如何在打字稿中将数组声明为 public?
How do i declare an array as public in typescript?
我有一个函数涉及声明和填充名为 ArrayRoute 的数组。稍后我需要在 for 循环中引用这个数组。如何将此数组设置为全局数组以便我可以在函数外部访问它?
谢谢
function route(permutation, origins) {
var myroute = origins[0];
var ArrayRoute = [];
ArrayRoute.push(origins[0]);
console.log('ArrayRoute= ' + ArrayRoute);
for (var i = 0; i < permutation.length; i++){
myr += '\n' + myd[permutation[i] - 1];
ArrayRoute.push(myd[permutation[i] - 1]);
}
return myroute;
}
for (i = 0; i < ArrayRoute.length - 1; i++) {
console.log(ArrayRoute[i] + '->' + ArrayRoute[i + 1]);
}
console.log('ArrayRouteeee= ' + ArrayRoute);
你不能。
如果您在函数内部创建数组,则只能从函数体内访问它。
你可以在函数外声明它:
let ArrayRoute = [];
function route(permutation, origins) {
var myroute = origins[0];
ArrayRoute.push(origins[0]);
console.log('ArrayRoute= ' + ArrayRoute);
for (var i = 0; i < permutation.length; i++){
myr += '\n' + myd[permutation[i] - 1];
ArrayRoute.push(myd[permutation[i] - 1]);
}
return myroute;
}
for (i = 0; i < ArrayRoute.length - 1; i++) {
console.log(ArrayRoute[i] + '->' + ArrayRoute[i + 1]);
}
console.log('ArrayRouteeee= ' + ArrayRoute);
您可以将其作为参数传递给函数:
function route(permutation, origins, ArrayRoute) {
...
}
或者您可以 return 数组作为函数的结果:
function route(permutation, origins) {
var myroute = origins[0];
var ArrayRoute = [];
ArrayRoute.push(origins[0]);
console.log('ArrayRoute= ' + ArrayRoute);
for (var i = 0; i < permutation.length; i++){
myr += '\n' + myd[permutation[i] - 1];
ArrayRoute.push(myd[permutation[i] - 1]);
}
return { myroute, ArrayRoute };
}
let { myroute, ArrayRoute } = route(...);
我有一个函数涉及声明和填充名为 ArrayRoute 的数组。稍后我需要在 for 循环中引用这个数组。如何将此数组设置为全局数组以便我可以在函数外部访问它?
谢谢
function route(permutation, origins) {
var myroute = origins[0];
var ArrayRoute = [];
ArrayRoute.push(origins[0]);
console.log('ArrayRoute= ' + ArrayRoute);
for (var i = 0; i < permutation.length; i++){
myr += '\n' + myd[permutation[i] - 1];
ArrayRoute.push(myd[permutation[i] - 1]);
}
return myroute;
}
for (i = 0; i < ArrayRoute.length - 1; i++) {
console.log(ArrayRoute[i] + '->' + ArrayRoute[i + 1]);
}
console.log('ArrayRouteeee= ' + ArrayRoute);
你不能。
如果您在函数内部创建数组,则只能从函数体内访问它。
你可以在函数外声明它:
let ArrayRoute = [];
function route(permutation, origins) {
var myroute = origins[0];
ArrayRoute.push(origins[0]);
console.log('ArrayRoute= ' + ArrayRoute);
for (var i = 0; i < permutation.length; i++){
myr += '\n' + myd[permutation[i] - 1];
ArrayRoute.push(myd[permutation[i] - 1]);
}
return myroute;
}
for (i = 0; i < ArrayRoute.length - 1; i++) {
console.log(ArrayRoute[i] + '->' + ArrayRoute[i + 1]);
}
console.log('ArrayRouteeee= ' + ArrayRoute);
您可以将其作为参数传递给函数:
function route(permutation, origins, ArrayRoute) {
...
}
或者您可以 return 数组作为函数的结果:
function route(permutation, origins) {
var myroute = origins[0];
var ArrayRoute = [];
ArrayRoute.push(origins[0]);
console.log('ArrayRoute= ' + ArrayRoute);
for (var i = 0; i < permutation.length; i++){
myr += '\n' + myd[permutation[i] - 1];
ArrayRoute.push(myd[permutation[i] - 1]);
}
return { myroute, ArrayRoute };
}
let { myroute, ArrayRoute } = route(...);