在 Oracle 中获取 SYNONYM 中的特定列名称

Question

通过此查询，我可以成功获取 Oracle table.

的列名列表

SELECT COLUMN_NAME
FROM USER_TAB_COLUMNS
WHERE table_name = 'TBL_NEWS' 
AND COLUMN_NAME LIKE ('GLOBE_%') 
ORDER BY  COLUMN_ID

我有一个同义词，我还需要获取该同义词的所有列名。那么我如何扩展上面的查询以获取同义词中以 GLOBE_ 开头的所有列名？

Answer 1

同义词没有列，它所指的 table 有列。所以你可以使用这个：

SELECT COLUMN_NAME
FROM ALL_TAB_COLUMNS atc
JOIN ALL_SYNONYMS als ON atc.table_name = als.table_name
WHERE als.SYNONYM_NAME='my_synonym'
  AND als.OWNER IN (USER, 'PUBLIC')
  AND atc.COLUMN_NAME LIKE ('GLOBE_%')
ORDER BY atc.COLUMN_ID

Answer 2

取决于您希望从中获取数据的架构范围 - 您可以使用 ALL_TAB_COLUMNS 和 ALL_SYNONYMS 或 DBA_TAB_COLUMNS 和 DBA_SYNONYMS

SELECT COLUMN_NAME FROM ALL_TAB_COLUMNS ATC JOIN ALL_SYNONYMS ALS ON ATC.table_name = ALS.table_name WHERE ALS.SYNONYM_NAME='my_synonym'      AND ATC.COLUMN_NAME LIKE ('GLOBE_%') ORDER BY ATC.COLUMN_ID;

or 


SELECT COLUMN_NAME FROM DBA_TAB_COLUMNS DTC JOIN DBA_SYNONYMS DS ON DTC.table_name = DS.table_name WHERE DS.SYNONYM_NAME='my_synonym'    AND DTC.COLUMN_NAME LIKE ('GLOBE_%') ORDER BY DTC.COLUMN_ID;

Answer 3

而不是查询数据字典。您可以在 table/view/synonym.

中的 return 列列表中创建函数

create type list_varchar2 is table of varchar2(100);
/
create or replace function  list_of_column(p_name in varchar2) return list_varchar2 PIPELINED  
    is
        v_Cnt        number :=  0;
        v_table_description       dbms_sql.desc_tab;
        c_curosor     integer default dbms_sql.open_cursor;
   begin
       dbms_sql.parse(  c_curosor, 'select * from '|| p_name||' where 1 = 2', dbms_sql.native );
       dbms_sql.describe_columns( c       => c_curosor,
                                  col_cnt => v_Cnt,
                                  desc_t  => v_table_description );

       for i in 1 .. v_Cnt
       loop

           pipe row ( v_table_description(i).col_name );

        end loop;
       dbms_sql.close_cursor(c_curosor);
   exception
       when others then dbms_sql.close_cursor( c_curosor );
           raise;
   end ;
/
select * from table(list_of_column('table_name'))
/
select * from table(list_of_column('view_name'))
/
select * from table(list_of_column('synonym'))
/

在 Oracle 中获取 SYNONYM 中的特定列名称

Get Specific Column Names in SYNONYM in Oracle

sql

oracle

synonym