如何使用正则表达式替换 PHP 中的重复标点符号？

Question

比方说，我有这个

Hello ??? WHERE ARE YOU!!!! Comon ?!?!?!
desired outout
Hello ? WHERE ARE YOU!!!! Comon ?!

我怎样才能做到这一点？我试过 preg_replace_callback 但没有成功。我用了 as an starting point but it works on complete sentence, I need it to work on word by word + I need to remove duplicate computations only (patterns)? Live Code

Answer 1

将\?+替换为?，将!+替换为!，将(\?!)+替换为?!，依此类推。

function dedup_punctuation($str) {
  $targets      = array('/\?+/', '/!+/', '/(\?!)+/');
  $replacements = array('?'    , '!'   , '?!'      );
  return preg_replace($targets, $replacements, $str);
}

Answer 2

使用以下代码：

$str = "Hello ??? WHERE ARE YOU!!!! Comon ?!?!?! ...";

$replacement = [
    '?',
    '?!',
    '.',
];

foreach( $replacement as $key => $value ){
    $pattern[$key] = sprintf("/(\%s)+/", $value);
}

echo $outout = preg_replace($pattern, $replacement, $str);

将任何标点符号插入替换数组以删除重复的标点符号。

如何使用正则表达式替换 PHP 中的重复标点符号？

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