将列表相乘

Question

一直在做一个小的 class 项目来制作二十一点游戏。我意识到在这方面有十亿种方法，但我正在尝试理解编码并构建自己的……话虽这么说，但我搞砸了很多。虽然这个难题让我感到困惑......在设置我的套牌时，我试过这个：

suits = ['spades', 'hearts', 'clubs', 'diamonds']
ranks = ['ace', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight',     'nine', 'ten', 'Jack', 'Queen', 'King']

decks = []

for suit in suits:
    for rank in ranks:
        decks += (rank, suit)
print decks

我得到了两个列表一起排序的预期结果： ['ace', 'spades', 'two', 'spades', 'three', 'spades', 'four'...]

但是，当我尝试将它们组合成字典时，如下所示：

b = dict(zip(decks[1::2], decks[0::2]))
print b

我得到：{'hearts'：'King'，'clubs'：'King'，'spades'：'King'，'diamonds' : 'King'} 为什么它只做国王值？

当我尝试使用以下代码进行纠正时：

spade = ['spades']

ranks = ['ace', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine', 'ten', 'Jack', 'Queen', 'King']

spades = []

for rank in ranks:
    spades += (rank, spade)
print spades

我得到这个作为输出： ['ace', ['spades'], 'two', ['spades'], 'three', ['spades'],...]

那么是什么原因呢？帮助菜鸟！我的意图是通过列表稍微优雅地创建一个套牌，将值附加到卡片，创建一个字典并使用这些值来计算分数......并试图更好地理解 Python 编码！

谢谢！

Answer 1

您可以使用列表组合来创建一副纸牌，例如 [[rank,suits]]。 dict() 仅从 2 个值 [value1,value2] 创建了一个对象。你不断得到 {'hearts': 'King', 'clubs': 'King', 'spades': 'King', 'diamonds': 'King'} 的原因是因为字典有唯一的 {key:value} 对，最后要分配这些键的项目是 ranks 数组中的 King 。

suits = ['spades', 'hearts', 'clubs', 'diamonds']
ranks = ['ace', 'two', 'three', 'four', 'five', 'six', 'seven',
         'eight',     'nine', 'ten', 'Jack', 'Queen', 'King']

print [(rank, suit) for suit in suits for rank in ranks]

解决方案

您可以将 ranks 的键和 (rank,suit) 的值设为具有相同 rank

的数组

card_dict = {}
suits = ['spades', 'hearts', 'clubs', 'diamonds']
ranks = ['ace', 'two', 'three', 'four', 'five', 'six', 'seven',
         'eight', 'nine', 'ten', 'Jack', 'Queen', 'King']
deck = [(rank, suit) for suit in suits for rank in ranks]

map(
    lambda rank: card_dict.update(
        {
            rank: filter(lambda card: rank in card, deck)
        }
    ), ranks
)

print card_dict

结果

{
  'King': [('King', 'spades'), ('King', 'hearts'), ('King', 'clubs'), ('King', 'diamonds')],
  'seven': [('seven', 'spades'), ('seven', 'hearts'), ('seven', 'clubs'), ('seven', 'diamonds')],
  'Queen': [('Queen', 'spades'), ('Queen', 'hearts'), ('Queen', 'clubs'), ('Queen', 'diamonds')],
  'ace': [('ace', 'spades'), ('ace', 'hearts'), ('ace', 'clubs'), ('ace', 'diamonds')],
  'ten': [('ten', 'spades'), ('ten', 'hearts'), ('ten', 'clubs'), ('ten', 'diamonds')],
  'nine': [('nine', 'spades'), ('nine', 'hearts'), ('nine', 'clubs'), ('nine', 'diamonds')],
  'six': [('six', 'spades'), ('six', 'hearts'), ('six', 'clubs'), ('six', 'diamonds')],
  'two': [('two', 'spades'), ('two', 'hearts'), ('two', 'clubs'), ('two', 'diamonds')],
  'three': [('three', 'spades'), ('three', 'hearts'), ('three', 'clubs'), ('three', 'diamonds')],
  'four': [('four', 'spades'), ('four', 'hearts'), ('four', 'clubs'), ('four', 'diamonds')],
  'five': [('five', 'spades'), ('five', 'hearts'), ('five', 'clubs'), ('five', 'diamonds')],
  'Jack': [('Jack', 'spades'), ('Jack', 'hearts'), ('Jack', 'clubs'), ('Jack', 'diamonds')],
  'eight': [('eight', 'spades'), ('eight', 'hearts'), ('eight', 'clubs'), ('eight', 'diamonds')]
}

或者如果您按 suits 而不是 ranks

映射

{
  'clubs': [('ace', 'clubs'),
    ('two', 'clubs'),
    ('three', 'clubs'),
    ('four', 'clubs'),
    ('five', 'clubs'),
    ('six', 'clubs'),
    ('seven', 'clubs'),
    ('eight', 'clubs'),
    ('nine', 'clubs'),
    ('ten', 'clubs'),
    ('Jack', 'clubs'),
    ('Queen', 'clubs'),
    ('King', 'clubs')
  ],
  'diamonds': [('ace', 'diamonds'),
    ('two', 'diamonds'),
    ('three', 'diamonds'),
    ('four', 'diamonds'),
    ('five', 'diamonds'),
    ('six', 'diamonds'),
    ('seven', 'diamonds'),
    ('eight', 'diamonds'),
    ('nine', 'diamonds'),
    ('ten', 'diamonds'),
    ('Jack', 'diamonds'),
    ('Queen', 'diamonds'),
    ('King', 'diamonds')
  ],
  'hearts': [('ace', 'hearts'),
    ('two', 'hearts'),
    ('three', 'hearts'),
    ('four', 'hearts'),
    ('five', 'hearts'),
    ('six', 'hearts'),
    ('seven', 'hearts'),
    ('eight', 'hearts'),
    ('nine', 'hearts'),
    ('ten', 'hearts'),
    ('Jack', 'hearts'),
    ('Queen', 'hearts'),
    ('King', 'hearts')
  ],
  'spades': [('ace', 'spades'),
    ('two', 'spades'),
    ('three', 'spades'),
    ('four', 'spades'),
    ('five', 'spades'),
    ('six', 'spades'),
    ('seven', 'spades'),
    ('eight', 'spades'),
    ('nine', 'spades'),
    ('ten', 'spades'),
    ('Jack', 'spades'),
    ('Queen', 'spades'),
    ('King', 'spades')
  ]
}

洗牌

import random
random.shuffle(deck)
print deck

Answer 2

谈论乘法列表应该迫使您使用 itertools.product，并通过转换为 list

强制迭代

import itertools

suits = ['spades', 'hearts', 'clubs', 'diamonds']
ranks = ['ace', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight',     'nine', 'ten', 'Jack', 'Queen', 'King']

decks = list(itertools.product(suits,ranks))

print(decks)

结果

[('spades', 'ace'), ('spades', 'two'), ('spades', 'three'), ('spades', 'four'), ('spades', 'five'), ('spades', 'six'), ('spades', 'seven'), ('spades', 'eight'), ('spades', 'nine'), ('spades', 'ten'), ('spades', 'Jack'), ('spades', 'Queen'), ('spades', 'King'), ('hearts', 'ace'), ('hearts', 'two'), ('hearts', 'three'), ('hearts', 'four'), ('hearts', 'five'), ('hearts', 'six'), ('hearts', 'seven'), ('hearts', 'eight'), ('hearts', 'nine'), ('hearts', 'ten'), ('hearts', 'Jack'), ('hearts', 'Queen'), ('hearts', 'King'), ('clubs', 'ace'), ('clubs', 'two'), ('clubs', 'three'), ('clubs', 'four'), ('clubs', 'five'), ('clubs', 'six'), ('clubs', 'seven'), ('clubs', 'eight'), ('clubs', 'nine'), ('clubs', 'ten'), ('clubs', 'Jack'), ('clubs', 'Queen'), ('clubs', 'King'), ('diamonds', 'ace'), ('diamonds', 'two'), ('diamonds', 'three'), ('diamonds', 'four'), ('diamonds', 'five'), ('diamonds', 'six'), ('diamonds', 'seven'), ('diamonds', 'eight'), ('diamonds', 'nine'), ('diamonds', 'ten'), ('diamonds', 'Jack'), ('diamonds', 'Queen'), ('diamonds', 'King')]

或者由于您似乎需要一个平面列表，只需使用 chain.from_iterable:

将其展平即可

decks = list(itertools.chain.from_iterable(itertools.product(suits,ranks)))

将列表相乘

Multiplying lists together

list

dictionary

python-2.6

解决方案

结果

洗牌