Pg-promise : 交易问题

Pg-promise : transaction issue

我对 pg-promise 与生成器的交易感到奇怪。
这就是我想要的:

  1. 获取或注册用户 (getOrRegisterUser)
  2. 做批处理(4 个插入生成器)
  3. 最后,使用 getOrRegisterCurrentParkingIfProvided generator
  4. 的结果进行最后一次插入(generator registerCall)

这是我的代码:

db.tx(function (t) {
            return t.task.call(params, getOrRegisterUser).then(function (user) {
                params.masterId = user.id; // NOTICE : MY USER ID DATABASE
                return t.batch([
                    t.task.call(params, registerNewPhones),
                    t.task.call(params, registerNewPlate),
                    t.task.call(params, registerNewSubscriptions),
                    t.task.call(params, getOrRegisterCurrentParkingIfProvided)
                ]).then(function (result) {
                    params.ParkingId = (result[3] !== undefined) ? result[3].id : null;
                    return t.task.call(params, registerCall);
                })
            });
}).then(function () {
    // job done
    resolve();
}).catch(function (err) {
    console.log(err);
    reject(err);
});

我在第二个生成器 (registerNewPhones) 收到此错误消息:

severity: 'ERREUR',
code: '23503',
detail: 'La clé (customer)=(3) n\'est pas présente dans la table « users ».',

有什么办法可以解决吗?我试过这样的交易:https://github.com/vitaly-t/pg-promise#nested-transactions or https://github.com/vitaly-t/pg-promise#synchronous-transactions 但在某些未知情况下我仍然在某处出错。

谢谢

PS:我知道这些生成器的实现是无罪的,所以...

编辑:如果你真的想看代码

let squel = require('squel');
// squel with PostgresSQL syntax
let squelPostgres = squel.useFlavour('postgres');

注册新手机:

// Register all new phones numbers for user
function * registerNewPhones(t) {

    let params = t.ctx.context;

    let findPhonesForUserQuery = squelPostgres
        .select()
        .from("HELPDESK.phones")
        .field("number")
        .where("customer = ?", params.masterId)
        .toString();

    let registerPhoneForUser = squelPostgres
        .insert()
        .into("HELPDESK.phones")
        .set("customer", params.masterId);

    // find the already known phone number(s) for this user
    return t.any(findPhonesForUserQuery).then(function (result) {

        // data
        let phones = (params.hasOwnProperty("phones") ? params.phones : []);

        let alreadyRegisteredPhones = result.map(function (element) {
            return element.number;
        });

        // filter data

        let phonesToRegister = phones.filter(function (aPhoneNumber) {
            return alreadyRegisteredPhones.indexOf(aPhoneNumber) == -1;
        });

        // create queries
        let queries = phonesToRegister.map(function (phone) {
            return db.none(
                registerPhoneForUser
                    .clone()
                    .set("number", phone)
                    .toString()
            );
        });
        return t.batch(queries);
    });

}

和生成器 getOrRegisterUser:

function * getOrRegisterUser(t) {

    let params = t.ctx.context;

    // QUERIES:
    let findUserQuery = squelPostgres
        .select()
        .from("HELPDESK.users")
        .field("id")
        .where("registered_id = ?", params.userId)
        .toString();

    let insertUserQuery = squelPostgres
        .insert()
        .into("HELPDESK.users")
        .setFields({
            name: params.userName,
            registered_id: params.userId,
            typeOfAccount: 'BASIC',
            email: params.email
        })
        .returning('id')
        .toString();

    let user = yield t.oneOrNone(findUserQuery);
    return yield user || t.one(insertUserQuery);
}

问题出在 ES6-Generator 函数中 registerNewPhones:

return t.any(findPhonesForUserQuery)...

它不是 yield 承诺结果,这是 ES6 生成器函数所必需的。

即它必须是:

return yield t.any(findPhonesForUserQuery)...