Compile Error: linker command failed with exit code 1

Question

我是 C++ 的新手，正在尝试编写一个简单的程序。

但是我得到这个错误：

    Undefined symbols for architecture x86_64:
  "_main", referenced from:
     implicit entry/start for main executable
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)
[Finished in 0.4s with exit code 1]

来自这段代码：

#include <iostream>
using namespace std;

// Lets add some global variables
int FirstNumber = 0;
int SecondNumber = 0;
int MultiNum = 0;

void MultiNumbers ()
{
    cout << "Enter the first number: ";
    cin >> FirstNumber;

    cout << "Enter the second number: ";
    cin >> SecondNumber;

    // Multiply two numbers...
    MultiNum = FirstNumber * SecondNumber;

    // Display result
    cout << "Displaying result from MultiNumbers(): ";
    cout << FirstNumber << " x " << SecondNumber;
    cout << " = " << MultiNum << endl;
}
int Main ()
{
    cout << "This program will help you to multiply two numbers" << endl;

    // Now call the function that does all the work
    MultiNumbers();

    cout << "Displaying from main(): ";

    // This line will not compile and work because of the global variables
    cout << FirstNumber << " x " << SecondNumber;
    cout << " = " << MultiNum << endl;

    return 0;
}

我已经尝试在 sublime 上检查我的编译器，在终端中使用 g++ -o test test.cpp

进行编译

但似乎无济于事。

我的理解是，我在上面定义了 MultiNumbers() 然后我在 Main() 中调用它...但我似乎错过了什么...

建议？

Answer 1

C++ 区分大小写。这个：

int Main ()

应该是

int main ()

Compile Error: linker command failed with exit code 1

Compile Error: linker command failed with exit code 1

c++

compiler-errors