PHP 如何从检查数组中多个日期范围的函数中获取值

Question

我有一个函数可以检查今天的日期是否落在数组中的多个日期间隔之间。我唯一需要的是这个函数 return checkRange 函数中的 $location 值。

function promoDates(){
    $current = strtotime("now");

    // Array gives a place, start date, and end date
    $intervals = array(
        //The $current start time falls between the dates in washington array
        array('washington', strtotime("2015-01-08 00:00"), strtotime("2015-01-30 00:00")),
        array('california', strtotime("2015-06-02 00:00"), strtotime("2015-06-17 00:00")),
        array('texas', strtotime("2015-02-12 00:00"), strtotime("2015-02-27 00:00")),
        array('ney-york', strtotime("2015-05-12 00:00"), strtotime("2015-05-26 00:00")),
        array('tennessee', strtotime("2015-10-29 00:00"), strtotime("2015-11-12 00:00")),
        array('utah', strtotime("2015-09-15 00:00"), strtotime("2015-09-30 00:00")),
        array('florida', strtotime("2015-11-12 00:01"), strtotime("2015-11-27 00:00"))
    );

    function checkRange($location, $startDate, $endDate, $currentDate){
        if ($currentDate >= $startDate && $currentDate <= $endDate){
            // Successfully echos 'washington' to page
            echo $location."<br>";
            return $location;
        }
    }

    for ($i = 0; $i <= 6; $i++){
        checkRange($intervals[$i][0], $intervals[$i][1], $intervals[$i][2], $current);
    }
    //This does not echo the location from the checkRange function
    echo checkRange();
}

我只需要帮助将 promoDates 函数设置为 return checkRange 函数所回应的内容。有没有一种方法可以在 checkRange 函数中设置一个变量并 return 在 promoDates 函数中设置它？

Answer 1

好吧，您没有将任何参数传递给 checkRange() 函数...我还将更改 checkRange 函数的签名以获取间隔数组：

function promoDates() {

    $current = strtotime("now");

    // Array gives a place, start date, and end date
    $intervals = array(
        //The $current start time falls between the dates in washington array
        array('washington', strtotime("2015-01-08 00:00"), strtotime("2015-01-30 00:00")),
        array('california', strtotime("2015-06-02 00:00"), strtotime("2015-06-17 00:00")),
        array('texas', strtotime("2015-02-12 00:00"), strtotime("2015-02-27 00:00")),
        array('ney-york', strtotime("2015-05-12 00:00"), strtotime("2015-05-26 00:00")),
        array('tennessee', strtotime("2015-10-29 00:00"), strtotime("2015-11-12 00:00")),
        array('utah', strtotime("2015-09-15 00:00"), strtotime("2015-09-30 00:00")),
        array('florida', strtotime("2015-11-12 00:01"), strtotime("2015-11-27 00:00"))
    );

    // we will use this like a filter
    function checkRange($currentDate, $promo) {
        list($location, $startDate, $endDate) = $promo;
       // return true or false
      return (($currentDate >= $startDate) && ($currentDate <= $endDate));
    }

    // loop over the intervals until we find a match then return it:
    foreach($intervals as $promoData) {
       if (checkRange($current, $promoData) === true) {
          return $promoData[0];
       }
    }

    // return null if we do not find any
    return null;     
}

用法如下：

echo promoDates();

Answer 2

编辑：我实际上只是按照@prodigitalson 的建议修复了它，并检查每个循环迭代是真还是假，然后在为真时返回值。

function checkRange($startDate, $endDate, $currentDate, $loc){
    if ($currentDate >= $startDate && $currentDate <= $endDate){
        return true;
    } else{
        return null;
    }
}

for ($i = 0; $i <= 6; $i++){
    if(checkRange($intervals[$i][1], $intervals[$i][2], $current, $intervals[$i][0]) == true){
        return $intervals[$i][0];
    }
}

并删除 echo checkRange()；在底部。

PHP 如何从检查数组中多个日期范围的函数中获取值

PHP How to get value from function that checks between multiple date ranges in array

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