如何通过在 PySide 中按下按钮来更改标签

Question

不知道哪里出了问题。只需要将标签文本从 'Default label' 更改为 'New label 01'。来自 PySide.QtGui 导入 *

class myWidget(QWidget):
    def __init__(self):
        super(myWidget, self).__init__()
        layout = QVBoxLayout(self)

        label1 = QLabel('Default label')
        layout.addWidget(label1)

        button = QPushButton('Change')
        layout.addWidget(button)
        button.clicked.connect(self.newlabel)


    def newlabel(self):
        print 'ACTION1'
        self.label1.setText('New label 01')
        print 'ACTION2'

app = QApplication([])
window = myWidget()
window.show()
app.exec_()

这是我在 pycharm

运行之后得到的

C:\Python27\python.exe D:/OneDrive/Projects/Personal/Tutorials/Python/CGScripting/PySide/simpleWidget.py
ACTION1
Traceback (most recent call last):
  File "D:/OneDrive/Projects/Personal/Tutorials/Python/CGScripting/PySide/simpleWidget.py", line 32, in newlabel
    self.label1.setText('New label 01')
AttributeError: 'myWidget' object has no attribute 'label1'

Process finished with exit code 0

Answer 1

您必须通过在 __init__ 方法中添加 self 来使 label1 成为您的 myWidget 实例的属性：

    self.label1 = QLabel('Default label')
    layout.addWidget(self.label1)

如何通过在 PySide 中按下按钮来更改标签

How to change label by pushing a button in PySide

python

pyqt

pyside

python-2.7

qlabel