从 DateTime c# 中删除秒数

Question

我有一段代码将 unix 时间戳值转换为标准时间，但它是 returning 小时、分钟和秒。我希望它只有 return 小时和分钟。

convertSunriseTime = UnixTimeStampToDateTime(currentSunriseTime).ToString();
convertSunsetTime = UnixTimeStampToDateTime(currentSunsetTime).ToString();

private static TimeSpan UnixTimeStampToDateTime(long unixTimeStamp)
{
    DateTime dtDateTime = new DateTime(1970, 1, 1, 0, 0, 0, 0, DateTimeKind.Utc);
    dtDateTime = dtDateTime.AddSeconds(unixTimeStamp);
    return dtDateTime.TimeOfDay;
}

然后变量 convertSunriseTime 和 convertSunsetTime 以秒返回。

Answer 1

这可以完成工作：

private static TimeSpan UnixTimeStampToDateTime(long unixTimeStamp)
{
    DateTime dtDateTime = new DateTime(1970, 1, 1, 0, 0, 0, 0, DateTimeKind.Utc);
    dtDateTime = dtDateTime.AddSeconds(unixTimeStamp);
    dtDateTime = DateTime.FromMinutes((int)dtdateTime.TotalMinutes);
    return dtDateTime.TimeOfDay;
}

Answer 2

所以你想格式化你的值以显示小时和分钟。你可以这样做：

convertSunriseTime = UnixTimeStampToDateTime(currentSunriseTime).ToString("hh\:mm");

这里，ToString() 方法的参数指定您只对将小时和分钟部分放入结果 string 感兴趣。这叫做 custom TimeSpan format string. There is also a set of standard ones: Standard TimeSpan format strings

Answer 3

Can you try this way

convertSunriseTime = UnixTimeStampToDateTime(currentSunriseTime).ToString();

convertSunsetTime = UnixTimeStampToDateTime(currentSunsetTime).ToString();

<pre>private static TimeSpan UnixTimeStampToDateTime(long unixTimeStamp) </pre>
<pre>{</pre>
        <pre>DateTime dtDateTime = new DateTime(1970, 1, 1, 0, 0, 0, 0, DateTimeKind.Utc);</pre>
    <pre>dtDateTime = dtDateTime.AddSeconds(unixTimeStamp);</pre>
        <pre>return dtDateTime.TimeOfDay;</pre>
<pre>}</pre>

从 DateTime c# 中删除秒数

Remove Seconds from DateTime c#

c#

datetime

unix-timestamp