从公式调用图像
Call Image From Formula
如果语句公式无法根据相邻单元格中的特定文本调用特定图像。
这个有效:
`=if(istext(A2), image("https://img.labnol.org/di/high-quality- photo.jpg",2),"")`
这不起作用,但这是需要的:
`=IF(istext(A2="Van", image("https://img.labnol.org/di/high-quality-photo.jpg",2),IF(A2="Bike", image("https://isome other image from the library",2),""))`
将istext(A2="Van"
更改为=if(find("Van",A3)>0, image("https://img.labnol.org/di/high-quality-photo.jpg",2),"")
如果语句公式无法根据相邻单元格中的特定文本调用特定图像。
这个有效:
`=if(istext(A2), image("https://img.labnol.org/di/high-quality- photo.jpg",2),"")`
这不起作用,但这是需要的:
`=IF(istext(A2="Van", image("https://img.labnol.org/di/high-quality-photo.jpg",2),IF(A2="Bike", image("https://isome other image from the library",2),""))`
将istext(A2="Van"
更改为=if(find("Van",A3)>0, image("https://img.labnol.org/di/high-quality-photo.jpg",2),"")