T-SQL - 在两个特定单词之后拆分下一个单词
T-SQL - Split the next word after two specific words
假设我有以下字符串:
"Select * From table_1 INNER JOIN table_2 ON table_1.A = table_2.B"
我想提取语句的两个表,以便得到:
table_1; table_2.
基本上我需要获取字符串 From 和 Join 之后的下一个单词。我正在尝试以下查询:
DECLARE @StaffName nvarchar(4000)
SET @StaffName = 'Select * From table_1 INNER JOIN table_2 ON table_1.A = table_2.B'
SELECT SUBSTRING
(
@StaffName,
CHARINDEX('From', @StaffName),
CHARINDEX(' ', SUBSTRING(@StaffName, CHARINDEX(' ', @StaffName), 255))
) ,
SUBSTRING(@StaffName, CHARINDEX('From ', @StaffName) + 5, LEN(@StaffName))
,
SUBSTRING(@StaffName, CHARINDEX('From ', @StaffName) + 5, LEN(@StaffName))
,
RIGHT(@StaffName,LEN(@StaffName)-CHARINDEX('From ',@StaffName))
但我没有得到我想要的:(
谁能帮帮我?
非常感谢!
使用 left()
、right(),
和 charindex()
的组合:
declare @str varchar(256) = 'Select * From table_1 INNER JOIN table_2 ON table_1.A = table_2.B';
select
tbl1 = left(right(@str,len(@str)-charindex(' From ',@str)-5)
,charindex(' ',right(@str,len(@str)-charindex(' From ',@str)-5))-1
)
, tbl2 = left(right(@str,len(@str)-charindex(' Join ',@str)-5)
,charindex(' ',right(@str,len(@str)-charindex(' Join ',@str)-5))-1
)
rextester 演示:http://rextester.com/WOO86939
returns:
+---------+---------+
| tbl1 | tbl2 |
+---------+---------+
| table_1 | table_2 |
+---------+---------+
查看 SQLZim 的完全有效 (+1) 的答案,让我意识到我已经厌倦了提取部分字符串。因此,我修改了我的解析函数以接受两个多字符定界符。因此,如果您对 UDF 开放,请考虑以下事项:
旁注:作为 Table-Valued-Function,很容易合并到 CROSS APPLY 中或作为单个查询
根据您的具体要求,我们正在寻找 FROM
和 ON
的关键词
Declare @String varchar(max) = 'Select * From table_1 INNER JOIN table_2 ON table_1.A = table_2.B'
Select Table1 = left(RetVal,charindex(' ',RetVal+' ')-1)
,Table2 = right(RetVal,charindex(' ',reverse(RetVal)+' ')-1)
From [dbo].[udf-Str-Extract] (@String,' from ',' on ')
Returns
Table1 Table2
table_1 table_2
一个通用示例:
假设我们正在寻找 {}
之间的值
Declare @String varchar(max) = 'co-101{12345},co-513{22578}'
Select * From [dbo].[udf-Str-Extract] (@String,'{','}')
Returns
RetSeq RetPos RetLen RetVal
1 8 5 12345
2 22 5 22578
另一个通用示例
Declare @String varchar(max) = '<root><firstmame>John</firstname><lastname>Cappelletti</lastname><phone>(401) 555-1212</phone></root>'
Select * From [dbo].[udf-Str-Extract] (@String,'>','<')
Returns
RetSeq RetPos RetLen RetVal
1 18 4 John
2 44 11 Cappelletti
3 73 14 (401) 555-1212
感兴趣的 UDF
CREATE FUNCTION [dbo].[udf-Str-Extract] (@String varchar(max),@Delimiter1 varchar(100),@Delimiter2 varchar(100))
Returns Table
As
Return (
with cte1(N) As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)),
cte2(N) As (Select Top (IsNull(DataLength(@String),0)) Row_Number() over (Order By (Select NULL)) From (Select N=1 From cte1 N1,cte1 N2,cte1 N3,cte1 N4,cte1 N5,cte1 N6) A ),
cte3(N) As (Select 1 Union All Select t.N+DataLength(@Delimiter1) From cte2 t Where Substring(@String,t.N,DataLength(@Delimiter1)) = @Delimiter1),
cte4(N,L) As (Select S.N,IsNull(NullIf(CharIndex(@Delimiter1,@String,s.N),0)-S.N,8000) From cte3 S)
Select RetSeq = Row_Number() over (Order By N)
,RetPos = N
,RetLen = charindex(@Delimiter2,RetVal)-1
,RetVal = left(RetVal,charindex(@Delimiter2,RetVal)-1)
From (Select A.N,RetVal = ltrim(rtrim(Substring(@String, A.N, A.L))) From cte4 A ) A
Where charindex(@Delimiter2,RetVal)>1
)
/*
Max Length of String 1MM characters
Declare @String varchar(max) = 'Dear [[FirstName]] [[LastName]], ...'
Select * From [dbo].[udf-Str-Extract] (@String,'[[',']]')
*/
假设我有以下字符串: "Select * From table_1 INNER JOIN table_2 ON table_1.A = table_2.B"
我想提取语句的两个表,以便得到: table_1; table_2.
基本上我需要获取字符串 From 和 Join 之后的下一个单词。我正在尝试以下查询:
DECLARE @StaffName nvarchar(4000)
SET @StaffName = 'Select * From table_1 INNER JOIN table_2 ON table_1.A = table_2.B'
SELECT SUBSTRING
(
@StaffName,
CHARINDEX('From', @StaffName),
CHARINDEX(' ', SUBSTRING(@StaffName, CHARINDEX(' ', @StaffName), 255))
) ,
SUBSTRING(@StaffName, CHARINDEX('From ', @StaffName) + 5, LEN(@StaffName))
,
SUBSTRING(@StaffName, CHARINDEX('From ', @StaffName) + 5, LEN(@StaffName))
,
RIGHT(@StaffName,LEN(@StaffName)-CHARINDEX('From ',@StaffName))
但我没有得到我想要的:(
谁能帮帮我?
非常感谢!
使用 left()
、right(),
和 charindex()
的组合:
declare @str varchar(256) = 'Select * From table_1 INNER JOIN table_2 ON table_1.A = table_2.B';
select
tbl1 = left(right(@str,len(@str)-charindex(' From ',@str)-5)
,charindex(' ',right(@str,len(@str)-charindex(' From ',@str)-5))-1
)
, tbl2 = left(right(@str,len(@str)-charindex(' Join ',@str)-5)
,charindex(' ',right(@str,len(@str)-charindex(' Join ',@str)-5))-1
)
rextester 演示:http://rextester.com/WOO86939
returns:
+---------+---------+
| tbl1 | tbl2 |
+---------+---------+
| table_1 | table_2 |
+---------+---------+
查看 SQLZim 的完全有效 (+1) 的答案,让我意识到我已经厌倦了提取部分字符串。因此,我修改了我的解析函数以接受两个多字符定界符。因此,如果您对 UDF 开放,请考虑以下事项:
旁注:作为 Table-Valued-Function,很容易合并到 CROSS APPLY 中或作为单个查询
根据您的具体要求,我们正在寻找 FROM
和 ON
Declare @String varchar(max) = 'Select * From table_1 INNER JOIN table_2 ON table_1.A = table_2.B'
Select Table1 = left(RetVal,charindex(' ',RetVal+' ')-1)
,Table2 = right(RetVal,charindex(' ',reverse(RetVal)+' ')-1)
From [dbo].[udf-Str-Extract] (@String,' from ',' on ')
Returns
Table1 Table2
table_1 table_2
一个通用示例:
假设我们正在寻找 {}
之间的值Declare @String varchar(max) = 'co-101{12345},co-513{22578}'
Select * From [dbo].[udf-Str-Extract] (@String,'{','}')
Returns
RetSeq RetPos RetLen RetVal
1 8 5 12345
2 22 5 22578
另一个通用示例
Declare @String varchar(max) = '<root><firstmame>John</firstname><lastname>Cappelletti</lastname><phone>(401) 555-1212</phone></root>'
Select * From [dbo].[udf-Str-Extract] (@String,'>','<')
Returns
RetSeq RetPos RetLen RetVal
1 18 4 John
2 44 11 Cappelletti
3 73 14 (401) 555-1212
感兴趣的 UDF
CREATE FUNCTION [dbo].[udf-Str-Extract] (@String varchar(max),@Delimiter1 varchar(100),@Delimiter2 varchar(100))
Returns Table
As
Return (
with cte1(N) As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)),
cte2(N) As (Select Top (IsNull(DataLength(@String),0)) Row_Number() over (Order By (Select NULL)) From (Select N=1 From cte1 N1,cte1 N2,cte1 N3,cte1 N4,cte1 N5,cte1 N6) A ),
cte3(N) As (Select 1 Union All Select t.N+DataLength(@Delimiter1) From cte2 t Where Substring(@String,t.N,DataLength(@Delimiter1)) = @Delimiter1),
cte4(N,L) As (Select S.N,IsNull(NullIf(CharIndex(@Delimiter1,@String,s.N),0)-S.N,8000) From cte3 S)
Select RetSeq = Row_Number() over (Order By N)
,RetPos = N
,RetLen = charindex(@Delimiter2,RetVal)-1
,RetVal = left(RetVal,charindex(@Delimiter2,RetVal)-1)
From (Select A.N,RetVal = ltrim(rtrim(Substring(@String, A.N, A.L))) From cte4 A ) A
Where charindex(@Delimiter2,RetVal)>1
)
/*
Max Length of String 1MM characters
Declare @String varchar(max) = 'Dear [[FirstName]] [[LastName]], ...'
Select * From [dbo].[udf-Str-Extract] (@String,'[[',']]')
*/