}
cfg_post = {k.replace('post_', ''): v for k, v in dl.items() if 'post' in k}
cfg_fail = {k.replace('fail_', ''): v for k, v in dl.items() if 'fail' in k}
字典将更加一致,pre、post和fail将只存储在变量名中:
cfg_pre = {'args': '-la -w --dir', 'enable': True, 'path': '/usr/bin/pre_script.sh'}
cfg_post = {'enable': True, 'path': '/usr/bin/post_script.sh'}
cfg_fail = {'args': '--debug 4', 'enable': True, 'path': '/usr/bin/failure_script.sh'}
编辑 -> 更新以满足您的需要
如果您想概括,我建议您按方法分组。像 :
import itertools as it
#define a function to split your universe (here the beginning of your keys)
def keyfunc(key):
return key.split('_')[0]
#group by prefixes
groups = {k:list(g) for k,g in it.groupby(dl, keyfunc)}
#build your output
output = {g:[(key,dl[key]) for key in v] for g,v in groups.items()}
您将得到以下输出:
{'fail': [('fail_enable', True),
('fail_path', '/usr/bin/failure_script.sh'),
('fail_args', '--debug 4')],
'post': [('post_enable', True), ('post_path', '/usr/bin/post_script.sh')],
'pre': [('pre_enable', True),
('pre_path', '/usr/bin/pre_script.sh'),
('pre_args', '-la -w --dir')]}
有没有更聪明的方法可以将 OrderedDict 中的所有键提取到新字典中?
例如:我将所有匹配到'pre'的key收集到字典'cfg_pre'中。我试过这个(有效):
#!/usr/bin/env python
import collections
dl=collections.OrderedDict()
dl ={
'pre_enable': True,
'pre_path': '/usr/bin/pre_script.sh',
'pre_args': '-la -w --dir',
'post_enable': True,
'post_path': '/usr/bin/post_script.sh',
'fail_enable': True,
'fail_path': '/usr/bin/failure_script.sh',
'fail_args': '--debug 4'
}
cfg_pre = dict((k,v) for k, v in dl.items() if 'pre' in k)
cfg_post= dict((k,v) for k, v in dl.items() if 'post' in k)
cfg_fail=dict((k,v) for k, v in dl.items() if 'fail' in k)
print (cfg_pre)
print ("---")
print(cfg_post)
print ("---")
print(cfg_fail)
print ("---")
dl-dict 中的键总是以 pre、post 或 fail 开头。 谢谢 ;)
对于这样的问题,三行就足够了。
听写理解会更清晰一些:
cfg_pre = {k: v for k, v in dl.items() if 'pre' in k}
cfg_post = {k: v for k, v in dl.items() if 'post' in k}
cfg_fail = {k: v for k, v in dl.items() if 'fail' in k}
您也可以像这样删除冗余数据:
cfg_pre = {k.replace('pre_', ''): v for k, v in dl.items() if 'pre' in k}
cfg_post = {k.replace('post_', ''): v for k, v in dl.items() if 'post' in k}
cfg_fail = {k.replace('fail_', ''): v for k, v in dl.items() if 'fail' in k}
字典将更加一致,pre、post和fail将只存储在变量名中:
cfg_pre = {'args': '-la -w --dir', 'enable': True, 'path': '/usr/bin/pre_script.sh'}
cfg_post = {'enable': True, 'path': '/usr/bin/post_script.sh'}
cfg_fail = {'args': '--debug 4', 'enable': True, 'path': '/usr/bin/failure_script.sh'}
编辑 -> 更新以满足您的需要
如果您想概括,我建议您按方法分组。像 :
import itertools as it
#define a function to split your universe (here the beginning of your keys)
def keyfunc(key):
return key.split('_')[0]
#group by prefixes
groups = {k:list(g) for k,g in it.groupby(dl, keyfunc)}
#build your output
output = {g:[(key,dl[key]) for key in v] for g,v in groups.items()}
您将得到以下输出:
{'fail': [('fail_enable', True),
('fail_path', '/usr/bin/failure_script.sh'),
('fail_args', '--debug 4')],
'post': [('post_enable', True), ('post_path', '/usr/bin/post_script.sh')],
'pre': [('pre_enable', True),
('pre_path', '/usr/bin/pre_script.sh'),
('pre_args', '-la -w --dir')]}