C# - 当 webRequest 发送 XML 时,将 Base64 安全作为 Gif?
C# - Safe a Base64 as Gif, when the webRequest sends XML?
我发送了一个 WebRequest,并在我的内容中得到了一个带有 XML 代码的字符串作为响应。
WebRequest request = WebRequest.Create("...");
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
Stream dataStream = response.GetResponseStream();
StreamReader reader = new StreamReader(dataStream);
string responseFromServer = reader.ReadToEnd();
byte[] bytes = Convert.FromBase64String(responseFromServer);
Image image;
using (MemoryStream ms = new MemoryStream(bytes))
{
image = Image.FromStream(ms);
}
image.Save("File", System.Drawing.Imaging.ImageFormat.Gif);
问题是 "Convert.FromBase64String(responseFromServer)" 无法转换为 base 64,因为响应是:
"<string xmlns="*LINK*"> 'content' </string>"
我可以删除这些标签或复制内容吗?
希望您能解决我的问题:)感谢您的帮助,抱歉英语不好 x)
您可以使用 XmlDocument..
WebRequest request = WebRequest.Create("...");
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
Stream dataStream = response.GetResponseStream();
StreamReader reader = new StreamReader(dataStream);
XmlDocument doc = new XmlDocument();
doc.Load(reader);
byte[] bytes = Convert.FromBase64String(doc.GetElementsByTagName("string")[0].InnerText);
System.Drawing.Image image;
using (MemoryStream ms = new MemoryStream(bytes))
{
image = System.Drawing.Image.FromStream(ms);
}
为此我建议使用 XmlReader
。
WebRequest request = WebRequest.Create("...");
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
Stream dataStream = response.GetResponseStream();
//StreamReader reader = new StreamReader(dataStream);
//string responseFromServer = reader.ReadToEnd();
//byte[] bytes = Convert.FromBase64String(responseFromServer);
using (var reader = XmlReader.Create(dataStream))
{
reader.Read();
reader.Read();
string base64 = reader.Value;
byte[] bytes = Convert.FromBase64String(base64);
Image image;
using (MemoryStream ms = new MemoryStream(bytes))
{
image = Image.FromStream(ms);
image.Save("File", System.Drawing.Imaging.ImageFormat.Gif);
}
}
有一种方法可以直接从元素值中的 Base64 进行转换,但是您需要知道或多或少需要阅读整个流才能做到这一点的事情(您可以查看编辑历史记录看看我如何解决这个问题 ;)。
我发送了一个 WebRequest,并在我的内容中得到了一个带有 XML 代码的字符串作为响应。
WebRequest request = WebRequest.Create("...");
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
Stream dataStream = response.GetResponseStream();
StreamReader reader = new StreamReader(dataStream);
string responseFromServer = reader.ReadToEnd();
byte[] bytes = Convert.FromBase64String(responseFromServer);
Image image;
using (MemoryStream ms = new MemoryStream(bytes))
{
image = Image.FromStream(ms);
}
image.Save("File", System.Drawing.Imaging.ImageFormat.Gif);
问题是 "Convert.FromBase64String(responseFromServer)" 无法转换为 base 64,因为响应是:
"<string xmlns="*LINK*"> 'content' </string>"
我可以删除这些标签或复制内容吗?
希望您能解决我的问题:)感谢您的帮助,抱歉英语不好 x)
您可以使用 XmlDocument..
WebRequest request = WebRequest.Create("...");
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
Stream dataStream = response.GetResponseStream();
StreamReader reader = new StreamReader(dataStream);
XmlDocument doc = new XmlDocument();
doc.Load(reader);
byte[] bytes = Convert.FromBase64String(doc.GetElementsByTagName("string")[0].InnerText);
System.Drawing.Image image;
using (MemoryStream ms = new MemoryStream(bytes))
{
image = System.Drawing.Image.FromStream(ms);
}
为此我建议使用 XmlReader
。
WebRequest request = WebRequest.Create("...");
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
Stream dataStream = response.GetResponseStream();
//StreamReader reader = new StreamReader(dataStream);
//string responseFromServer = reader.ReadToEnd();
//byte[] bytes = Convert.FromBase64String(responseFromServer);
using (var reader = XmlReader.Create(dataStream))
{
reader.Read();
reader.Read();
string base64 = reader.Value;
byte[] bytes = Convert.FromBase64String(base64);
Image image;
using (MemoryStream ms = new MemoryStream(bytes))
{
image = Image.FromStream(ms);
image.Save("File", System.Drawing.Imaging.ImageFormat.Gif);
}
}
有一种方法可以直接从元素值中的 Base64 进行转换,但是您需要知道或多或少需要阅读整个流才能做到这一点的事情(您可以查看编辑历史记录看看我如何解决这个问题 ;)。